/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 \(.\) In a rigid insulated conta... [FREE SOLUTION] | 91Ó°ÊÓ

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\(.\) In a rigid insulated container of volume \(0.8 \mathrm{~m}^{3}, 2.5 \mathrm{~kg}\) of air is filled. A paddle wheel is fitted in the container and it transfers energy to the contained air at a constant rate of \(12 \mathrm{~W}\) for a period of \(1 \mathrm{~h}\). There is no change in the potential or kinetic energy of the system. Determine the energy transfer by the wheel to the air per \(\mathrm{kg}\) of air.

Short Answer

Expert verified
17280 \mathrm{J/kg}

Step by step solution

01

- Identify given information

First, extract and list the given data from the problem:1. Volume of container, \( V = 0.8 \mathrm{~m}^{3} \)2. Mass of air, \( m = 2.5 \mathrm{~kg} \)3. Energy transfer rate by paddle wheel, \( P = 12 \mathrm{~W} \)4. Duration of energy transfer, \( t = 1 \mathrm{~h} \) (convert to seconds by multiplying with 3600, thus, \( t = 3600 \mathrm{~s} \))
02

- Calculate total energy transferred

The energy transferred to the air by the paddle wheel can be determined by multiplying the power by the time:\( E_{total} = P \times t \)Substitute the values:\( E_{total} = 12 \mathrm{~W} \times 3600 \mathrm{~s} \)\( E_{total} = 43200 \mathrm{~J} \)
03

- Determine energy transfer per kg of air

To find the energy transfer per kilogram of air, divide the total energy transferred by the mass of the air:\( E_{per \, kg} = \frac{E_{total}}{m} \)Substitute the values:\( E_{per \, kg} = \frac{43200 \mathrm{~J}}{2.5 \mathrm{~kg}} \)\( E_{per \, kg} = 17280 \mathrm{~J/kg} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

energy transfer
Energy transfer refers to the process of moving energy from one place to another or transforming it from one form into another. In this particular problem, energy is transferred from a paddle wheel to the air inside a rigid insulated container. The paddle wheel does work on the air, and this work is a form of energy transfer. Given that the power (rate of energy transfer) is constant at 12 W, and it operates for 1 hour, understanding how to calculate the total energy transferred is crucial. The formula used is simple: multiply power by time. In mathematical terms: \( E_{total} = P \times t \) Here, P is the power, and t is the time. Always ensure you convert time into consistent units, such as seconds, for these calculations.
specific energy
Specific energy is the amount of energy per unit mass. It's a valuable concept in thermodynamics as it helps us understand how much energy each kilogram of a substance receives or contains. In this problem, after finding the total energy transferred to the air (43200 J), we can determine how much energy each kilogram of air receives by dividing the total energy by the mass of the air. The formula is: \( E_{per \textrm{ kg}} = \frac{E_{total}}{m} \) Here, \( E_{total} \) is the total energy, and m is the mass of the air. This gives us the specific energy of 17280 J/kg, showing the energy imparted to each kilogram of air in the container.
power and time calculation
Power is a measure of the rate at which work is done or energy is transferred. It’s measured in Watts (W), where 1 W = 1 Joule per second. In this exercise, the paddle wheel is transferring energy at a constant power of 12 W. When dealing with problems involving power and time, it’s important to ensure the units of time are appropriate. Here, time is given in hours but needs to be converted into seconds, using the conversion factor: 1 hour = 3600 seconds. The total time in seconds is critical for calculating the total energy transferred, as energy is the product of power and time.
rigid insulated container
A rigid insulated container in thermodynamics indicates that the volume of the container is constant (rigid) and that no heat enters or leaves the container (insulated). This scenario simplifies calculations because: - No energy is lost or gained through heat transfer (perfect insulation). - The changes in internal energy are purely due to the work done within the system (by the paddle wheel in this case). The rigidity and insulation assumptions help isolate the internal processes and focus solely on the energy transfer due to mechanical work.
paddle wheel energy transfer
In this problem, the paddle wheel acts as the mechanism transferring energy to the air. The wheel does mechanical work, which translates into increasing the internal energy of the air. The key points include: - The paddle wheel's energy transfer rate is given by its power (12 W). - The duration of energy transfer is one hour or 3600 seconds. By combining these, we can determine the total energy input to the air, which is essential for finding how much energy is transferred per kilogram. Paddle wheel setups are often used in thermodynamic problems to illustrate concepts of mechanical energy transfer in isolated systems.

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Most popular questions from this chapter

A chip with surface area of upper face of \(25 \mathrm{~mm}^{2}\) is exposed to a convection environment that has a temperature equal to \(25^{\circ} \mathrm{C}\). An electrical input of \(0.325 \mathrm{~W}\) is provided to the chip and under steady state heat is transferred from the upper face of the chip into the surrounding. The convective heat transfer coefficient between the chip and the surrounding is \(125 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the surface temperature of the chip.

\(.\mathrm{~A}\) gas expands in a piston-cylinder assembly from \(p_{1}=8\) bar, \(V_{1}=0.02 \mathrm{~m}^{3}\) to \(p_{2}=2\) bar in a process during which the relation between pressure and volume is \(p V^{1.2}=\) constant. The mass of the gas is \(0.25 \mathrm{~kg}\). If the specific internal energy of the gas decreases by \(55 \mathrm{~kJ} / \mathrm{kg}\) during the process, determine the heat transfer, in \(\mathrm{kJ}\). Kinetic and potential energy effects are negligible.

\(.\) A system with a mass of \(5 \mathrm{~kg}\), initially moving horizontally with a velocity of \(40 \mathrm{~m} / \mathrm{s}\), experiences a constant horizontal deceleration of \(2 \mathrm{~m} / \mathrm{s}^{2}\) due to the action of a resultant force. As a result, the system comes to rest. Determine the length of time, in s, the force is applied and the amount of energy transfer by work, in \(\mathrm{kJ}\).

The two major forces opposing the motion of a vehicle moving on a level road are the rolling resistance of the tires, \(F_{t}\), and the aerodynamic drag force of the air flowing around the vehicle, \(F_{\mathrm{d}}\), given respectively by $$ F_{r}=f m g, \quad F_{d}=C_{d} \mathrm{~A}_{2} \rho \mathrm{V}^{2} $$ where \(f\) and \(C_{\mathrm{d}}\) are constants known as the rolling resistance coefficient and drag coefficient, respectively, \(\mathrm{m}\) and \(\mathrm{A}\) are the vehicle mass and projected frontal area, respectively, \(\mathrm{V}\) is the vehicle velocity, and \(\rho\) is the air density. For a passenger car with \(\mathrm{m}=1,610 \mathrm{~kg}, \mathrm{~A}=2.2 \mathrm{~m}^{2}\), and \(C_{\mathrm{d}}=0.34\), and when \(f=0.02\) and \(\rho=1.28 \mathrm{~kg} / \mathrm{m}^{3}\) (a) determine the power required, in \(\mathrm{kW}\), to overcome rolling resistance and aerodynamic drag when \(\mathrm{V}\) is \(88.5\) \(\mathrm{km} / \mathrm{hr}\)\ (b) plot versus vehicle velocity ranging from 0 to \(120.7 \mathrm{~km} / \mathrm{hr}\) (i) the power to overcome rolling resistance, (ii) the power to overcome aerodynamic drag, and (iii) the total power, all in \(\mathrm{kW}\). What implication for vehicle fuel economy can be deduced from the results of part (b)?

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