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Round off to three significant figures. (a) \(9.745 \mathrm{~g}\) (b) \(9.835 \mathrm{~cm}\) (c) \(28457 \mathrm{~m}\).

Short Answer

Expert verified
(a) 9.75 g, (b) 9.84 cm, (c) 28500 m.

Step by step solution

01

Understand Significant Figures

Significant figures are the digits in a number that contribute to its accuracy. This includes all digits except leading zeroes, trailing zeroes (when they're merely place-holders), and initially unmarked digits. Our task here is to round each given value to three significant figures.
02

Evaluate Each Number (a)

For the number 9.745, identify the significant figures: 9, 7, 4. The next digit (5) dictates whether we round up. Since it is 5 or greater, we round up the previous digit. So, 9.745 becomes 9.75.
03

Evaluate Each Number (b)

For the number 9.835, identify the significant figures: 9, 8, 3. The next digit (5) will also cause us to round up. Thus, 9.835 becomes 9.84.
04

Evaluate Each Number (c)

For the number 28457, identify the significant figures: 2, 8, 4. The fourth digit (5) suggests rounding up the previous digit. Hence, 28457 becomes 28500, ensuring the other digits are replaced with zero to signify their insignificant status.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rounding Numbers
Rounding numbers is a fundamental skill in mathematics, especially when dealing with significant figures. It's all about simplifying a number while keeping its value close to what it originally was. When rounding, you decide how many digits you want to keep and adjust the number based on the digits you're discarding.

Follow these basic steps for rounding numbers:
  • Identify the last digit you wish to keep: This digit will stay as it is, unless the next digit is 5 or higher.
  • Look at the next digit: If it's 5 or higher, increase the last digit you wish to keep by one. Otherwise, leave the last digit as is.
For example, consider the number 9.745. If you need to round to three significant figures, you look at the fourth digit, which is 5. This means you round the last digit up, making the rounded number 9.75. It's important because rounding affects how precise and reliable your final answer is. Numbers are rounded in science and engineering to reduce error in measurements and calculations.
Precision in Measurements
Precision refers to how closely repeated measurements or calculations will give you similar results. It's crucial when performing experiments or listing values. The more decimal places you have, the more precise your measurement is considered. However, a higher number of decimals isn't always practical, which is why rounding is often necessary.

Here are some reasons precision matters:
  • Accurate Data Representation: Helps in accurately conveying the measurement you performed.
  • Consistency: Provides consistent data that can be more easily compared or tracked over time.
  • Resource Management: Avoids spending too much time and resources measuring to an unnecessary level of detail.
In measurement, ensuring the right amount of precision can prevent misunderstandings or misinterpretations of the data collected. This is particularly important in fields like chemistry or physics, where quantities need to be precise for the integrity of the experiments. Thus, it's important to round off numbers while still maintaining the necessary level of precision to convey accurate data.
Significant Digits Rules
Significant digits rules are guidelines that help you determine which digits in a number are important for its accuracy. This plays a critical role in measurements, calculations, and data reporting.

Some basic rules include:
  • All non-zero digits are significant: For example, in 28457, all the digits 2, 8, 4, 5, and 7 are significant.
  • Leading zeros are not significant: They serve only as placeholders.
  • Any zeros between significant digits are significant: They add to the precision of the measurement.
  • Trailing zeros in a decimal number are significant: These also contribute to the precision.
Understanding these rules allows you to correctly identify the number of significant figures that you should retain when performing rounding. For instance, in the example of the number 9.835, it needs to be rounded to three significant figures to give an accurate representation while eliminating those digits that do not affect the overall precision. This results in a rounded figure of 9.84.

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Most popular questions from this chapter

\(\Lambda\) physical quantity \(X\) is related to three observable \(a, b\) and \(c\) as \(X-\frac{b^{2} \sqrt{a}}{c} .\) The errors of measurements in \(a, b\) and \(c\) are \(4 \%, 3 \%\) and \(2 \%\) respoctively. What is the percentage crror in the quantity \(X^{n}\) ?

The least count of a stop watch is \(\frac{1}{5} \mathrm{~s}\). Two persons \(A\) and \(B\) usc this watch to mcasure the timc ocriod o \([\) an oscillating pendulum. Pcrson \(A\) takes the time period of 30 oscillations and person \(B\) akes the timc period of 50 oscillations. Neglccting all other sources of crror, we ean say that (a) Absolute crror in mcasurcment by \(A\) is greator than that of \(B\) (b) Absolute crror in moasurcment by \(A\) is cqual to that of \(B\) (c) Accuracy in mcasurement by \(B\) is greater than that of \(A\) (d) Aceuracy in mcasurement by \(B\) is cqual to that of \(A\)

In an cxpcriment to determine the radius of a chalk by sercw gauge, the diameter is mcasurod and readings are \(d_{1}=1.002 \mathrm{~cm}, d_{2}=1.004 \mathrm{~cm}\) and \(d_{3}=1.006 \mathrm{~cm}\). Scloct the correct alternatives (a) Mcan absolute cror in radius is \(0.0013 \mathrm{~cm}\) (b) Mean absolute crror in diamcter is \(0.0013 \mathrm{~cm}\) (c) Absolute error in first measurement \(d_{1}\) is \(0.002 \mathrm{~cm}\) (d) Pcrecntage crror in the mcasurcment of diamcter is \(0.13 \%\)

If the velocity \(V\), acceleration \(A\) and force \(F\) are taken as fundamental quantities instead of mass \(M\), length \(L\) and time \(T\), the dimensions of Young's modulus \(Y\) would be (a) \(\mathrm{FA}^{2} \mathrm{~V}^{4}\) (b) \(\Gamma \Lambda^{2} V^{5}\) (c) \(\Gamma \Lambda^{2} V^{3}\) (d) \(\Gamma \Lambda^{2} V^{2}\)

If energy \(E\), velocity \(V\) and time \(T\) were chosen as fundamental physical quantities for measurment, then find the dimension of mass.

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