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Column-1 Column-II (different forms of Bernoulli's equation) (possible unit) (a) \(\frac{V^{2}}{2 g}+\frac{P}{\rho g}+z-\) constant (p) Total energy per unit mass (b) \(\frac{\rho V^{2}}{2 g}+P+\rho g z-\) constant (q) Total energy per unit volume (c) \(\frac{V^{2}}{2}+\frac{p}{\rho}+g z-\) constant (r) Total cnergy per unit weight

Short Answer

Expert verified
(a)–(r); (b)–(q); (c)–(p).

Step by step solution

01

Analyze the Expression in (a)

The expression \( \frac{V^{2}}{2 g}+\frac{P}{\rho g}+z \) equates to a constant, representing Bernoulli's equation normalized by gravity. This form represents energy per unit weight, linking velocity head, pressure head, and elevation head to a constant.
02

Match (a) to its Corresponding Description

Since the expression in (a) includes terms divided by \( g \), it reflects total energy per unit weight. Therefore, (a) matches with (r).
03

Analyze the Expression in (b)

The expression \( \frac{\rho V^{2}}{2 g}+P+\rho g z \) is set to a constant. It incorporates density and resembles terms in energy per volume analysis, particularly focusing on pressure, kinetic, and potential energy density terms.
04

Match (b) to its Corresponding Description

The representation of energy in expression (b) as a function of volume indicates that (b) corresponds with total energy per unit volume. Therefore, (b) matches with (q).
05

Analyze the Expression in (c)

The expression \( \frac{V^{2}}{2}+\frac{p}{\rho}+g z \) corresponds to a constant, featuring kinetic, potential, and pressure terms divided by mass, hence representing energy per unit mass.
06

Match (c) to its Corresponding Description

Given that (c)'s terms reflect energy per mass, (c) aligns with total energy per unit mass. Hence, (c) matches with (p).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Dynamics
Fluid dynamics is a branch of physics that explores how fluids (liquids and gases) behave when they are in motion. Understanding fluid dynamics is essential because it allows us to predict how fluids flow, interact, and change under various conditions. This understanding has practical applications in engineering, meteorology, oceanography, and even medicine. Fluid dynamics studies concepts like:
  • Velocity: How fast a fluid particle moves through a space.
  • Pressure: The force exerted by the fluid on the walls of its container or on objects placed within it.
  • Viscosity: A measure of a fluid's resistance to flow.
In Bernoulli's equation, fluid dynamics concepts combine to describe the conservation of energy in a flowing fluid. By analyzing velocity, pressure, and gravitational potential energy, Bernoulli’s equation helps us determine how energy is distributed within the fluid system. This knowledge helps optimize systems like piping networks and airfoil designs to enhance efficiency and performance. Understanding fluid dynamics is crucial for designing systems that involve fluid transport and management.
Energy Conservation in Fluids
Energy conservation in fluids is a fundamental principle derived from Bernoulli's equation. It asserts that, in a steady flow of an ideal fluid along a streamline, the total mechanical energy remains constant. This energy can appear as kinetic energy, potential energy, or pressure energy. Bernoulli's equation reflects these three components:
  • Kinetic energy: Represented by the term \( \frac{V^{2}}{2} \), this is energy due to the fluid's velocity. Faster movements increase kinetic energy.
  • Potential energy: The energy represented by \( gz \), dependent on height. fluids at greater heights possess more potential energy.
  • Pressure energy: Displayed by \( \frac{p}{\rho} \), it shows energy stored in the fluid due to pressure.
Energy conservation in fluids highlights how energy can transform among these types without loss. For example, when pressure energy decreases, kinetic or potential energy might increase, maintaining the total energy constant. This transformation plays an essential role in many real-world applications like calculating fluid flow rates, predicting pressure changes, and streamlining fluid systems for optimized performance.
Units of Energy in Fluids
Different forms of Bernoulli's equation represent energy with varying units, providing insights into the fluid's characteristics:
  • Per unit mass: When energy terms are related to mass, the units often are Joules per kilogram \( (J/kg) \). This reflects how energy is distributed within a fluid based on mass.
  • Per unit weight: Division by weight gives a form that uses units like energy per Newton \( (J/N) \). This is particularly useful for understanding energy based on gravitational effects.
  • Per unit volume: Energy linked to volume uses units like Joules per cubic meter \( (J/m^3) \). It helps visualize how pressure, kinetic, and potential energies combine to create an overall energy density in a fluid system.
These different expressions and units help to apply Bernoulli's equation effectively across various domains. Converting between these units allows engineers to tailor solutions according to specific system requirements. Being familiar with the units of energy in fluids leads to better analysis and prediction of fluid behavior in different scenarios.

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Most popular questions from this chapter

A capillary tube is dipped in water vertically. It is sufficient long so that water rises to maximum height \(10 \mathrm{~cm}\) in the tube. The length of the portion immersed in water is \(25 \mathrm{~cm}\). The lower end of the tube is closed, the tube is taken out and opened again. Then (a) All water flows out of the tube (b) The length of the water column remaining in the tube will be \(10 \mathrm{~cm}\) (c) The length of the water ramaining in the tube will be \(20 \mathrm{~cm}\) (d) the length of the water column remaining in the tube will be \(35 \mathrm{~cm}\)

An elastic metal rod will change its length when it (a) falls vertically under its weight (b) is pulled along its length by a force acting at one end (c) rotates about an axis at one end (d) slides on a rough surface

Find the relative change in the density of a cylindrical copper rod when it is comprcssed by a pressure \(P\). Young's modulus is \(Y\), Poisson ratio \(v\).

A composite rod consists of a steel rod of length \(25 \mathrm{~cm}\) and area \(2 A\) and a copper rod of length \(50 \mathrm{~cm}\) and area \(A\). The composite rod is subjected to an axial load \(F\). If the Young's moduli of steel and copper are in the ratio \(2: 1\), then which statement \(/ \mathrm{s}\) is/are correct? (a) the extension produced in copper rod will be more (b) the extension in copper and steel parts will be in the ratio \(1: 2\) (c) the stress applied to copper rod will be more (d) no extension will be produced in the steel rod

A drop of water of volume \(V\) is pressed between two glass plates so as to spread to an area \(A\). If \(T\) is the surface tension, the normal force required to separate the glass plates (a) \(\frac{T A^{2}}{V}\) (b) \(\frac{2 T A^{2}}{V}\) (c) \(\frac{4 T A^{2}}{V}\) (d) \(\frac{T A^{2}}{2 V}\)

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