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There are three different liquids \(\Lambda, B\) and \(C\) having same mass. Their temperatures are respectively \(10^{\circ} \mathrm{C} .15^{\circ} \mathrm{C}\) and \(25^{\circ} \mathrm{C}\). When \(A\) and \(B\) are mixed together the temperature of their mixture is \(12^{\circ} \mathrm{C}\). Bul when \(B\) and \(C\) are mixcd then the temperature of their mixture is \(21 "\).. Calculate the temperature when \(A\) and \(C\) are mixcd togethcr.

Short Answer

Expert verified
The temperature when A and C are mixed together is \(17.5^{\circ} \text{C}\).

Step by step solution

01

Understanding Heat Equilibrium for A and B

When two liquids are mixed, the final temperature is a result of their thermal energy exchange. Given that when liquids \(A\) and \(B\) are mixed, the resulting temperature is \(12^{\circ} \text{C}\), we can use the formula for heat exchange: \[ mA_{A} (T_A - T_{ ext{final}}) = mA_{B} (T_{ ext{final}} - T_B) \]where \(m\) is the mass and \(A\) is the specific heat capacity, which cancels out since both liquids have the same mass and specific heat. The temperatures of \(A\) and \(B\) are \(10^{\circ} \text{C}\) and \(15^{\circ} \text{C}\) respectively. Solve for this equation:\[ 10 - 12 = 15 - 12 \]Both sides of the equation are equal, confirming balance of energy.
02

Understanding Heat Equilibrium for B and C

Repeat a similar process for liquids \(B\) and \(C\). When they are mixed, the temperature of the mixture is \(21^{\circ} \text{C}\). Use the formula:\[ mA_{B} (T_B - T_{ ext{final}}) = mA_{C} (T_{ ext{final}} - T_C) \]The temperatures of \(B\) and \(C\) are \(15^{\circ} \text{C}\) and \(25^{\circ} \text{C}\), respectively. Substitute:\[ 15 - 21 = 21 - 25 \]This yields a consistent heat balance as well.
03

Calculating Final Temperature of A and C

Now, apply the concept to liquids \(A\) and \(C\) to find their mixture temperature. Set up the equation:\[ mA_{A} (T_A - T_{ ext{final}}) = mA_{C} (T_{ ext{final}} - T_C) \]Temperatures of \(A\) and \(C\) are \(10^{\circ} \text{C}\) and \(25^{\circ} \text{C}\) respectively. Substitute to find the balance:\[ 10 - T_{ ext{final}} = T_{ ext{final}} - 25 \]Solving this yields:\[ 10 - T = T - 25 \]\[ 2T = 35 \]\[ T = 17.5 \]
04

Conclusion

The resulting temperature when liquids \(A\) and \(C\) are mixed is \(17.5^{\circ} \text{C}\). This result is consistent with equilibrium through the calculations involved on a similar basis to previous mixes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a fundamental concept that describes how thermal energy moves from one object or substance to another. In the context of this exercise, heat transfer occurs when two liquids at different temperatures are mixed together.
The liquid with the higher temperature loses heat to the one with a lower temperature until they reach a common temperature known as thermal equilibrium.
This process happens because heat always flows from the warmer substance to the cooler one, equalizing their energy.
  • When liquids \(A\) and \(B\) are mixed, the temperature balances to \(12^{\circ} \text{C}\). This demonstrates heat moving from the warmer liquid to the cooler one.
  • Similarly, mixing \(B\) and \(C\) yields a mixture temperature of \(21^{\circ} \text{C}\).
Thermal equilibrium is thus a state where no net heat transfer occurs, as both substances have reached the same temperature. This balancing act underpins the calculations for finding the temperature when two different substances are mixed.
Specific Heat Capacity
Specific heat capacity is the measure of a substance’s ability to absorb heat. It tells us how much heat energy one gram of a substance needs to change its temperature by 1 °C.
In the problem, all three liquids have the same specific heat capacity and mass, simplifying our calculations since these values cancel out during heat transfer equations.
Understanding specific heat capacity helps clarify why equal masses of different substances require different amounts of energy to change their temperatures.
Since in this scenario all liquids share the same specific heat capacity, only temperature differences affect the heat balance. The specific heat capacity influences how much the temperature of each liquid changes when mixed. For example:
  • A liquid with higher specific heat would not change its temperature as quickly as one with a lower specific heat when both absorb or lose the same amount of heat.
Temperature Mixing
Temperature mixing is the process by which mixed substances reach a new uniform temperature. Here, it involves calculating the resulting temperature when two liquids of different initial temperatures are combined. The process is guided by energy conservation and the shared specific heat capacity of the substances.
When mixing liquids \(A\) and \(B\):
  • Initial temperatures are \(10^{\circ} \text{C}\) and \(15^{\circ} \text{C}\) respectively.
  • The mixed temperature comes out to \(12^{\circ} \text{C}\).
Similarly, for liquids \(B\) and \(C\):
  • Initial temperatures are \(15^{\circ} \text{C}\) and \(25^{\circ} \text{C}\).
  • The resulting temperature is \(21^{\circ} \text{C}\).
These specifics demonstrate how initial temperatures and equilibrium influence the final result. Temperature mixing equations ensure energy conservation, highlighting how temperature differences are reconciled in mixed liquids.
Energy Conservation
The principle of energy conservation tells us that energy cannot be created or destroyed, only transformed. In the thermal context, this means the total thermal energy of the system remains constant before and after mixing.
In this exercise, energy conservation is key to understanding the final temperatures of liquid mixtures. Here’s how:
  • When mixing \(A\) and \(B\), the heat lost by \(B\) equals the heat gained by \(A\), balancing out to a final temperature of \(12^{\circ} \text{C}\).
  • Similarly, the heat lost by \(C\) and gained by \(B\) equalize to reach \(21^{\circ} \text{C}\).
  • Finally, for \(A\) and \(C\), the balance point is \(17.5^{\circ} \text{C}\).
Energy conservation applies here through the cancellation of the mass and specific heat during calculations, focusing purely on temperature differences. This ensures that when two liquids mix, their combined energy system remains unchanged, adhering to this fundamental law of physics.

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Most popular questions from this chapter

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