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Statement-1: According to the Newton's third law of motion, the magnitudc of the action and reaction forec in an action reaction pair is same only in an incrtial frame of refcrenec. Statement-2 : Netwon's laws of motion are applicable in cvery incrtial refcrence frame.

Short Answer

Expert verified
Statement 1 is false; Statement 2 is true.

Step by step solution

01

Analyzing Statement 1

Statement 1 claims that the magnitudes of action and reaction forces in an action-reaction pair are the same only in an inertial frame of reference. According to Newton's Third Law, for every action, there is an equal and opposite reaction. This law holds true in all frames, inertial or non-inertial. Therefore, Statement 1 is incorrect as it incorrectly limits the applicability of Newton's Third Law only to inertial frames.
02

Analyzing Statement 2

Statement 2 states that Newton’s laws of motion are applicable in every inertial reference frame. Newton's laws of motion are indeed formulated to apply within inertial frames (frames either at rest or moving at constant velocity). Thus, Statement 2 is correct.
03

Evaluating Both Statements

Statement 2 correctly describes the applicability of Newton's laws, while Statement 1 falsely restricts Newton's Third Law to only inertial frames. Therefore, while Statement 2 is true, Statement 1 is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inertial Frame of Reference
An inertial frame of reference is a fundamental concept when studying motion and forces. Imagine standing still on solid ground, holding a ball. From your perspective, you're not moving. This is akin to an inertial frame.

Simply put, an inertial frame is a steady situation. No accelerations are acting upon it (like being on a train moving at a constant speed). Within an inertial frame:
  • Objects at rest remain at rest.
  • Objects in motion continue with constant velocity unless acted upon by a force.
Newton's laws of motion, including the famous Third Law, are specifically designed to describe events accurately in these frames.

Non-inertial frames, on the other hand, introduce apparent forces (like the push you feel when a car accelerates suddenly). Such forces can mislead our observations without clear comprehension of the context. Therefore, understanding inertial frames allows physics laws to maintain their universal logic.
Action-Reaction Forces
Action-reaction forces are central to Newton's understanding of forces. They involve pairs. Imagine kicking a ball; your foot exerts a force on the ball (action), and the ball exerts an equal but opposite force back on your foot (reaction).

Important points to remember:
  • Action and reaction forces act on different objects.
  • They don't cancel each other since they are not acting on the same body.
Newton's Third Law makes clear that these forces always occur in pairs and are equal in magnitude but opposite in direction. This law operates universally, not just in inertial frames. Hence, the equal magnitude of these forces remains true regardless of the observer's motion or lack thereof.
Newton's Third Law
Newton's Third Law of Motion is elegantly simple yet powerful in its implications. It states: "For every action, there is an equal and opposite reaction."

This principle has wide-reaching applications:
  • Rocket launches, where the exhaust gases are pushed downwards, and as a reaction, the rocket is propelled upward.
  • Walking, as your foot pushes the ground backward, the ground pushes you forward.
The essence of this law is mutual interaction. Forces do not exist in isolation; they require an interaction between at least two bodies. The force pairs are always equal and opposite.

Importantly, Newton's Third Law is not restricted to inertial frames. It holds true universally, within both moving and stationary contexts. Newton's laws, particularly the third, give a consistent framework for predicting and understanding interactions in the world around us.

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Most popular questions from this chapter

\(\Lambda\) cat of mass \(m=1 \mathrm{~kg}\) climbs to a rope hung over a light frictionless pulley. The opposite end of the rope is tied to a weight of mass \(M=2 \mathrm{~m}\) lying on a smooth horizontal plane. What is the tension of the rope when the cat moves upwards with an acceleration \(a=2 \mathrm{~m} / \mathrm{s}^{3}\) relative to the rope'? Solution Let \(a\) be the absolute upward acceleration of the monkey and \(a\) ' be the absolute downward acceleration of the rope. \(a\) ' is also the tightward acceleration of \(M\). Then, \(b=a-\left(-a^{\prime}\right)\) (since relative acceleration is the vector difference between the absolute accelerations) or \(b-a=a^{\prime}\) Considering upward motion of the cat \(\quad T-m g=m a \ldots\) (i) Considering rightward motion of \(M\) \(T=M a^{\prime}=M(b-a) \quad \ldots(\) ii \()\) From (i) and (ii), we get \(T=\frac{m M}{m+M}(g+b)=\left(\frac{m \times 2 m}{m+2 m}\right)(10+2)=\frac{2 m}{3} \times 12=8 \mathrm{~N}\)

A small sphere is suspended by a light string from the ceiling of a car and the car begins to move with a constant acceleration \(a\). The inclination of the string to the vertical is (a) \(\tan ^{1}(a / g)\) in the direction of motion (b) \(\tan ^{1}(a / g)\) opposite to the direction of motion (c) \(\tan ^{1}(g / a)\) in the direction of motion (d) tan \({ }^{1}(g / a)\) opposite to the direction of motion

A block of mass \(m\) is placed over a rough surface in which minimum force is required to move block, it is given coefficient of friction between block and ground is \(\mu\) \(\mu \quad m\) (a) \(\mu \mathrm{mg}\) (b) \(\frac{\mu m g}{\sqrt{1+\mu^{2}}}\) (c) \(\frac{\mu m g}{2}\) (d) \(2 \mu \mathrm{mg}\)

\(\Lambda\) man of mass \(m\) is standing in a lift which moves down with an upward acceleration \(a\). Find the pseudo force acting on the man as observed by himself. \(\Lambda\) lso find the pseudo force acting on the man if the lift falls freely.

Two blocks having masses \(m_{1}\) and \(m_{2}\) are connected by a thread and are placed on an inclined plane with thread initially in a state of no Lension. Thread will not develop any tension if (a) \(m_{1}>m_{2}\) (b) Plane is smooth (c) No friction acts on \(\mathrm{m} 1\) while it acts on \(\mathrm{m}_{2}\) (d) No friction acts on \(m_{2}\) while it acts on \(m_{1}\)

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