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Statement-1: A body under the action of two forces is in cquilibrium. Statement-2: The forces must be collincar.

Short Answer

Expert verified
Both statements are true; Statement-2 explains why Statement-1 is true.

Step by step solution

01

Understanding Equilibrium

In physics, for a body to be in equilibrium, the net force and net torque acting on the body must be zero. This can occur in two types of equilibrium: static (where the body is completely at rest) and dynamic (where the body moves at a constant velocity).
02

Analyzing Statement-1

Statement-1 claims that a body under the action of two forces is in equilibrium. For this to be true, the vector sum of the forces acting on the body must be zero, that is \(\vec{F}_1 + \vec{F}_2 = 0\). This implies that the two forces are equal in magnitude and opposite in direction.
03

Analyzing Statement-2

Statement-2 proposes that two forces must be collinear for the body to be in equilibrium. Collinear forces mean that the forces act along the same line. Since the forces must cancel each other out in magnitude and direction, they inherently must also be collinear.
04

Connecting the Statements

Both statements are concerned with the condition of equilibrium of a body. Statement-2 provides the necessary property -- collinearity -- for Statement-1 to hold. Hence, Statement-2 is a correct explanation for Statement-1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collinear Forces
Collinear forces play a crucial role in achieving equilibrium for a body. To understand collinear forces, imagine forces that act along the same straight line. For a body under the action of two forces to be in equilibrium, these forces must be collinear. This means they should align perfectly along the same line.

The concept of collinearity is important because it allows the forces to be equal in magnitude but opposite in direction. This causes them to effectively cancel each other out. If the forces are not collinear, they will create a net force that causes movement, thus disturbing equilibrium.

Imagine two people playing tug-of-war on a straight rope. For the game to be in a state of equilibrium, both players must pull with equal force and in opposite directions, maintaining the rope straight along one line. This highlights how collinear forces interact to maintain balance.
Vector Sum of Forces
The vector sum of forces refers to the sum of all forces acting on a body, taking into account both magnitude and direction. In physics, it is crucial for determining if a body is in equilibrium. For a body under two forces to achieve equilibrium, the vector sum of these forces must be zero.

This means that the forces should be equal in strength but opposite in direction. Mathematically, this can be expressed as: \[\vec{F}_1 + \vec{F}_2 = 0\]
Thus, one force exactly cancels out the other, meaning the body experiences no net force and remains in its current state, whether at rest or moving uniformly.

Consider a box on a frictionless floor with two forces acting upon it: one from the left and one from the right. If these forces are equal in magnitude but opposite in direction, their vector sum is zero, and the box remains in equilibrium, neither sliding to the left nor right.
Static and Dynamic Equilibrium
In physics, equilibrium can be categorized into two types: static and dynamic.

  • Static Equilibrium: This occurs when a body is at rest and remains so because the net force and net torque are zero. For example, a book lying on a table is in static equilibrium. It does not move because the gravitational force pulling it down is balanced by the table's support force pushing it up.
  • Dynamic Equilibrium: This form of equilibrium happens when a body is moving with a constant velocity. Here, all forces and torques still equal zero, but the body continues in motion. A practical example is a car cruising at a steady speed on a straight road; the forces of friction and engine power are balanced, and thus, the car maintains its speed and direction.

Understanding these types of equilibrium helps us predict how forces will interrelate in various situations. Whether an object is still or in motion, the necessity for a net force of zero remains a defining characteristic of equilibrium in both static and dynamic cases.

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Most popular questions from this chapter

\(\Lambda\) man of mass \(m\) is standing in a lift which moves down with an upward acceleration \(a\). Find the pseudo force acting on the man as observed by himself. \(\Lambda\) lso find the pseudo force acting on the man if the lift falls freely.

Two blocks \(A\) and \(B\) of masses \(10 \mathrm{~kg}\) and \(12 \mathrm{~kg}\) respectively are kept on a rough wedge of inclination \(30^{\circ}\) and \(60^{\circ}\) respectively. The coefficient of friction between the block \(A\) and wedge is \(0.6\) while that between \(B\) and the wedge is \(0.3\). The blocks are connected by a light inextensible thread. The wedge is fixed with respect to ground. Force of friction acting on the block \(A\) is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) ) (a) \(35.92 \mathrm{~N}\) (b) \(25.79 \mathrm{~N}\) (c) \(51.96 \mathrm{~N}\) (d) \(54.83 \mathrm{~N}\)

Statement-1 : In a frame of reference attached to a particle itself, the acceleration of the particle is zero. Statement-2: The frame of reference which moves with constant velocity w.r.t. another frame of reference is an inertial frame of reference.

If the coefficient of friction between an insect and bowl is \(\mu\) and the radius of the bowl is \(r\), the maximum height to which the insect can crawl in the bowl is (a) \(\frac{r}{\sqrt{1+\mu^{2}}}\) (b) \(r\left[1 \frac{1}{\sqrt{1+\mu^{2}}}\right]\) (c) \(r \sqrt{1+\mu^{2}}\) (d) \(r\left[\sqrt{1+\mu^{2}}-1\right]\)

A system consisting of two blocks kept onc over the other rests over a smooth horizontal surface. Somchow it is sct in motion so that the system of blocks acquires a constant velocity. Friction cocfficicnts between the two blocks is \(\mu(\mu \neq O)\) Statement-1 : Aflerwards, friction between the blocks is static in nature and non zero. Statement-2 : 'The lower block is in translational equilibrium.

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