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Statement-1: Work done by a force acting on a particle may be negative, even if kinetic energy of the body remains constant. Statement-2: Work done by conservative force equals negative of change in potential cnergy of Lhe body.

Short Answer

Expert verified
Both Statement-1 and Statement-2 are correct.

Step by step solution

01

Understanding Work Done

Work done by a force is defined as the product of the force and the displacement in the direction of the force. Mathematically, it can be expressed as: \( W = F \cdot d \cdot \cos(\theta) \). It can be negative when the force acts opposite to the direction of displacement (\( \theta > 90^\circ \)).
02

Understanding Kinetic Energy and Work

Kinetic energy depends on the velocity of the object: \( KE = \frac{1}{2}mv^2 \). If kinetic energy is constant, the speed of the particle does not change, meaning net work on the particle is zero. However, individual forces might still do work.
03

Analyzing Statement-1

For Statement-1, even if the kinetic energy remains constant, work can be negative if there is another force doing an equal amount of positive work. This ensures that the total work (work done by all forces) is zero, keeping kinetic energy constant.
04

Exploring Conservative Forces

A conservative force, like gravity, has work done that can be linked to potential energy changes. The work done by a conservative force is expressed as: \( W = -\Delta U \), where \( \Delta U \) is the change in potential energy of the system.
05

Analyzing Statement-2

Statement-2 states that work done by a conservative force equals the negative change in potential energy. This is accurate based on the definition of conservative forces, which is consistent with the conservation of mechanical energy.
06

Final Conclusion

Both statements are correct. Statement-1 describes a scenario consistent with the conservation of mechanical energy. Statement-2 is true by the definition of conservative forces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work Done by a Force
Work is a measure of energy transfer, and in physics, it's the result of a force moving an object over a distance. When discussing work, it's important to consider both the magnitude of the force and the direction relative to the object's movement. The formula for work is given by \( W = F \cdot d \cdot \cos(\theta) \), where:
  • \( W \) is the work done.
  • \( F \) is the magnitude of the force applied.
  • \( d \) is the displacement of the object.
  • \( \theta \) is the angle between the force and the displacement vector.
When the angle \( \theta \) is greater than 90 degrees, work done becomes negative. This happens when a force acts opposite the direction of movement, like friction slowing down a moving book. Even if kinetic energy (which depends on speed) remains constant, work can still be occurring due to competing forces like friction and propulsion, balancing each other's effects. This interplay allows kinetic energy to stay unchanged while individual forces perform positive or negative work.
Conservative Forces
Forces in physics can be classified as either conservative or non-conservative. A conservative force, such as gravity or the spring force, has two main characteristics:
  • It depends only on the initial and final positions of the object, not on the path taken.
  • Work done by the force around any closed path is zero.
An essential property of conservative forces is their relation to potential energy. When a conservative force does work, it results in a change in potential energy. This is expressed mathematically as \( W = -\Delta U \), where \( \Delta U \) is the change in potential energy. This relationship highlights that energy is conserved in mechanical systems involving only conservative forces. Such forces can store and release energy without loss, behaving like a perfect spring or pendulum, allowing potential energy to convert into kinetic energy and vice versa without affecting the total mechanical energy of the system.
Potential Energy
Potential energy is stored energy based on an object's position or arrangement. It represents the capacity to do work as a result of position or configuration. Gravitational potential energy and elastic potential energy are two common types associated with conservative forces.
  • Gravitational Potential Energy is energy stored due to an object's height above the ground. It's calculated as \( U = mgh \), where \( m \) is mass, \( g \) is acceleration due to gravity, and \( h \) is the height.
  • Elastic Potential Energy is energy stored in objects like springs, described by \( U = \frac{1}{2}kx^2 \), with \( k \) as the spring constant and \( x \) as the displacement from equilibrium.
The concept of potential energy is crucial in understanding how forces like gravity store energy, converting it back to kinetic energy when, for example, a lifted object falls. Potential energy is intrinsic to systems with conservative forces, allowing energy to be transformed without loss, unlike non-conservative forces that can dissipate energy as heat or sound. Understanding potential energy's role in these systems helps explain energy conservation, ensuring that the total energy remains constant even as it shifts forms from potential to kinetic and back.

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Most popular questions from this chapter

\(\Lambda\) body projected up has potential cnergy of \(1080 \mathrm{~J}\) and a kinetic energy \(880 \mathrm{~J}\) at a point \(P\) in its path vertically upwards. If its mass is \(10 \mathrm{~kg}\). what is the velocity of projection? What is the maximum height reached by it? What is the height of \(P\) expressed as a fraction of the maximum height reached? Solution Total cncrgy at any point \(=1080+880=1960=\) intial K.E. \(=\frac{1}{2} m v^{2}-\frac{1}{2} \times 10 \times v^{2}\) \(\therefore\) Velocity of projection \(-v-\sqrt{\frac{1960}{5}}-\sqrt{392}-14 \sqrt{2} \mathrm{~m} / \mathrm{sec}\) Total energy is also equal to the P.E. at the highest point. \(\therefore \quad 1960=m \mathrm{gh}=10 \times 9.8 \times h\) \(\therefore\) Maximum height reached \(=20 \mathrm{~m}\) $$ \frac{\text { height of } \mathrm{P}}{\text { maximum height }}-\frac{m g h}{m g H}-\frac{h}{H}-\frac{1080}{1960}-\frac{27}{49} \quad \therefore \quad h-\frac{27}{49} \mathrm{H} $$

A block of mass \(2 \mathrm{~kg}\) is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force \(F=40 \mathrm{~N}\). The kinetic energy of the particle increase \(40 \mathrm{~J}\) in a given interval of time. Then: \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\) (a) tension in the string is \(40 \mathrm{~N}\) (b) displacement of the block in the given interval of time is \(2 \mathrm{~m}\) (c) work done by gravity is \(-20 \mathrm{~J}\) (d) work done by tension is \(80 \mathrm{~J}\)

A block of mass \(m\) is stationary with respect to a rough wedge as shown in figure. Starting from rest in time \(f,\left(m=1 \mathrm{~kg}, \theta=30^{\circ}\right.\), \(a=2 \mathrm{~m} / \mathrm{s}^{2}, t=4 \mathrm{~s}\) ) work done on block: Column-I (a) By gravity (b) By normal reaction (c) By Criction (d) By all the forces Column-II (p) \(144 \mathrm{~J}\) (q) \(32 \mathrm{~J}\) (r) \(56 \mathrm{~J}\) (s) \(48 \mathrm{~J}\) (l) Nonc

Consider a hypothetical relation giving potential energy of a system of two atoms in a diatomic molecule: \(U-\frac{\alpha}{r^{11}} \frac{\beta}{r^{5}}\), (where \(\alpha\) and \(\beta\) are constant, \(r\) represents interatomic scparation). Interatomic separation at the equilibrium is (a) \(\left(\frac{11 \alpha}{5 \beta}\right)^{1 / 6}\) (b) \(\left(\frac{11 \alpha}{\beta}\right)^{1 / 6}\) (c) \(\left(\frac{5 \beta}{11 \alpha}\right)^{1 / 6}\) (d) \(\left(\frac{\beta}{11 \alpha}\right)^{1 / 6}\)

In casc of a simple pendulum of length \(L:\) (a) The maximum possible velocity \((v)\) at lowcst point for oscillations is \(\sqrt{2 g L}\). (b) The pendulum may leave the circle after reaching a certain height if \(v\) lies between \(\sqrt{2 g L}\) and \(\sqrt{5 g L}\) (c) The pendulum will loop if \(v>\sqrt{5 g L}\). (d) None

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