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\(\Lambda\) particle of mass \(m\) is placcd at lowest poinl of smooth parabola \(x^{2}=a y\) ( \(x\) and y in metre). What is the time period for small oscillation? (a) \(2 \pi \sqrt{\frac{a}{g}}\) (b) \(2 \pi \sqrt{\frac{2 a}{g}}\) (c) \(2 \pi \sqrt{\frac{a}{4 g}}\) (d) \(2 \pi \sqrt{\frac{a}{2 g}}\)

Short Answer

Expert verified
The time period for small oscillations is \(2\pi \sqrt{\frac{2a}{g}}\), corresponding to choice (b).

Step by step solution

01

Identify the Forces Involved

The parabola is described by the equation \(x^2 = ay\). The gravitational force acts vertically downwards. For small oscillations, the restoring force is primarily due to gravity acting on the vertically displaced position of the particle.
02

Analyze the Parabola Shape

The parabola opens upwards, and the particle is at the lowest point, which is at the vertex. For small displacements from the vertex, the equation of motion can be linearized.
03

Small Oscillation Approximation

For small displacements about the equilibrium position, the motion can be considered harmonic. The motion along the parabola can be approximated as a simple pendulum if the parabola is shallow.
04

Use Parabolic Curve Equation

For a displacement along the parabola, small displacements can consider the equation as follows: \(\theta = \frac{x}{y}\) and \(\cos \theta \approx 1 - \frac{x^2}{2a}\). For small \(x\), \(y \approx \frac{x^2}{a}\).
05

Determine Expression for Time Period

The time period \(T\) for small oscillations about the equilibrium position is driven by the derivation that mirrors that of a pendulum: \(T = 2\pi \sqrt{\frac{l}{g_{eff}}}\). Here, \(y\) substitutes \(l\), and \(g_{eff}\) acts like \(g\). For our problem, \(T = 2\pi \sqrt{\frac{2a/g}{g}} = 2\pi \sqrt{\frac{2a}{g}}\).
06

Conclusion and Answer Selection

From the derived formula \(T = 2\pi \sqrt{\frac{2a}{g}}\), we find that the answer corresponds to the given choice (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabolic Motion
In physics, parabolic motion refers to the path followed by an object that is influenced by gravity, often depicted as a parabola. The equation given in the exercise, \(x^2 = ay\), describes a parabolic curve. In this scenario, the particle is placed at the lowest point of the parabola, known as the vertex. At this position, the particle has no initial horizontal or vertical velocity.

When the particle is slightly displaced, it will oscillate around this point. This is typical of small oscillations in physics, where the trajectory becomes a smooth, repeating pattern. Since the motion takes place on a curve, understanding parabolic motion can help predict how the particle behaves when it's shifted slightly away from the vertex.
Simple Harmonic Motion
Simple Harmonic Motion (SHM) is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the opposite direction. When a particle undergoes SHM, it moves back and forth through its equilibrium position, creating a smooth, sinusoidal motion.

In the context of the original exercise, the particle at the lowest point of the parabola can experience SHM when displaced slightly from its spot. The forces acting upon it try to return it to equilibrium, resulting in harmonic motion. Understanding SHM is crucial as it provides a simplified model that allows us to analyze complex motions using straightforward mathematics.
Gravitational Forces
Gravitational forces play a pivotal role in determining the motion of objects on Earth. Gravity pulls objects towards the center of the Earth, affecting their motion and speed. For a particle in a parabolic path, like in the exercise, gravity is the primary force creating the oscillation.

The downward gravitational force acts at the particle's position, and for small oscillations, this force leads to a restoring force that encourages harmonic motion. By acknowledging gravity's impact, physicists can predict the oscillatory patterns of particles in similar scenarios, ensuring precise calculations and understanding of their movements.
Small Oscillations
Small oscillations refer to slight deviations from an equilibrium position, wherein the restoring forces are linear. In the exercise mentioned, the particle undergoes such oscillations around the parabola's vertex.

Because these oscillations are minor, certain approximations apply. For instance, the angle \(\theta\) might be particularly small, implying \(\cos \theta \approx 1\). This simplifies the analysis and makes the connection to simple harmonic motion more apparent. These approximations, combined with gravitational forces, provide the necessary framework for determining the motion's time period.
Time Period Calculation
The time period of oscillation, commonly denoted as \(T\), is the duration taken for one complete cycle of the motion. Calculating the time period involves understanding the interplay between restoring forces and inertia. The formula for the time period in SHM is \(T = 2\pi \sqrt{\frac{l}{g_{eff}}}\), where \(l\) is the length of the motion path and \(g_{eff}\) is the effective gravitational acceleration.

In the exercise, similar principles apply. By substituting \(y\) (height in the parabola) for \(l\), and acknowledging gravity's role, the time period formula becomes \(T = 2\pi \sqrt{\frac{2a}{g}}\). This effectively shows how the oscillation behaves over time, helping to determine the correct answer choice. Understanding this concept is vital for mastering the physics of oscillatory movement.

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Most popular questions from this chapter

Which of the following waves will give rise to stationary waves? (a) \(\Lambda \sin (\omega t-k x)+A \sin (\omega t+k x)\) (b) \(A \sin (\omega t-k x)-A \sin (\omega t+k x)\) (c) \(A \sin (\omega t+k x)-A \sin (\omega t-k x)\) (d) \(A \sin ^{2}(\omega t-k x)+B \sin 3(\omega t-k x)\)

\(\delta=\frac{m}{L}=\frac{32}{4} \times 10^{2}=\frac{4}{5} \times 10^{2} \mathrm{~kg} / \mathrm{m}\) Now, According to question, \(v=v_{o}=220 \mathrm{II} z\) \(\therefore \frac{v}{2 L}=220 \mathrm{~Hz} \quad[\quad L=40 \mathrm{~cm}\) \(m=3.2 \mathrm{gm}\) \(\sqrt{\frac{T}{\delta}} \times \frac{1}{2 L}=220 \mathrm{II} z\) 1. \(\sqrt{\frac{T}{\rho}}=220 \times 2 L\) \(\therefore \quad \sqrt{T}=\sqrt{\rho} \times 220 \times 2 L$$$ \begin{aligned} &\therefore \quad T=\rho \times(220 \times 2 L)^{2}=\frac{4}{5} \times 10^{-2}(22 \times 2 \times 4)^{2} \\ &=\frac{4}{5} \times 10^{-2} \times 30976=2478.8 \times 10^{-2} \\ &\text { Now suress }=\frac{F}{\Lambda}=\frac{T}{\Lambda}=\frac{2478.8 \times 10^{-2}}{\left(10^{-3}\right)^{2}} \\ &=2478.8 \times 10^{4}=\mathrm{N} / \mathrm{m}^{2} \end{aligned} $$ and strain $$ =\frac{0.05}{40} \times \frac{10^{2}}{10^{2}}=\frac{5}{40} \times 10^{-2}=\frac{1}{8} \times 10^{-2} $$ \)\therefore$ (Youngs modulus) $$ \begin{aligned} Y &=\frac{\text { stress }}{\text { strain }}=\frac{2478.8 \times 10^{4}}{10^{2} / 8} \\ &=1.98 \times 101^{\prime} \mathrm{N} / \mathrm{m}^{2} \end{aligned} $$

The cquation of a transverse wave travelling on a suring is \(y=2 \cos (0.5 \pi x-150 \pi t)\) where \(x\) and \(y\) are in \(\mathrm{cm}\) and \(t\) is in second. Which of the following are truc? (a) The velocity of the wave is \(3 \mathrm{~m} / \mathrm{s}\) (b) The period of the wave is \(0.1 \mathrm{~s}\) (c) The wavelength of the wave is \(4 \mathrm{~cm}\) (d) The amplitude of the wave is \(2 \mathrm{~cm}\)

A string of length \(L\) is stretched along the \(x\)-axis and is rigidly clamped at its two ends. It undergoes transverse vibrations. If \(n\) is an integer, which of the followings relations may represent the shape of the string at any time \(t ?\) (a) \(y-\Lambda \sin \left(\frac{n \pi x}{L}\right) \cos \omega\) (b) \(y-\Lambda \sin \left(\frac{n \pi x}{L}\right) \sin \alpha\) (c) \(y-A \cos \left(\frac{n \pi x}{L}\right) \cos \omega\) (d) \(y-A \cos \left(\frac{n \pi x}{L}\right) \sin \omega\)

Standing wave \(\xi=a \sin k x \cos \omega t\) is maintained in a homogeneous rod with cross-sectional area \(S\) and density \(\rho\). Find the total mechanical cnergy confined between the sections corresponding to the adjacent displacement nodes.

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