/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Determine the maximum theoretica... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the maximum theoretical thermal efficiency for any power cycle operating between hot and cold reservoirs at \(800^{\circ} \mathrm{C}\) and \(120^{\circ} \mathrm{C}\), respectively.

Short Answer

Expert verified
The theoretical maximum thermal efficiency is approximately 63.37%.

Step by step solution

01

- Understand The Temperature Conversion

Convert the given temperatures from Celsius to Kelvin. The formula for conversion is: \( T(K) = T(^{\circ}C) + 273.15 \)So, \( T_{hot} = 800 + 273.15 = 1073.15 \text{K} \)\( T_{cold} = 120 + 273.15 = 393.15 \text{K} \)
02

- Identify the Carnot Efficiency Formula

The maximum theoretical efficiency for a heat engine operating between two reservoirs is given by the Carnot efficiency formula: \( \text{Efficiency} = 1 - \frac{T_{cold}}{T_{hot}} \)
03

- Substitute The Values

Substitute the Kelvin temperatures into the Carnot efficiency formula:\( \text{Efficiency} = 1 - \frac{393.15}{1073.15} \)
04

- Calculate The Efficiency

Perform the division and subtraction calculations to find the efficiency:\( \text{Efficiency} = 1 - 0.3663 \approx 0.6337 \)Therefore, the theoretical maximum thermal efficiency is approximately 63.37%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carnot efficiency
The Carnot efficiency represents the maximum theoretical thermal efficiency that a heat engine can achieve operating between two thermal reservoirs. Named after Sadi Carnot, this concept is fundamental in thermodynamics.

The formula for Carnot efficiency is: \[ \text{Efficiency} = 1 - \frac{T_{cold}}{T_{hot}} \]where \( T_{cold} \)and \( T_{hot} \)are the temperatures of the cold and hot reservoirs, respectively, measured in Kelvin.

Understanding Carnot efficiency helps in determining the upper limit of efficiency for real-world engines, aiding in the design of more efficient systems.
For example, in our exercise, the temperatures given were converted to Kelvin and then used in the Carnot formula to find that the maximum efficiency is approximately 63.37%.
temperature conversion
Temperature conversion is essential in thermodynamics when dealing with heat engines. Most equations, like the Carnot efficiency formula, require temperatures to be in Kelvin rather than Celsius or Fahrenheit.

To convert a temperature from Celsius to Kelvin, you use the formula:
\[ T(K) = T(°C) + 273.15 \]This step ensures our calculations are accurate and follow the standard scientific protocols.

In our exercise, we converted the given temperatures from Celsius to Kelvin: \( T_{hot} = 800 + 273.15 = 1073.15 \text{K} \)and \( T_{cold} = 120 + 273.15 = 393.15 \text{K} \).This conversion was critical to applying the Carnot efficiency formula correctly.
heat engine
A heat engine is a machine that converts thermal energy into mechanical work. It operates by exploiting the temperature difference between a hot and a cold reservoir. The efficiency of a heat engine is a measure of how well it converts the input heat (from the hot reservoir) into useful work, with the rest of the heat being expelled to the cold reservoir.

Real-world engines strive to approach the Carnot efficiency but are always less efficient due to irreversibilities and practical limitations. Understanding the theoretical limit helps engineers improve the design and performance of these engines.
The exercise example showed how a heat engine operating between 1073.15 K (hot reservoir) and 393.15 K (cold reservoir) could maximally achieve a thermal efficiency of about 63.37%. This knowledge is crucial for applications ranging from power plants to vehicle engines, aiming for optimized performance.

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Most popular questions from this chapter

A carnot engine absorbs \(250 \mathrm{~J}\) of heat from reservoir at \(100^{\circ} \mathrm{C}\) and rejects heat to a reservoir at \(20^{\circ} \mathrm{C}\). Find (a) the heat rejected, (b) work done by the engine, and (c) thermal efficiency.

Two reversible power cycles are arranged in series. The first cycle receives energy by heat transfer from a hot reservoir at temperature \(T_{\mathrm{H}}\) and rejects energy by heat transfer to a reservoir at an intermediate temperature \(T

An inventor claims to have developed a power cycle operating between hot and cold reservoirs at \(2000 \mathrm{~K}\) and \(500 \mathrm{~K}\), respectively, that develops net work equal to a multiple of the amount of energy, \(Q_{C}\) rejected to the cold reservoir \(-\) that is \(W_{\text {cycle }}=N Q_{c}\), where all quantities are positive. What is the maximum theoretical value of the number \(\mathrm{N}\) for any such cycle?

For each \(\mathrm{kW}\) of power input to an ice maker at steady state, determine the maximum rate that ice can be produced, in \(\mathrm{kg} / \mathrm{h}\), from liquid water at \(0^{\circ} \mathrm{C}\) Assume that \(333 \mathrm{~kJ} / \mathrm{kg}\) of energy must be removed by heat transfer to freeze water at \(0^{\circ} \mathrm{C}\), and that the surroundings are at \(20^{\circ} \mathrm{C}\).

A reversible power cycle receives energy \(Q_{\mathrm{H}}\) from a reservoir at temperature \(T_{\mathrm{H}}\) and rejects \(Q_{\mathrm{C}}\) to a reservoir at temperature \(T_{\mathrm{C}}\). The work developed by the power cycle is used to drive a reversible heat pump that removes energy \(Q_{\mathrm{C}}^{\prime}\) from a reservoir at temperature \(T_{\mathrm{C}}^{\top}\) and rejects energy \(Q_{\mathrm{H}}^{\prime}\) to a reservoir at temperature \(T_{\mathrm{H}}^{\prime}\) (a) Develop an expression for the ratio \(Q_{\mathrm{H}}^{\prime} / Q_{\mathrm{H}}\) in terms of the temperatures of the four reservoirs. (b) What must be the relationship of the temperatures \(T_{\mathrm{H}}, T_{\mathrm{C}}, T_{\mathrm{C}}^{\prime}\), and \(T^{\prime}{ }_{\mathrm{H}}\) for \(Q_{\mathrm{H}}^{\prime} / Q_{\mathrm{H}}\) to exceed a value of unity?

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