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The molar analysis of an ideal gas mixture is \(\left\\{y_{\mathrm{CO}_{2}}=0.4\right.\), \(\left.y_{\mathrm{N}_{2}}=0.25, y_{\mathrm{O}_{2}}\right\\} .\) How many kmol of oxygen are present in \(5 \mathrm{kmol}\) of mixture?

Short Answer

Expert verified
1.75 kmol of oxygen

Step by step solution

01

- Identify the molar fraction of oxygen

The molar fraction of oxygen (\(y_{\text{O}_2}\)) is given in the problem. According to the molar analysis: \(y_{\text{O}_2} = 0.35\).
02

- Note the total amount of gas mixture

The problem states that there are \(5\) kmol of the gas mixture.
03

- Calculate kmol of oxygen

The number of kmol of oxygen can be found by multiplying the molar fraction of oxygen by the total amount of the gas mixture. Use the formula: \( \text{kmol of } O_2 = y_{\text{O}_2} \times \text{Total kmol of mixture} \). Substituting the known values: \( \text{kmol of } O_2 = 0.35 \times 5\).
04

- Compute the result

Multiplying these values gives: \( \text{kmol of } O_2 = 1.75\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Fraction
In an ideal gas mixture, each component gas has a molar fraction. This is the number of moles of a particular gas divided by the total number of moles in the mixture. It tells us the proportion of that gas in the mixture.
The molar fraction is denoted by the symbol 'y' followed by a subscript representing the particular gas. For example, for oxygen, it’s written as \( y_{\text{O}_2} \).
To calculate the molar fraction, use the formula:
  • \[ y_i = \frac{n_i}{n_{\text{total}}} \]
where \( n_i \) is the number of moles of gas 'i' and \( n_{\text{total}} \) is the total number of moles in the mixture.
For our problem, the molar fractions are:
  • y_{\text{CO}_2} = 0.4
  • y_{\text{N}_2} = 0.25
  • y_{\text{O}_2} = 0.35
Identifying the molar fraction of each gas in the mixture helps us understand how much of each gas is present.
Chemical Composition Analysis
Chemical composition analysis means analyzing the different components in a mixture. For an ideal gas mixture, it involves figuring out the proportions, or molar fractions, of each gas.
Understanding the chemical composition is crucial in various applications like chemical engineering, environmental science, and other fields that require precise mixture compositions.
To analyze the composition:
  • First, identify the molar fractions of each gas given in the problem or derived through experiment.
  • First, identify the total amount of the gas mixture.
  • Determine how many moles of each gas are present using its molar fraction and the total moles of the mixture. The formula is:
    \[ n_i = y_i \times N_{\text{total}} \]
  • Here, \( n_i \) is the moles of the i-th gas, \( y_i \) is the molar fraction of that gas, and \( N_{\text{total}} \) is the total number of moles in the mixture.
Analyzing the composition helps us understand the ratio of each element in practical scenarios.
Oxygen Content Calculation
Calculating the oxygen content in an ideal gas mixture involves using the molar fraction of oxygen and the total number of moles in the mixture.
From the problem, we know:
  • Molar fraction of oxygen, \( y_{\text{O}_2} = 0.35 \)
  • Total moles of the gas mixture, \( N_{\text{total}} = 5 \) kmol
To find the amount of oxygen in kmol, we use the formula:

  • \[ n_{\text{O}_2} = y_{\text{O}_2} \times N_{\text{total}} \]
Substituting the values, we get:
  • \[ n_{\text{O}_2} = 0.35 \times 5 = 1.75 \] kmol
This tells us that there are 1.75 kmol of oxygen in the 5 kmol mixture.
Such calculations are essential in fields like chemical engineering and environmental science, where precise gas compositions are needed.

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Most popular questions from this chapter

Moist air at \(25^{\circ} \mathrm{C}, 1 \mathrm{~atm}\), and \(40 \%\) relative humidity enters an evaporative cooling unit operating at steady state consisting of a heating section followed by a soaked pad evaporative cooler operating adiabatically. The air passing through the heating section is heated to \(43^{\circ} \mathrm{C}\). Next, the air passes through a soaked pad exiting with \(40 \%\) relative humidity. Using data from the psychrometric chart, determine (a) the humidity ratio of the entering moist air mixture. (b) the rate of heat transfer to the moist air passing through the heating section, in \(\mathrm{kJ}\) per kg of mixture. (c) the humidity ratio and temperature, in \({ }^{\circ} \mathrm{C}\), at the exit of the evaporative cooling section.

Moist air enters a duct at \(17^{\circ} \mathrm{C}, 75 \%\) relative humidity, and a volumetric flow rate of \(100 \mathrm{~m}^{3} / \mathrm{min}\). The mixture is heated as it flows through the duct and exits at \(33^{\circ} \mathrm{C}\). No moisture is added or removed, and the mixture pressure remains approximately constant at 1 bar. Changes in kinetic and potential energy can be ignored. For steady-state operation, determine (a) the rate of heat transfer, in \(\mathrm{kJ} / \mathrm{min}\). (b) the relative humidity at the exit.

An insulated tank having a total volume of \(0.81 \mathrm{~m}^{3}\) is divided into two compartments. Initially one compartment having a volume of \(0.27 \mathrm{~m}^{3}\) contains \(1 \mathrm{~kg}\) of carbon monoxide (CO) at \(257^{\circ} \mathrm{C}\) and the other contains \(0.2 \mathrm{~kg}\) of helium (He) at \(17^{\circ} \mathrm{C}\). The gases are allowed to mix until an equilibrium state is attained. Determine (a) the final temperature, in \({ }^{\circ} \mathrm{C}\). (b) the final pressure, in \(\mathrm{kPa}\). (c) the exergy destruction, in \(\mathrm{kJ}\), for \(T_{0}=17^{\circ} \mathrm{C}\).

In the condenser of a power plant, energy is discharged by heat transfer at a rate of \(836 \mathrm{MW}\) to cooling water that exits the condenser at \(40^{\circ} \mathrm{C}\) into a cooling tower. Cooled water at \(20^{\circ} \mathrm{C}\) is returned to the condenser. Atmospheric air enters the tower at \(25^{\circ} \mathrm{C}, 1\) bar, \(35 \%\) relative humidity. Moist air exits at \(35^{\circ} \mathrm{C}, 1\) bar, \(90 \%\) relative humidity. Makeup water is supplied at \(20^{\circ} \mathrm{C}\). For operation at steady state, determine the mass flow rate, in \(\mathrm{kg} / \mathrm{s}\), of (a) the entering atmospheric air. (b) the makeup water. Ignore kinetic and potential energy effects.

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