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Statement-1: A body is moving under the action of constant force, Its kinetic energy observed from a uniformly moving frame along any fixed direction changes. Statement-2: The acceleration of a particle observed from a uniformly moving frame is independent on the frame of references.

Short Answer

Expert verified
Both statements are correct; Statement-2 explains why kinetic energy varies in different frames.

Step by step solution

01

Understanding Kinetic Energy in Reference Frames

Consider a body moving under a constant force. Its kinetic energy in a stationary frame is due to its velocity. In a uniformly moving frame, the velocity of the body relative to that frame will change. Thus, the observed kinetic energy from the moving frame will also change.
02

Analyzing Acceleration in Uniformly Moving Frames

The acceleration of a body is defined as the change in velocity over time. When observed from a uniformly moving frame (one moving with constant velocity), the change in velocity remains the same as in the stationary frame. Thus, the observed acceleration remains the same, independent of the movement of the frame.
03

Evaluating Statement-1

Statement-1 suggests that the kinetic energy changes when viewed from a uniformly moving frame. Since the relative velocity changes due to the frame moving, the kinetic energy changes accordingly. Therefore, Statement-1 is correct.
04

Evaluating Statement-2

Statement-2 asserts that acceleration is independent of the reference frame, provided the frame is moving uniformly. Because acceleration is determined solely by the change in velocity over time, it remains the same regardless of the uniform motion of the reference frame. Thus, Statement-2 is correct and explains why the kinetic energy observed can change, as acceleration and force lead to that change.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy in Reference Frames
Kinetic energy is a key concept that describes the energy possessed by an object due to its motion. It is calculated using the formula \( KE = \frac{1}{2} mv^2 \), where \( m \) is the mass of the object and \( v \) is its velocity. In the context of reference frames, especially when observed from a uniformly moving frame, kinetic energy behaves interestingly.

When a body is observed from a stationary frame, its kinetic energy is directly dependent on its velocity in that frame. However, if you switch to a uniformly moving frame, this observation changes. The velocity of the object relative to this new moving frame alters because the frame itself has a velocity. Consequently, the kinetic energy, which is dependent on this relative velocity, will appear different from this moving perspective.

This change in observed kinetic energy is crucial to understand. It highlights how reference frames can affect the perception of physical quantities, even though the intrinsic properties of the object, like its mass, remain unchanged.
Acceleration and Reference Frames
Acceleration is defined as the rate of change of velocity over time and is central to understanding motion dynamics. It is expressed mathematically as \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is the change in velocity and \( \Delta t \) is the change in time.

In the context of reference frames, especially uniformly moving ones, acceleration shows an interesting trait: it remains invariant. This means that whether you observe an object from a stationary frame or from one that moves at a constant velocity, the acceleration observed will be the same. This invariance occurs because acceleration is based on how velocity changes over time, which does not depend on the observer moving at a constant speed.

This independence of acceleration from the reference frame is a fundamental concept. It ensures the uniformity and predictability of physical laws irrespective of our vantage point. It also reinforces the understanding that while speed might vary with different frames, acceleration as a measure of how velocity changes remains constant.
Understanding Uniform Motion
Uniform motion refers to a type of motion where an object moves with constant speed in a straight line. This means that its velocity is unchanging over time and there is no acceleration acting on the object. In the realm of physics, uniform motion is a simple yet fundamentally important concept as it sets the baseline for understanding more complex motions.

When discussing reference frames, uniform motion frames are particularly special. These frames move at a constant velocity, meaning they do not accelerate. Thus, any measurements of velocity or acceleration from such frames are straightforward.

However, when it comes to kinetic energy, observing an object from a uniformly moving frame complicates things. Even though this frame moves uniformly, the object's velocity relative to this frame differs from a stationary frame, affecting the observed kinetic energy. Keeping this distinction in mind helps clarify how different frames influence our observations of motion and energy.

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Most popular questions from this chapter

Which of the following are correct? (a) A body moving with velocity \(v\) can be stopped over a distance \(s\). If the kinetic energy of the body is doubled the body can be stopped over distance \(2 s\), provided the retarding force remains unchanged. (b) The work done by a body is inversely proportional to time. (c) Work equal to \(16 \mathrm{~J}\) is done on a \(2 \mathrm{~kg}\) body to set it in motion. If whole of this work had been used up in increasing the kinetic energy, then the body would have acquired a velocity of \(4 \mathrm{~ms}^{-1}\). (d) If potential energy of a stretched spring is plotted against y-axis and (extension) \(^{2}\) against \(\mathrm{x}\) -axis, then the graph is a straight line.

The mean kinetic energy of a particle of mass \(m\) moving under a constant acceleration in any interval of time when initial and final vclocities are \(u_{1}\) and \(u_{2}\) (a) \(\frac{1}{2} m\left(u_{1}^{2} \mid u_{2}^{2}\right)\) (b) \(\frac{1}{2} m\left(u_{1}^{2} \quad u_{2}^{2}\right)\) (c) \(\frac{1}{6} m\left(u_{1}^{2}\left|u_{2}^{2}\right| u_{1} u_{2}\right)(\) d) Zero

A small block of mass \(m\) is kept on a rough inclined surface of inclination \(\theta\) fixed in an clevator. The elevator goes up with a uniform velocity \(v\) and the block does not slide on the wedge. The work done by the force of friction on the block in a time \(t\) will be: (a) zcro (b) \(m g v t \cos ^{2} \theta\) (c) \(m g v t \sin ^{2} \theta\) (d) \(\frac{1}{2} m g v \sin ^{2} \theta\)

Work done in time \(t\) on a body of mass \(m\) which is accelerated from rest to a speed \(v\) in time \(t_{1}\), as a function of time \(t\) is given by (a) \(\frac{1}{2} m \frac{v}{t_{1}} t^{2}\) (b) \(m \frac{v}{t_{1}} t^{2}\) (c) \(\frac{1}{2} \frac{m v^{2}}{t_{1}} t^{2}\) (d) \(\frac{1}{2} m \frac{v}{t_{1}} t^{2}\)

Consider a hypothetical relation giving potential energy of a system of two atoms in a diatomic molecule: \(U-\frac{\alpha}{r^{11}} \frac{\beta}{r^{5}}\), (where \(\alpha\) and \(\beta\) are constant, \(r\) represents interatomic scparation). Interatomic separation at the equilibrium is (a) \(\left(\frac{11 \alpha}{5 \beta}\right)^{1 / 6}\) (b) \(\left(\frac{11 \alpha}{\beta}\right)^{1 / 6}\) (c) \(\left(\frac{5 \beta}{11 \alpha}\right)^{1 / 6}\) (d) \(\left(\frac{\beta}{11 \alpha}\right)^{1 / 6}\)

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