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\(\Lambda\) body travels uniformly a distance of \((13.8 \pm 0.2) \mathrm{m}\) in a time \((4.0 \pm 0.3) \mathrm{s}\). Find the velocity of the body within error limits and the percentage error.

Short Answer

Expert verified
The velocity is \((3.45 \pm 0.26)\, \text{m/s}\) with a percentage error of \(7.54\%\).

Step by step solution

01

Understand the Given Values

We are given the distance \(d = 13.8 \pm 0.2 \text{ m}\) and the time \(t = 4.0 \pm 0.3 \text{ s}\). Our task is to find the velocity \(v\) of the body along with its error limits and the percentage error.
02

Calculate the Nominal Velocity

The nominal velocity \(v\) is calculated using the formula \(v = \frac{d}{t}\). Substituting the given values, we get:\[ v = \frac{13.8 \text{ m}}{4.0 \text{ s}} = 3.45 \text{ m/s} \]
03

Calculate the Absolute Error in Velocity

The absolute error in velocity \(\Delta v\) can be calculated using error propagation for division:\[ \frac{\Delta v}{v} = \sqrt{\left(\frac{\Delta d}{d}\right)^2 + \left(\frac{\Delta t}{t}\right)^2} \]Substitute \(\Delta d = 0.2\) m and \(\Delta t = 0.3\) s:\[ \frac{\Delta v}{3.45} = \sqrt{\left(\frac{0.2}{13.8}\right)^2 + \left(\frac{0.3}{4.0}\right)^2} \]\[ \frac{\Delta v}{3.45} = \sqrt{(0.0145)^2 + (0.075)^2} \]\[ \frac{\Delta v}{3.45} = \sqrt{0.00021025 + 0.005625} \]\[ \frac{\Delta v}{3.45} = \sqrt{0.00583525} \]\[ \frac{\Delta v}{3.45} \approx 0.076 \]\[ \Delta v = 3.45 \times 0.076 = 0.26 \text{ m/s} \]
04

Determine the Velocity with Error Limits

The velocity with error limits is:\[ v = (3.45 \pm 0.26) \text{ m/s} \]
05

Calculate the Percentage Error

The percentage error in velocity is calculated as:\[ \text{Percentage Error} = \frac{\Delta v}{v} \times 100\% \]Substitute the values:\[ \text{Percentage Error} = \frac{0.26}{3.45} \times 100\% \approx 7.54\% \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Calculation
Velocity is an important concept in physics that measures how fast something moves in a specific direction. It is calculated using the formula:

\[ v = \frac{d}{t}\]where:
  • \(v\) is the velocity
  • \(d\) is the distance traveled
  • \(t\) is the time taken
In this exercise, the given distance is \(13.8 \text{ m}\) and the time is \(4.0 \text{ s}\). Plugging these values into the formula gives the nominal velocity:

\[ v = \frac{13.8}{4.0} = 3.45 \text{ m/s}\]This means the body travels at an average speed of 3.45 meters per second. It's important to calculate velocity correctly to understand motion dynamics, which are crucial for predicting the positions and speed of moving objects.
Error Propagation
Error propagation is a technique used to estimate the uncertainty in the result, based on the uncertainties in the measurements used to calculate that result. When quantities with uncertainties are used in calculations, these uncertainties affect the precision of the final calculated result.

For division, the formula used for error propagation is:

\[ \frac{\Delta v}{v} = \sqrt{\left(\frac{\Delta d}{d}\right)^2 + \left(\frac{\Delta t}{t}\right)^2}\]where:
  • \(\Delta v\) is the absolute error in velocity
  • \(\Delta d\) and \(\Delta t\) are the absolute errors in distance and time, respectively
By substituting the given errors \(\Delta d = 0.2\) m and \(\Delta t = 0.3\) s, we calculated the error in velocity as approximately \(0.26 \text{ m/s}\). This means the calculated velocity \(3.45 \text{ m/s}\) could range from \(3.19 \text{ m/s}\) to \(3.71 \text{ m/s}\). Understanding error propagation is vital in scientific experiments to account for measurement errors and to ensure realistic and reliable data.
Percentage Error
Percentage error provides a way to express the accuracy of a measurement or calculation relative to the expected or accepted value. It is calculated as:

\[ \text{Percentage Error} = \frac{\Delta v}{v} \times 100\%\]where:
  • \(\Delta v\) is the absolute error
  • \(v\) is the measured value
In this exercise, substituting the values yielded a percentage error of approximately \(7.54\%\). This gives a clear idea about how much the calculated velocity deviated from the true velocity due to the errors in measured parameters. Evaluating percentage errors helps in assessing the quality of measurements and guides improvements in experimental techniques to achieve more accurate results.

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Most popular questions from this chapter

Mark the correct statement (s) (a) The reading of a particular physieal quantity measured from an instrument having smaller least count is more accuratc than mousured from an instrument having larger lcast count. (b) The last significant digit in the measurement is uncertain. (c) In a particular measurement, the number of standard deviations is more as compared to previous reading it means \(2^{\text {nil }}\) reading is morc accurate. (d) All o[ the above

If forec \(F\), acceleration \(A\) and time \(T\) be taken as the fundamental physical quantities, the dimensions of length on this system of units are (a) \(F A T^{2}\) (b) \(F A T\) (c) \(F T\) (d) \(A T^{2}\)

Let main scale division of a vernier callipers is \(1 \mathrm{~mm}\). With zero of vernier coinciding with the zero of main scale, the \(50^{\text {th }}\) division of vernier scale coincides with 49 th division of main scale. 'Ihe least count of the vernier is (a) \(0.1 \mathrm{~mm}\) (b) \(0.01 \mathrm{~mm}\) (c) \(0.2 \mathrm{~mm}\) (d) \(0.02 \mathrm{~mm}\)

'Ihe density of a cube is measured by measuring its mass and the length of its sides. If the maximum errors in the measurement of mass and length are \(3 \%\) and \(2 \%\), respectively, then find the maximum etror in the measurement of the density of cube.

The pressure on a square plate is measured by measuring the forec on the plate and the length of the sides of the plate by using the formula \(P-\frac{F}{l^{2}}\). If the maximum crrors in the measurement of force and length are \(4 \%\) and \(2 \%\), respectively, then what is the maximum error in the measurement of pressure?

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