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Experimental molecular motors are reported to exhibit movement upon the absorption of light, thereby achieving a conversion of electromagnetic radiation into motion. Should the incident light be considered work or heat transfer?

Short Answer

Expert verified
The incident light should be considered work.

Step by step solution

01

Understand the Concepts of Work and Heat

Work is the energy transfer that occurs when a force is applied over a distance, resulting in motion. Heat, on the other hand, is the energy transfer due to a temperature difference, resulting in changes in the internal energy of the system.
02

Identify the Nature of Light

The incident light in this context is electromagnetic radiation, which is capable of transferring energy without involving any temperature difference.
03

Analyze the Effect of Light on the Molecular Motor

The light causes the molecular motor to move. This means that the energy from the light is being converted into mechanical motion, which involves applying a force over a distance.
04

Conclude Based on Definitions

Since the energy from the light is used by the molecular motor to create motion (work) rather than changing the internal energy through temperature difference (heat), the incident light should be considered as work.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Transfer
Energy transfer is a fundamental concept in physics. It refers to the movement of energy from one place or object to another. There are several ways energy can be transferred, including through mechanical work, heat, and electromagnetic radiation.

When discussing mechanical work, the energy transfer occurs when a force is applied over a distance. For example, pushing a box across the floor involves transferring energy from your muscles to the box.

Heat transfer, on the other hand, happens due to a temperature difference between two objects. Energy moves from the warmer object to the cooler one until they reach thermal equilibrium. There are three main methods of heat transfer: conduction, convection, and radiation.

Finally, electromagnetic radiation, such as light, is another form of energy transfer. This occurs when energy is transferred through electromagnetic waves, which can travel through a vacuum. In the context of molecular motors, understanding how these forms of energy transfer work is crucial for grasping their operation.
Electromagnetic Radiation
Electromagnetic radiation is a type of energy that is propagated through space in the form of electromagnetic waves. These waves can have different wavelengths and frequencies, such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

The energy carried by electromagnetic waves can be absorbed by matter, causing various effects. For molecular motors, the absorption of light (a form of electromagnetic radiation) results in energy being transferred to the motor. This absorbed energy then causes the molecular motor to move or change shape.

The light used in this context does not involve a temperature difference—it transfers energy directly to the molecular motor, enabling it to perform work. This distinction is vital because it clarifies why light in this case is considered work rather than heat. Understanding the nature of electromagnetic radiation helps in comprehending how these experimental molecular motors function and leverage the energy they absorb.
Work vs Heat
In thermodynamics, work and heat are two primary ways energy can be transferred into or out of a system.

**Work** involves transferring energy through a force acting over a distance. When we push an object and it moves, we're doing work on that object. Classic examples of work include moving parts of machinery, lifting objects, or, as discussed, the movement of molecular motors under the influence of light.

**Heat** transfer is the energy transferred due to temperature differences between systems. When you touch a hot stove, heat flows from the stove to your hand. Heat can change the internal energy of a system without any movement of its parts.

In the scenario of molecular motors absorbing light, the key distinction lies in the type of energy transfer. Since the light causes motion by transferring its energy directly to the motor (via electromagnetic radiation), it fits the definition of doing work. Conversely, if that light simply caused the motor to heat up without causing movement, it would be a heat transfer.

This distinction helps clarify many processes in physics and engineering by defining the roles of energy transfer in different contexts. Keeping these definitions in mind allows for a better understanding of how various systems utilize incoming energy.

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Most popular questions from this chapter

Why are the symbols \(\Delta U, \Delta \mathrm{KE}\), and \(\Delta \mathrm{PE}\) used to denote the energy change during a process, but the work and heat transfer for the process are represented, respectively, simply as \(W\) and \(Q\) ?

An air-conditioning unit with a coefficient of performance of \(2.93\) provides \(5,275 \mathrm{~kJ} / \mathrm{h}\) of cooling while operating during the cooling season 8 hours per day for 125 days. If you pay 10 cents per \(\mathrm{kW} \cdot \mathrm{h}\) for electricity, determine the cost, in, dollars, for the cooling season.

A vertical cylindrical mass of \(5 \mathrm{~kg}\) undergoes a process during which the velocity decreases from \(30 \mathrm{~m} / \mathrm{s}\) to \(15 \mathrm{~m} / \mathrm{s}\), while the elevation remains unchanged. The initial specific internal energy of the mass is \(1.2 \mathrm{~kJ} / \mathrm{kg}\) and the final specific internal energy is \(1.9 \mathrm{~kJ} / \mathrm{kg}\). During the process, the mass receives \(2 \mathrm{~kJ}\) of energy by heat transfer through its bottom surface and loses \(1 \mathrm{~kJ}\) of energy by heat transfer through its top surface. The lateral surface experiences no heat transfer. For this process, evaluate (a) the change in kinetic energy of the mass in \(\mathrm{kJ}\), and (b) the work in \(\mathrm{kJ}\).

The two major forces opposing the motion of a vehicle moving on a level road are the rolling resistance of the tires, \(F_{t}\), and the aerodynamic drag force of the air flowing around the vehicle, \(F_{\mathrm{d}}\), given respectively by $$ F_{r}=f m g, \quad F_{d}=C_{d} \mathrm{~A}_{2} \rho \mathrm{V}^{2} $$ where \(f\) and \(C_{\mathrm{d}}\) are constants known as the rolling resistance coefficient and drag coefficient, respectively, \(\mathrm{m}\) and \(\mathrm{A}\) are the vehicle mass and projected frontal area, respectively, \(\mathrm{V}\) is the vehicle velocity, and \(\rho\) is the air density. For a passenger car with \(\mathrm{m}=1,610 \mathrm{~kg}, \mathrm{~A}=2.2 \mathrm{~m}^{2}\), and \(C_{\mathrm{d}}=0.34\), and when \(f=0.02\) and \(\rho=1.28 \mathrm{~kg} / \mathrm{m}^{3}\) (a) determine the power required, in \(\mathrm{kW}\), to overcome rolling resistance and aerodynamic drag when \(\mathrm{V}\) is \(88.5\) \(\mathrm{km} / \mathrm{hr}\)\ (b) plot versus vehicle velocity ranging from 0 to \(120.7 \mathrm{~km} / \mathrm{hr}\) (i) the power to overcome rolling resistance, (ii) the power to overcome aerodynamic drag, and (iii) the total power, all in \(\mathrm{kW}\). What implication for vehicle fuel economy can be deduced from the results of part (b)?

.A composite plane wall consists of a \(23 \mathrm{~cm}\)-thick layer of brick \(\left(\kappa_{b}=2.4 \times 10^{-3} \mathrm{~kW} / \mathrm{m} \cdot \mathrm{K}\right)\) and a \(10 \mathrm{~cm}\)-thick layer of insulation \(\left(\kappa_{\mathrm{i}}=0.09 \times 10^{-3} \mathrm{~kW} / \mathrm{m} \cdot \mathrm{K}\right)\). The outer surface temperatures of the brick and insulation are \(700 \mathrm{~K}\) and \(310 \mathrm{~K}\), respectively, and there is perfect contact at the interface between the two layers. Determine at steady state the instantaneous rate of heat transfer, in \(\mathrm{kW} / \mathrm{m}^{2}\) of surface area, and the temperature, in \(\mathrm{K}\), at the interface between the brick and the insulation.

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