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'Ihe moment of inertia of a wheel is \(1000 \mathrm{~kg} \mathrm{~m}^{2} . \Lambda\) t a given instant, its angular velocity is \(10 \mathrm{rad} / \mathrm{s}\). After the wheel rotates through an angle of 100 radians, the wheel's angular velocity is \(100 \mathrm{rad} / \mathrm{s}\). Calculate (a) the torque applied on the wheel (b) the increase in rotational kinetic energy

Short Answer

Expert verified
(a) The torque applied is 49500 Nm. (b) The increase in rotational kinetic energy is 4950000 J.

Step by step solution

01

Understand the Given Values

The problem provides the following values: \(I = 1000 \text{ kg m}^2\) (moment of inertia), initial angular velocity \(\omega_i = 10 \text{ rad/s}\), final angular velocity \(\omega_f = 100 \text{ rad/s}\), and the angle rotated \(\theta = 100 \text{ radians}\).
02

Use Work-Energy Principle

The work done by the torque can be equated to the change in rotational kinetic energy, given by the formula \(W = \Delta KE = \frac{1}{2}I\omega_f^2 - \frac{1}{2}I\omega_i^2\). Substitute the given values to calculate the work done.
03

Calculate Change in Rotational Kinetic Energy

Substitute the values into the formula: \[ \Delta KE = \frac{1}{2} \times 1000 \times 100^2 - \frac{1}{2} \times 1000 \times 10^2 \]This simplifies to:\[ \Delta KE = 50000 \times (10000 - 100) = 4950000 \text{ J} \]
04

Relate Work to Torque and Angle

The work done by the torque over the angle \(\theta\) is: \(W = \tau \theta\). Using the calculated work done from Step 3, the torque \(\tau\) can be calculated by re-arranging the formula to \(\tau = \frac{W}{\theta}\).
05

Calculate the Torque Applied

Substitute the known values into the formula:\[ \tau = \frac{4950000}{100} \text{ N m} = 49500 \text{ N m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
Moment of inertia is one of the key concepts in angular motion and is often described as the rotational equivalent of mass in linear motion. It measures an object's resistance to changes in its rotational speed. Just as mass quantifies how much an object resists changes in linear motion, the moment of inertia quantifies the same for rotational motion. - The moment of inertia (\(I\)) depends not only on the mass of an object but also on how that mass is distributed in relation to the axis of rotation.- For the wheel in our exercise, the given moment of inertia is \(1000 \, \text{kg m}^2\), indicating the resistance the wheel has to change its rotational speed.Consider a wheel that is easy to spin when its mass is concentrated around its axis, but more difficult to spin when its mass is concentrated further outwards. This highlights the importance of mass distribution in calculating and underlining the moment of inertia.
Angular Velocity
Angular velocity is a vector quantity that represents the rate of rotation of an object around an axis. It tells us how fast something is spinning, and usually, it is measured in radians per second (rad/s).- The initial angular velocity (\(\omega_i\)) for the wheel is \(10 \, \text{rad/s}\), and the final angular velocity (\(\omega_f\)) is \(100 \, \text{rad/s}\).These values show that the wheel has undergone a significant increase in rotational speed. This change is a crucial factor in determining the work done and torque applied to the wheel. The increase from \(10 \, \text{rad/s}\) to \(100 \, \text{rad/s}\) across an angle of \(100 \, \text{radians}\) signifies an acceleration in angular motion, which indicates external torque was applied to the system to achieve this heightened speed.
Torque
Torque can be thought of as a force that causes an object to rotate about an axis. It's the rotational equivalent of linear force and is typically measured in Newton-meters (N m).- The formula to calculate torque (\(\tau\)) is \(\tau = \frac{W}{\theta}\), where \(W\) represents the work done and \(\theta\) is the angle rotated (in radians).- From the solution, the calculated work done (\(4950000 \, \text{J}\)) and angle \(100 \, \text{radians}\) provide the values needed to find the torque: \( \tau = \frac{4950000}{100} = 49500 \, \text{N m}\).This torque value indicates the effectiveness of the forces applied to change the wheel's rotational speed. Understanding torque is critical to solving problems related to the efficiency and performance of rotational systems.
Rotational Kinetic Energy
Rotational kinetic energy is the energy due to the rotation of an object and is part of its total kinetic energy. It is determined by the object's moment of inertia and its angular velocity.- The formula used to calculate rotational kinetic energy (\(KE\)) is \(KE = \frac{1}{2}I\omega^2\).- In the exercise, we calculate the change in rotational kinetic energy: \(\Delta KE = \frac{1}{2} \times 1000 \times 100^2 - \frac{1}{2} \times 1000 \times 10^2\)This simplifies to: \(\Delta KE = 4950000 \, \text{J}\).The change in rotational kinetic energy reflects how much energy is needed to speed up the wheel from its initial to its final angular velocity. This is directly linked to the work done on the wheel via torque, showcasing the interconnection between these fundamental concepts of angular motion.

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