/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 A thin spherical shell of mass \... [FREE SOLUTION] | 91Ó°ÊÓ

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A thin spherical shell of mass \(M\) and radius \(R\) has a small hole. A particle of mass \(m\) is released at the mouth of the hole. Then (a) the particle will execute simple harmonic motion inside the shell. (b) the particle will oscillate inside the shell, but the oscillations are not simple harmonic. (c) the particle will not oscillate, but the speed of the particle will go on increasing. (d) none of these

Short Answer

Expert verified
(d) none of these

Step by step solution

01

Understanding the Gravitational Field Inside the Shell

According to the Shell Theorem, the gravitational field inside a thin spherical shell of uniform mass distribution is zero everywhere inside the shell. This implies that any point inside the spherical shell does not experience gravitational force due to the shell.
02

Analyzing the Motion of the Particle

Since the gravitational field inside the spherical shell is zero, any particle inside, such as the particle of mass \(m\) in this scenario, will not experience a net gravitational force. Therefore, there will be no restoring force acting on it to cause an oscillation.
03

Conclusion About the Particle's Motion

With no restoring force to act on the particle of mass \(m\), it will not engage in oscillatory motion. Since the net gravitational force on the particle is zero while it's inside the shell, it will remain at rest once released, barring any external forces, such as a kick or push.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Field
The concept of a gravitational field is crucial in understanding how objects interact with each other through the force of gravity. Imagine a field, somewhat like a magnetic field, which exists around any mass, pulling other masses toward it. This force field is described by the gravitational field strength, which tells us how strong the gravitational influence is at any given point.

For a uniformly distributed mass, like a spherical shell, the Shell Theorem is pivotal. According to this theorem, the gravitational field inside a hollow spherical shell of uniform mass is zero. This means if you were inside such a shell, you would not feel any gravitational pull from the shell itself.
  • Outside the shell, the gravitational field behaves as if all the mass were concentrated at the center.
  • Inside, the field cancels out, resulting in no net gravitational pull from the shell.
Consequently, a particle inside the shell remains unaffected by its gravitational pull.
Simple Harmonic Motion
Simple Harmonic Motion (SHM) is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the opposite direction of displacement. This motion is seen in systems like springs and pendulums.

Key characteristics of SHM include:
  • The presence of a restoring force, such as gravity for a pendulum or elastic potential for a spring.
  • Motion that repeats itself after regular intervals, known as oscillations.
For a particle to perform SHM inside a spherical shell, a restoring force would be needed. However, because the gravitational field inside the shell is zero, the particle experiences no such force, meaning it cannot perform SHM. Thus, without a force guiding its motion back toward an equilibrium point, the particle will not oscillate.
Spherical Shell
A spherical shell is a three-dimensional hollow structure resembling a ball made from a thin layer of material. This concept is essential in physics, especially when exploring gravitational fields and forces.

The Shell Theorem helps us understand how gravity behaves concerning spherical shells. Here are some key features:
  • Uniform mass distribution along the shell provides an equal gravitational pull in all directions inside, effectively canceling itself out.
  • Outside the shell, the gravitational effect depends only on the total mass and the distance from the center, as if all mass were at the center.
  • It provides interesting results in calculations, like those involving gravity inside planets or hollow celestial bodies.
Understanding spherical shells allows scientists and engineers to model complex systems in various fields, from astronomy to mechanical engineering, emphasizing the importance of this concept in scientific studies.

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Most popular questions from this chapter

Three particles each having a mass of \(100 \mathrm{gm}\) are placed on the vertices of an equilateral triangle of side \(20 \mathrm{~cm}\). The work done in increasing the side of this triangle to \(40 \mathrm{~cm}\) is \(\left(G=6.67 \times 10^{\prime \prime} \mathrm{Nm}^{2} \mathrm{~kg}^{2}\right)\) (a) \(5.0 \times 10^{-12} \mathrm{~J}\) (b) \(2.25 \times 10^{-10} \mathrm{~J}\) (c) \(4.0 \times 10^{-11} \mathrm{~J}\) (d) \(6.0 \times 10^{-15} \mathrm{~J}\)

Which of the following are correct? (a) Moon has no atmosphere like carth because the root mean square velocity of all gases is more than their escape velocity from moon's surface. (b) The tangential acceleration of a planet is zero. (c) The atmosphere is held to carh by gravity. (d) nuelcar forec, viscous forec and clectric force are independent of the gravitational cfrect.

A particle of mass \(m\) is placed at the centre of a uniform spherical shell of same mass and radius \(R\). Find the gravitational potential at a distance \(R / 2\) from the centre.

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Let \(V\) and \(E\) be the gravitational potential and gravitational field. 'l'hen select the correct al?crnative (s) (a) the plot of \(E\) against \(r\) (disunce from centre) is discontinuous for a spherical shell (b) the plot of \(V\) against \(r\) is continuous for a spherical shell (c) the plot of \(E\) against \(r\) is discontinuous for a solid sphere (d) the plot of \(V\) against \(r\) is continuous for a solid sphere

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