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Statement-1: When a length of \(2.0 \mathrm{~m}\) is converted into centimeter, the result is \(200 \mathrm{~cm}\). Statement-2 : 'l'he numerical value of a measurement is proportional to reciprocal of the size of unit used.

Short Answer

Expert verified
Both Statement-1 and Statement-2 are correct.

Step by step solution

01

Understanding Unit Conversion

To convert a measurement from meters to centimeters, we need to understand the relationship between these two units. We know that 1 meter is equivalent to 100 centimeters. This conversion factor will be important for performing the conversion.
02

Performing the Conversion

Given that the length is 2.0 meters, we multiply this length by the conversion factor: \[ 2.0 \text{ meters} \times 100 \text{ (centimeters/meter)} = 200 \text{ centimeters} \]This calculation confirms that the length in centimeters is indeed 200 cm.
03

Understanding Proportionality in Units

Statement-2 suggests that the numerical value of a measurement changes with the size of the unit. As smaller units are used, the numerical value of the measurement increases proportionally. For example, converting meters to centimeters involves using smaller units (centimeters), which results in a larger numerical value (2.0 becomes 200).
04

Verdict on Both Statements

Statement-1 is a practical conversion that is true given the correct conversion factor. Statement-2 is a general observation about how numerical values of measurements increase when smaller units are used. Both statements support each other, demonstrating that changing units changes the numerical value due to the proportional relationship.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

metric system
The metric system is a standardized system of measurement used worldwide. It simplifies calculations and ensures consistency in the way we measure different quantities. Within the metric system, various units are based on powers of ten, making it easy to convert between larger and smaller units. For instance, a meter is the base unit for length, and it can be broken down into 100 centimeters or expanded into 1,000 millimeters. This intuitive structure helps users intuitively understand and calculate measurements across various scales.

The metric system is particularly beneficial in scientific and mathematical contexts because it allows for straightforward conversions without the need for complex calculations. By using a consistent base such as ten, the metric system allows for easier correlation and conversion between different measurements, eliminating much of the confusion that can arise from using less systematic measurement systems.
  • Meters (m), the base unit for length
  • Liters (L), the base unit for volume
  • Grams (g), the base unit for mass
measurement units
Measurement units are the standardized values that we use to quantify and express dimensions, weights, volumes, and other quantities. They provide a way to communicate and compare measurements effectively. Units form the backbone of systematic calculations, and choosing the right units is crucial in obtaining accurate and meaningful results. In the metric system, common units include meters, liters, and grams, which align with length, volume, and mass.

When converting measurement units, it is essential to understand the relationship between each unit. For example, converting meters to centimeters merely involves multiplying by 100 because one meter equals 100 centimeters. This straightforward approach makes working within the metric system particularly effective.

Different contexts might require different unit choices. Scientific investigations, construction projects, and everyday life all may involve varied units depending on the level of precision and size of the amounts being measured. Understanding how to select and convert these units is crucial to accurate measurement.
proportionality in measurement
Proportionality in measurement pertains to the way numerical values change when a measurement is expressed in different units. When we change the units to smaller denominations, the numerical value of that measurement increases proportionately. Conversely, when using larger units, the numerical value decreases.

This principle of proportionality is clearly demonstrated when converting meters to centimeters. Since a meter is 100 times larger than a centimeter, expressing a length originally measured in meters in centimeters increases the number 100-fold. For example, a length of 2.0 meters becomes 200 centimeters because we multiply by the conversion factor of 100.

The concept of proportionality lies at the heart of unit conversion and is fundamental in ensuring measurements remain consistent and accurately represent the same actual size, regardless of the unit choice. This principle is vital for everyday problem solving, enabling easy transitions between scales and making complex calculations more manageable through proportional adjustments.

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Most popular questions from this chapter

Let \(x, y\) and \(z\) be threc physical quantitics having diflerent dimensions. Which of the following mathematical operations must be meaningless? (a) \(\frac{x}{y}=z\) (b) \(\frac{x \times y}{x+y}=z\) (c) \(x^{2} y^{3}=z\) (d) \(z=x^{2} \div y^{3}\)

Four persons use the same stopwatch (of least count \(100 \mathrm{~ms}\) ) to measure the time-period of a pendulum. Which of following assertions is possibly correct? (a) \(1^{\text {ss }}\) person says that the time period is \(3.75 \mathrm{~s}\) (b) \(2^{\text {nd }}\) person says that the time period is \(2.1 \mathrm{~s}\) (c) \(3^{\text {rd }}\) person says that the time period is \(3.70 \mathrm{~s}\) (d) \(4^{\text {th }}\) person says that the time period is \(2.92 \mathrm{~s}\)

1 Iow many significant figures are there in the following numbers? (a) \(67.8 \pm 0.3\) (b) \(4.899 \times 10^{9}\) (c) \(3.56 \times 10^{6}\) (d) \(0.0065\)

'Ihe diameter of a sphere is measured as \(1.71 \mathrm{~cm}\) using an instrument with a least count \(0.01 \mathrm{~cm}\). What is the percentage error in its surface area?

In the measurcment of \(g\) using simple pendulum the time taken for 30 oscillations is \((61.2 \pm 1.3) \mathrm{s}\) and cffective length of pendulum is \((1.00 \pm 0.01) \mathrm{m} .\) The value of \(g\) with error limits is: (a) \((9.80 \pm 0.2) \mathrm{m} / \mathrm{s}^{2}\) (b) \((9.81 \pm 0.47) \mathrm{m} / \mathrm{s}^{2}\) (c) \((9.49 \pm 0.1) \mathrm{m} / \mathrm{s}^{2}\) (d) \((9.49 \pm 0.47) \mathrm{m} / \mathrm{s}^{2}\)

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