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Two linear SHM of equal amplitudes \(A\) and frequencies \(e\) and \(2 \omega\) are impressed on a particle along \(x\) and \(y\)-axes respectively, If the initial phase difference between them is \(\pi / 2 .\) Find the resultant path followed by the particle.

Short Answer

Expert verified
The resultant path is a Lissajous figure described by function involving \(x\) and \(y\).

Step by step solution

01

Set up the Equation for SHM Along the X-Axis

The simple harmonic motion (SHM) along the x-axis can be described by an equation of the form: \( x = A \cos (\omega t) \), where \( A \) is the amplitude and \( \omega \) is the frequency. Since the amplitude \( A \) and frequency \( \omega \) are given, this is used as our equation for X-axis SHM.
02

Set up the Equation for SHM Along the Y-Axis

Similarly, the motion along the y-axis is a SHM described by: \( y = A \cos (2\omega t + \frac{\pi}{2}) \). This accounts for the frequency being double that of the x-axis and the phase difference of \( \frac{\pi}{2} \).
03

Simplify the Equation for Y-Axis

The given phase difference means the cosine function can be rewritten using a sine function, as \( \cos(\theta + \frac{\pi}{2}) = -\sin(\theta) \). Thus, \( y = -A \sin (2\omega t) \).
04

Find the Relation Between X and Y

To find the resultant path described by the equations, we need to eliminate the parameter \( t \). From \( x = A \cos(\omega t) \), we can express \( \cos(\omega t) = \frac{x}{A} \). Similarly, from \( y = -A \sin(2\omega t) \), express \( \sin(2\omega t) = -\frac{y}{A} \).
05

Use Trigonometric Identity to Relate the Terms

We need to relate \( \cos(\omega t) \) and \( \sin(2\omega t) \). Note that \( \sin(2\omega t) = 2\sin(\omega t)\cos(\omega t) \). Thus, \( y = -2A \sin(\omega t) \cos(\omega t) = -2 \cdot A \sin(\omega t) \cdot \frac{x}{A} = 0 \).
06

Substitute and Simplify

By substituting \( \sin(\omega t) = \sqrt{1 - \left( \frac{x}{A} \right)^2} \) into the equation \( y = -2 \cdot A \sin(\omega t) \cdot \frac{x}{A} \), we have \( y = -2x\sqrt{1-\frac{x^2}{A^2}} \), which simplifies to a specific type of curve expression.
07

Analyze Resultant Path

After simplifying, we find the expression for the coordinates relating the position in terms of \( x \) and \( y \). These steps lead to understanding that the expression describes a Lissajous figure, noting the initial phase difference and frequencies.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Harmonic Motion (SHM)
Simple Harmonic Motion (SHM) is a type of periodic motion where an object moves back and forth along a straight line. It is fundamental in explaining how particles move in predictable patterns. In each SHM:
  • There is an equilibrium position that the object oscillates around.
  • The object experiences a restoring force proportional to its displacement from this equilibrium, typically described by Hooke's law.
  • This motion can be expressed using trigonometric functions such as sine and cosine.
For example, if we consider SHM along the x-axis, the motion can be described as: \[ x = A \cos(\omega t) \]where:
  • \( A \) is the amplitude (maximum displacement)
  • \( \omega \) is the angular frequency, determining how quickly the oscillations occur
  • \( t \) is time
SHM allows for prediction and analysis of vibrating systems, making it crucial in understanding Lissajous figures, which are the graphical representations of two perpendicular SHMs.
Phase Difference
Phase difference is a measure of how much one wave leads or lags behind another wave. It's crucial in analyzing waves that interact. In the study of Lissajous figures, understanding phase difference helps in determining the shape of the resultant path:
  • The phase difference can cause two waves to either reinforce each other or cancel out at various points.
  • It's expressed in radians, where \( \pi/2 \) indicates the waves are out of phase by a quarter cycle.
When dealing with horizontal (x-axis) and vertical (y-axis) SHMs, the initial phase difference plays a significant role.For instance, if the equation for SHM on the y-axis is given by \[ y = A \cos(2\omega t + \frac{\pi}{2}) \]the phase shift of \( \frac{\pi}{2} \) means it can be rewritten using sine:\[ y = -A \sin(2\omega t) \]This conversion is due to the identity \( \cos(\theta + \frac{\pi}{2}) = -\sin(\theta) \). By understanding and manipulating phase difference, we can predict the unique paths formed by the system of SHMs.
Trigonometric Identities
Trigonometric identities are mathematical equations that relate various trigonometric functions. These identities are essential in simplifying and solving complex expressions involving waves, such as those in SHM. Key identities used here include:
  • \( \cos(\theta + \frac{\pi}{2}) = -\sin(\theta) \)
  • Double angle identity: \( \sin(2\omega t) = 2\sin(\omega t)\cos(\omega t) \)
These identities help express one trigonometric function in terms of another, making it easier to relate different aspects of the equations involved.In our context, by using the identity \( \sin(2\omega t) = 2\sin(\omega t)\cos(\omega t) \), we can establish a new relationship:\[ y = -2x\sqrt{1-\frac{x^2}{A^2}} \]This equation helps describe the Lissajous figure formed by the interacting SHMs. Through trigonometric identities, complex wave interactions are made simpler to analyze and understand.

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Most popular questions from this chapter

An open pipe \(40 \mathrm{~cm}\) long and a closed pipe \(31 \mathrm{~cm}\) long, both having same diameler, are producing their first overtone, and these are in unison. Determine the end correction of these pipes.

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