/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 A large number of droplets, each... [FREE SOLUTION] | 91Ó°ÊÓ

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A large number of droplets, each of radius \(a\), coalesce to form a big drop of radius \(b\). Assume that the energy released in the process is converted into kinetic energy of the drop. The velocity of the drop is \((\sigma=\) surface tension, \(\rho=\) density of droplet \()\) (a) \(\left[\frac{\sigma}{\rho}\left(\begin{array}{ll}\frac{1}{a} & \frac{1}{b}\end{array}\right)\right]^{1 / 2}\) (b) \(\left[\frac{2 \sigma}{\rho}\left(\begin{array}{ll}\frac{1}{a} & \frac{1}{b}\end{array}\right)\right]^{1 / 2}\) (c) \(\left[\frac{3 \sigma}{\rho}\left(\begin{array}{ll}\frac{1}{a} & \frac{1}{b}\end{array}\right)\right]^{1 / 2}\) (d) \(\left[\frac{6 \sigma}{\rho}\left(\begin{array}{ll}\frac{1}{a} & \frac{1}{b}\end{array}\right)\right]^{1 / 2}\)

Short Answer

Expert verified
The velocity of the drop is \(\left[\frac{6 \sigma}{\rho}\left(\frac{1}{a} - \frac{1}{b}\right)\right]^{1/2}\), which is option (d).

Step by step solution

01

Understand the Concept of Surface Tension Energy

When small droplets coalesce to form a larger drop, the surface area decreases, reducing the surface energy. This released energy is converted into the kinetic energy of the resulting larger drop.
02

Calculate Initial and Final Surface Energies

The surface energy of the droplets can be calculated using the formula for the surface area of a sphere and the surface tension. For the initial droplets with radius \(a\), the total surface energy is \(N \times 4\pi a^2 \times \sigma\), where \(N\) is the number of droplets. For the single large drop of radius \(b\), the surface energy is \(4\pi b^2 \times \sigma\).
03

Determine the Energy Released

The energy released during the coalescence is the difference between the initial and final surface energies, given by \[ \\text{Energy Released} = N \times 4\pi a^2 \times \sigma - 4\pi b^2 \times \sigma \] Using the volume conservation \(N \times \frac{4}{3}\pi a^3 = \frac{4}{3}\pi b^3\), we get \(N = (b/a)^3\). Substitute this into the energy expression:\[ \\text{Energy Released} = 4\pi \sigma \left((b^3/a) \times a^2 - b^2\right) = 4\pi \sigma (b^3 - b^2a)\]
04

Equate Energy Released to Kinetic Energy

The kinetic energy of the large drop is given by \(\frac{1}{2} m v^2\) where \(m\) is the mass of the large drop. Using the density \(\rho\), the mass is \(\frac{4}{3}\pi b^3 \rho\). Set the kinetic energy equal to the released energy to solve for \(v\):\[ 4\pi \sigma (b^3 - b^2a) = \frac{1}{2} \left(\frac{4}{3}\pi b^3 \rho\right) v^2\] Rearrange to solve for \(v\): \[ v^2 = \frac{6 \sigma (b^3 - ab^2)}{b^3 \rho}\]
05

Simplify and Solve for Velocity \(v\)

Divide every term by \(b^3\) to simplify:\[ v^2 = \frac{6 \sigma}{\rho} \frac{(1 - a/b)}{b}\] This equation simplifies to:\[ v^2 = \frac{6 \sigma}{\rho} \left(\frac{1}{a} - \frac{1}{b}\right)\] Thus, the velocity \(v\) is:\[ v = \left(\frac{6 \sigma}{\rho} \left(\frac{1}{a} - \frac{1}{b}\right)\right)^{1/2}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coalescence of Drops
When many small droplets combine to form a larger single drop, this process is known as coalescence. It involves the merging of boundaries between the droplets, ultimately uniting them into one. The primary impact of coalescence is the reduction of total surface area. Many small droplets together have a larger combined surface area than the one large drop that forms from them.

This decrease in surface area is crucial because it directly influences the surface energy. Fewer surface molecules in the large drop mean less energy being held at the surface compared to when the droplets are separate. Understanding coalescence is also key for phenomena like raindrop formation and oil spills dispersing into water. In short, coalescence reduces surface energy and is an energetic transformation influencing fluids in nature.
Surface Energy
Surface energy is the energy present at the surface of a material. In liquids, it is directly related to surface tension, which is the force that makes the surface behave as though it were a stretched elastic membrane. This is why droplets take a spherical shape, minimizing the surface area for a given volume.

In our exercise, when multiple droplets coalesce to form a larger drop, the total surface area is reduced, thus releasing surface energy. The surface energy for each droplet can be calculated using the surface area formula for spheres and the surface tension value. The formula is:
  • Initial surface energy = Total number of droplets \( \times 4\pi a^2 \times \sigma \)
  • Final surface energy = \( 4\pi b^2 \times \sigma \)
Here, \(a\) is the radius of the small droplets, \(b\) is the radius of the larger drop, and \(\sigma\) is the surface tension. The difference in these energies is what converts to the kinetic energy of the drop.
Kinetic Energy Conversion
Kinetic energy is the energy of movement. In our context, when the small droplets merge into a larger one, the energy released as surface energy transforms into kinetic energy, propelling the new larger drop forward.

The transformation involves calculating the energy released due to the reduction in surface area and equating it to the kinetic energy formula. The equation for kinetic energy is \( \frac{1}{2} m v^2 \), where \(m\) is mass, and \(v\) is velocity. Using the volume conservation principle, the mass of the large drop can be computed, and the released surface energy can be set equal to this kinetic energy. The formula simplifies to find the velocity \(v\) of the big drop:
  • \( v = \left(\frac{6 \sigma}{\rho} \left(\frac{1}{a} - \frac{1}{b}\right)\right)^{1/2} \)
This describes how the potential energy loss of surface tension is transformed into kinetic energy that moves the drop. Understanding this conversion is essential in dynamics involving fluids and their interactions with other media.
Sphere Surface Area Formula
The surface area of a sphere is crucial for many physics problems, particularly when dealing with fluids and surface tension. The formula for the surface area of a sphere is:
  • Surface Area = \( 4\pi r^2 \)
where \(r\) is the radius of the sphere.

This formula is used to calculate the surface energy in our exercise, as surface tension is quantified in terms of area. When droplets coalesce, the total initial surface area is the sum of the surfaces of all spheres before coalescence, calculated using their individual radii. Once they combine to form a larger sphere (the big drop), only the surface area of the single large sphere is considered.

This understanding helps quantify the changes in surface area and, subsequently, energy when droplets merge. The surface area reduction results in decreased surface energy, which, as explained earlier, gets converted into kinetic energy. This conversion showcases the interconnectedness of geometry and energy transformations in fluid dynamics.

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