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If the radius of the carth were increased by a factor of 2 kecping the mass constant, then by what factor would its density have to be changed to keop \(g\) the same? (a) \(\frac{1}{8}\) (b) 4 (c) \(\frac{1}{2}\) (d) \(\frac{1}{4}\)

Short Answer

Expert verified
(a) \( \frac{1}{8} \)

Step by step solution

01

Understanding the Relationship Between Density and Gravity

The gravitational force on the surface of a sphere (like the Earth) is given by the equation \( g = \frac{GM}{R^2} \), where \( G \) is the gravitational constant, \( M \) is mass, and \( R \) is radius. To maintain the same \( g \), we need to adjust the density since \( M = \rho V \), where \( \rho \) is density and \( V \) is volume.
02

Calculate the New Volume

The volume of a sphere is given by \( V = \frac{4}{3}\pi R^3 \). If the radius is increased by a factor of 2, the new volume \( V' \) becomes \( V' = \frac{4}{3}\pi (2R)^3 = \frac{4}{3}\pi \times 8R^3 = 8V \). Thus, the volume increases by a factor of 8.
03

Relate Density to the Volume Change

To keep \( M \) constant, \( \rho'V' = \rho V \) must hold, where \( \rho' \) is the new density. Since \( V' = 8V \), \( \rho' \times 8V = \rho V \) simplifies to \( \rho' = \frac{\rho}{8} \). Therefore, the density must decrease by a factor of 8.
04

Conclusion Based on Calculations

The factor by which the density has to change to keep gravity the same is \( \frac{1}{8} \). Therefore, the answer is choice (a) \( \frac{1}{8} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a fundamental property of matter, defined as mass per unit volume. It is expressed by the formula \( \rho = \frac{M}{V} \), where \( M \) is mass and \( V \) is volume. In simple terms, density tells us how much stuff is packed into a given space. If you imagine the Earth, its density represents how its mass is distributed within its volume.
The density of an object influences its gravitational force. If you were to change the radius of the Earth but keep its mass the same, the density would have to adjust accordingly to maintain the same gravitational pull on its surface. Understanding how density alters in response to changes in volume is crucial for maintaining gravitational equilibrium. In this context, when the Earth's radius doubles, its volume increases by a factor of 8, necessitating a reduction in density by the same factor to keep gravity constant.
Volume of a Sphere
The volume of a sphere is determined using the formula \( V = \frac{4}{3}\pi R^3 \), where \( R \) represents the radius of the sphere. This formula shows how a small change in the radius can significantly impact the volume because volume increases with the cube of the radius.
  • For example, if you double the radius of a sphere, as shown in the exercise, the new volume becomes \( 8 \) times the original.
  • This is because \( (2R)^3 = 8R^3 \), and when plugged into the volume formula, the sphere's volume scales up by a factor of 8.
The concept is simple but has profound implications in gravitational physics and helps explain why the Earth's density must decrease when its radius increases to maintain the same surface gravity.
Gravitational Constant
The gravitational constant, denoted by \( G \), is a pivotal constant in physics. It appears in Newton's law of universal gravitation, which states that every point mass attracts every other point mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The constant \( G \) serves to make the equation dimensionally consistent and allows us to calculate the gravitational force.
In the equation \( g = \frac{GM}{R^2} \), where \( g \) is the gravitational force at the Earth's surface, \( G \) helps define how this gravitational pull is affected by changes in mass and distance (radius). Understanding this constant is crucial for grasping how alterations in the Earth's physical dimensions would influence its gravitational field.
Mass of Earth
The Earth's mass is the total quantity of matter contained in the planet. It plays a vital role in determining the gravitational force experienced at its surface. This force is what we perceive as gravity. When solving problems related to gravitational force, understanding the Earth's mass is essential.
Keeping the Earth's mass constant while changing its radius challenges the density and volume balance. Because mass must remain unchanged, any increase in volume due to a radius expansion necessitates a decrease in density. In the case of a doubled radius, while the mass stays constant, these changes must occur proportionally to maintain balance across the gravitational equation. This understanding helps in predicting how gravitational forces might be altered by planetary transformations.

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