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A ball is thrown horizontally from the top of a 20-meter-tall platform. The ball travels 40 meters horizontally before striking the ground. Determine the initial velocity of the ball. (A) 10 m/s (B) 20 m/s (C) 40 m/s (D) 80 m/s (E) 120 m/s

Short Answer

Expert verified
The initial velocity of the ball is closest to 20 m/s, so the best answer is (B) 20 m/s

Step by step solution

01

Calculate the time it took for the ball to hit the ground

Using the equation of motion, \( h = \frac{1}{2}gt^2 \), where \( h = 20m \) is the height of the fall and \( g = 9.8m/s^2 \) is the acceleration due to gravity. Solving for \( t \), we find \( t = \sqrt{ \frac{2h}{g}} = \sqrt{ \frac{40}{9.8}} = 2.02s \)
02

Calculate the initial horizontal velocity of the ball

The initial horizontal velocity can be found using the equation \( v = \frac{d}{t} \), where \( d = 40m \) is the horizontal distance travelled by the ball and \( t = 2.02s \) is the time it took for the ball to hit the ground. Solving for \( v \), we find \( v = \frac{40}{2.02} = 19.8m/s \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Velocity Calculation
The initial velocity of an object in projectile motion is a key factor in determining its trajectory and outcome. Calculating the initial velocity lets us predict where the object will land and analyze its motion. When a ball is thrown horizontally from a certain height, its initial velocity is only in the horizontal direction. This is because there is no initial vertical component of velocity in purely horizontal projection; gravity acts vertically downward to pull the object toward the ground. For the problem at hand, to calculate the initial velocity, we first determine how long the object takes to fall to the ground. This is done by using the formula for vertical motion: \[ h = \frac{1}{2} g t^2 \] Here, \( h \) is the vertical height (20 meters), \( g \) is the acceleration due to gravity (9.8 \( m/s^2 \)), and \( t \) is the time taken to reach the ground. We rearrange this formula to solve for \( t \), which gives the time duration for the vertical fall, independent of the horizontal motion.Once the time \( t \) is known, we use it to compute the initial horizontal velocity \( v \) using the formula: \[ v = \frac{d}{t} \] where \( d \) is the horizontal distance traveled (40 meters). This gives a precise value for the initial velocity needed to reach the specified horizontal distance.
Horizontal Motion
Horizontal motion refers to the movement of an object along the horizontal axis. In projectile motion, horizontal motion becomes quite simple because the only force acting on the object is gravity, and it acts in the vertical direction, not affecting horizontal velocity. Thus, the horizontal velocity remains constant throughout the motion, assuming air resistance is negligible. For the problem involving the ball, the horizontal motion lasts the entire duration from launch to landing due to the only changing factor – the constant gravitational pull along the vertical. This constant horizontal velocity results in the ball covering a specific distance during its time in the air. Key points to understand horizontal motion:
  • The horizontal velocity remains constant if air resistance is ignored.
  • The horizontal distance covered by the object is reliant upon both the time in the air and the initial horizontal velocity.
The scenario of throwing a ball horizontally from an elevated point illustrates horizontal motion effectively, focusing purely on travel along a straight, flat path.
Equations of Motion
Equations of motion describe the behavior of moving objects. For projectile motion, they are crucial in determining various parameters like time of flight, range, and velocity components. These equations simplify the problem-solving process for different types of motion, such as vertical free-fall or horizontal launch in the context of our problem.In this specific problem, two main equations of motion are used:
  • The vertical motion equation \( h = \frac{1}{2} g t^2 \) helps calculate the time it takes for the object to fall from its initial height to the ground.
  • The horizontal motion equation \( v = \frac{d}{t} \) is used once the time \( t \) is ascertained to find the horizontal velocity \( v \), required for covering the horizontal distance \( d \).
These vector components for motion—vertical and horizontal—are handled separately, and their combined analysis gives the complete picture of projectile trajectory.By applying the equations step-by-step, not only do we solve for unknown values, but we also gain a deeper understanding of how initial conditions affect the entire motion. This forms the foundation for analyzing more complex motion scenarios.

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