Chapter 11: Problem 74
If \(Q\) amount of heat is required to increase the temperature of one mole of a monoatomic gas at constant pressure by \(\wedge T\), the amount of heat required to increase the temperature of half mole of a diatomic gas at constant volume by \(2 \wedge T\) will be (a) \(Q\) (b) \(5 / 3 Q\) (c) \(8 Q\) (d) \(3 / 5 Q\)
Short Answer
Step by step solution
Understand the Heat Formula
Review the Goal
Monoatomic Gas Heat Required
Calculate Heat for Diatomic Gas
Ratio of Heat Required
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat Capacity
- Specific Heat Capacity at Constant Volume ( C_v): Refers to the heat capacity when the volume is kept constant. In this scenario, the gas does not perform any work on its surroundings.
- Specific Heat Capacity at Constant Pressure ( C_p): Refers to the heat capacity when the pressure is constant, which is usually greater than C_v for a given gas since the gas does work on its surroundings as it expands.
Monoatomic Gas
- At constant volume, the heat capacity, C_v, for a monoatomic gas, is \( \frac{3}{2} R \).
- At constant pressure, the heat capacity, C_p, is \( \frac{5}{2} R \).
Diatomic Gas
- At constant volume, C_v is \( \frac{5}{2} R \).
- At constant pressure, C_p is \( \frac{7}{2} R \).
Constant Pressure
- A higher heat capacity ( C_p) compared to constant volume due to work done against external pressure.
- More heat being required to increase the gas's temperature for a given amount.
Constant Volume
- The heat capacity ( C_v) does not include work done by or on the gas, focusing purely on changes in internal energy.
- Less heat is required to change the temperature compared to a constant pressure scenario.