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91Ó°ÊÓ

Statement-1 : Normal reaction acting on a body is always perpendicular to the sufrace. Statement-2 : Normal reaction is a componcnt of contact force.

Short Answer

Expert verified
Both statements are true and related.

Step by step solution

01

Understand Statement 1

Statement-1 claims that the normal reaction force acting on a body is always perpendicular to the surface. This is generally true for rigid, flat surfaces without deformation, where the normal force acts at a 90-degree angle to the surface.
02

Analyze Statement 2

Statement-2 explains that the normal reaction is a component of the contact force. This is accurate because contact forces can be broken up into components: one along the surface (friction) and one perpendicular to the surface (normal force).
03

Compare Statements

Statements 1 and 2 do not contradict each other. In fact, they complement each other by describing the nature and orientation of the normal force as a part of the contact force.
04

Conclude Relationship

Both statements are individually true and consistent with one another. The normal reaction is indeed perpendicular to the surface (Statement-1) and is a component of the contact force (Statement-2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perpendicular forces
When talking about a normal force, it's essential to understand its nature as a perpendicular force. In physics, **perpendicular forces** are those that act at a right angle, or 90 degrees, relative to a surface. Imagine placing a book on a table; the force the table exerts on the book is perpendicular to its surface. This force is what we call the normal force.

Why does it act perpendicular? The normal force opposes the force of gravity trying to pull the book down. Since gravity typically acts downward and perpendicular to flat surfaces, the normal force counters this by acting in the opposite direction, directly outward from the surface. It's like a stable seesaw balancing gravitational force.
  • Normal force = Perpendicular to the surface
  • Opposes gravitational pull
  • Ensures equilibrium on flat surfaces
This perpendicular nature helps in determining the stability of objects, ensuring they don't sink into or float above the surface unless an additional force acts upon them.
Contact forces
Contact forces come into play whenever two objects touch each other. These are forces that arise from the interaction between objects in direct contact with one another. **Contact forces** can generally be split into two main components: the frictional force, which is parallel to the surface, and the normal force, which is perpendicular.

The concept involves understanding how objects interact at their point of contact. For instance, when you press your hand against a wall, you experience a reaction. This is a contact force responding to your push. The normal component pushes back perpendicular to the surface, while the frictional component acts along the surface if any sliding motion occurs.
  • Contact force = Combination of friction and normal forces
  • Acts when objects are in touch
  • Balances and opposes external forces
Recognizing these two components, the normal force helps maintain stability, while the frictional component can either aid or resist motion across the surface.
Frictional forces
Frictional forces are a crucial part of contact forces. Friction occurs when two surfaces slide or attempt to slide across each other. This frictional force resists the relative motion of the surfaces. **Frictional forces** act parallel to the surfaces in contact. If you push a box on the floor, friction works against your push by slowing it down.

Understanding how friction works requires identifying factors like surface roughness and the nature of the materials. Frictional forces can vary greatly depending on these, from smooth surfaces with minimal friction to rough surfaces where much more force is needed to initiate movement.
  • Friction = Opposes motion
  • Parallel to the contact surface
  • Influenced by surface material and texture
Without friction, objects could slide indefinitely with little resistance once set in motion. However, with enough friction, objects can remain stationary even on inclined surfaces, providing essential grip and traction in everyday situations.

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Most popular questions from this chapter

A time vary force applied on a body of \(m\) is \(F=a t-b t^{2}\) where \(a\) and \(b\) arc arbitrary constant. The correct options is/are (a) The force is maximum at \(t-\frac{a}{2 b}\) (b) Maximum impulse is \(\frac{a^{3}}{12 b^{2}}\) (c) Maximum force is \(\frac{a^{2}}{4 b}\) (d) Maximum force is \(\frac{a^{2}}{2 b}\)

\(\Lambda\) block of mass \(2 \mathrm{~kg}\) slides down an inclined plane which makes an angle of \(30^{\circ}\) with the horizontal. The cocfficient of finction between the block and the surface is \(\frac{\sqrt{3}}{2}\) (a) What force must be applicd to the block so that the block moves down the planc without accclcration? (b) What force should be applicd to the block so that it can move up without any acecleration? (c) Calculate the ratio of powers nceded in the above two cases, if the block moves with the same specd in both the cases.

Two blocks \(A\) and \(B\) of masses \(10 \mathrm{~kg}\) and \(12 \mathrm{~kg}\) respectively are kept on a rough wedge of inclination \(30^{\circ}\) and \(60^{\circ}\) respectively. The coefficient of friction between the block \(A\) and wedge is \(0.6\) while that between \(B\) and the wedge is \(0.3\). The blocks are connected by a light inextensible thread. The wedge is fixed with respect to ground. Force of friction acting on the block \(A\) is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) ) (a) \(35.92 \mathrm{~N}\) (b) \(25.79 \mathrm{~N}\) (c) \(51.96 \mathrm{~N}\) (d) \(54.83 \mathrm{~N}\)

Two blocks \(A\) and \(B\) of masses \(10 \mathrm{~kg}\) and \(12 \mathrm{~kg}\) respectively are kept on a rough wedge of inclination \(30^{\circ}\) and \(60^{\circ}\) respectively. The coefficient of friction between the block \(A\) and wedge is \(0.6\) while that between \(B\) and the wedge is \(0.3\). The blocks are connected by a light inextensible thread. The wedge is fixed with respect to ground. Tension in the thread connceling \(A\) and \(B\) is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) ) (a) \(24.83 \mathrm{~N}\) (b) \(85.92 \mathrm{~N}\) (c) 7.cro (d) \(55.79 \mathrm{~N}\)

A body with a mass \(m\) slides along the surface of a trihedral prism of mass \(M\), whose upper plane is inclined at an angle \(\alpha\) to the horizontal. The prism rests on a horizontal plane having a vertical wall at the rear edge of the prism to keep it at rest. The normal reaction on the block is (a) \(m g\) (b) \(M g\) (c) \(m g \cos \alpha\) (d) \(m g \sin \alpha \cos \alpha\)

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