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\(\Lambda\) block of mass \(m_{1}\) is connected to another block of mass \(m_{2}\) by a light spring of spring constant \(k\). 'The blocks are kept on a smooth horizontal surface. Initially the blocks are at rest and the spring is unstretched when a constant force \(F\) starts acting on the block of mass \(m_{2}\) to pull il. Find the maximum clongation of the spring.

Short Answer

Expert verified
The maximum elongation of the spring is \( x_{max} = \frac{F m_1}{k(m_1 + m_2)} \).

Step by step solution

01

Analyze Forces and System Equilibrium

Consider the forces acting on the system. The force \( F \) is applied to \( m_2 \). Since there is no friction, the system only needs to overcome inertial forces. Initially, the spring is unstretched, so both blocks accelerate together under the influence of force \( F \). The net external force \( F \) acts on the total mass \( m_1 + m_2 \).
02

Calculate the initial acceleration

Utilize Newton's second law to find the acceleration of the system. The equation for acceleration \( a \) can be written from the total force and total mass: \[ a = \frac{F}{m_1 + m_2} \]
03

Determine elongation conditions

The maximum elongation of the spring occurs when the relative velocity between the blocks becomes zero. At this point, the internal energy is fully stored in the spring as potential energy. The work done by the force \( F \) also equals the kinetic energy of the system plus the stored potential energy in the spring.
04

Apply Conservation of Energy

At maximum elongation, the kinetic energy is the same, but potential energy in the spring is maximized. Define the spring's potential energy as: \[ rac{1}{2} k x^2 \]where \( x \) is the elongation. The work done by the force \( F \) equals the change in kinetic energy, plus the change in potential energy of the spring.
05

Set Up And Solve the Energy Equation

Initially, the work done on \( m_2 \) by force \( F \) as it causes elongation \( x \) in the spring, can be written as:\[ F x = \frac{1}{2} k x^2 + \frac{1}{2} (m_1 + m_2) a^2\] Apply the acceleration found in Step 2 to find the relationship:Substitute \( a = \frac{F}{m_1 + m_2} \) in the energy equation and solve the resulting quadratic in \( x \) to find: \[ x = \frac{F}{k} \left(\frac{m_1}{m_1 + m_2}\right) \]
06

Solve for Maximum Elongation

Upon solving the quadratic equation, the solution reveals that the maximum elongation \( x \) occurs when the relative velocity is zero. Simplifying further gives the expression for maximum elongation, \[ x_{max} = \frac{F}{k} \left(\frac{m_1}{m_1 + m_2}\right) \] This shows the extent to which the spring stretches due to the force \( F \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is the foundation of classical mechanics and is crucial for understanding how forces affect motion. It states that the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass. In equation form, this is expressed as:\[ a = \frac{F}{m} \]In the original exercise, we apply Newton's Second Law to calculate the acceleration of the system. Here, the entire force \( F \) is applied to the combined mass of both blocks, \( m_1 + m_2 \). This means that both blocks accelerate together under the influence of \( F \), and the acceleration \( a \) of the system is:\[ a = \frac{F}{m_1 + m_2} \]This step helps us understand how the force affects the motion of the blocks and sets the stage for further analysis of energy changes within the system.
Conservation of Energy
The principle of conservation of energy is key in analyzing the maximum elongation of the spring. This principle states that the total energy of an isolated system remains constant.In our exercise, energy transitions from one form to another but is conserved in total quantity:- Initially, all energy is in the form of work done by force \( F \).- As the system moves, energy is divided into kinetic energy of both blocks and potential energy stored in the spring.The spring achieves maximum elongation when all kinetic energy results in potential energy in the spring. Mathematically, this can be expressed as:\[ F x = \frac{1}{2} k x^2 + \frac{1}{2} (m_1 + m_2) a^2 \]Understanding these energy transformations teaches us how the external force \( F \) not only impacts motion but also physically stretches the spring to its maximum point.
Maximum Elongation
Maximum elongation refers to the furthest stretch of the spring when the relative velocity between blocks becomes zero. At this point, the spring holds maximum potential energy, meaning all kinetic energy of relative motion is converted.To find maximum elongation mathematically:- Recognize the right moment happens when there's no relative motion between blocks.- Utilize energy equations or force analysis to solve for when elongation maximizes.Using:\[ x_{max} = \frac{F}{k} \left( \frac{m_1}{m_1 + m_2} \right) \]This analysis provides insight into the behavior of spring systems and understanding how forces translate into mechanical deformation.
Kinetic and Potential Energy
Kinetic and potential energy are two critical forms of energy involved in the spring dynamics of this problem.
  • Kinetic Energy (KE): When the force \( F \) is first applied, it initially converts into the kinetic energy of the mass system. The kinetic energy of the moving blocks is collectively given by \( \frac{1}{2} (m_1 + m_2) a^2 \).

  • Potential Energy (PE): As the force continues to act, energy is gradually stored in the spring as potential energy, defined by \( \frac{1}{2} k x^2 \), where \( x \) is the instantaneous elongation.

The transition between these energies is seamless, guaranteeing that, as kinetic energy decreases when elongation progresses, potential energy increases, illustrating the fundamental interplay within mechanical systems.

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Most popular questions from this chapter

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