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Question: (II) There is an electric field near the Earth’s surface whose magnitude is about \({\bf{150}}\;{\bf{V/m}}\). How much energy is stored per cubic meter in this field?

Short Answer

Expert verified

The energy stored per cubic meter in the field is \(1.0 \times {10^{ - 7}}\;{\rm{J/}}{{\rm{m}}^{\rm{3}}}\).

Step by step solution

01

Understanding the energy density

The energy density is defined as the energy per unit volume. For an electric field, it depends only on the magnitude of electric field strength.

The energy density in an electric field is given as:

\(u = \frac{1}{2}{\varepsilon _0}{E^2}\) … (i)

Here,\({\varepsilon _0}\)is the permittivity of free space and E is the electric field strength.

02

Given data

The electric field strength is, \(E = 150\;{\rm{V/m}}\)

03

Determination of the energy stored per cubic meter

The energy stored per cubic meter in the field is calculated as:

\(\begin{aligned}{c}U &= \frac{1}{2}{\varepsilon _0}{E^2}\\ &= \frac{1}{2}\left( {8.854 \times {{10}^{ - 12}}\;{{\rm{C}}^{\rm{2}}}{\rm{/N}} \cdot {{\rm{m}}^{\rm{2}}}} \right){\left( {150\;{\rm{V/m}}} \right)^2}\\ &= 9.96 \times {10^{ - 8}}\;{\rm{J/}}{{\rm{m}}^{\rm{3}}}\\ \approx 1.0 \times {10^{ - 7}}\;{\rm{J/}}{{\rm{m}}^{\rm{3}}}\end{aligned}\)

Thus, the energy stored per cubic meter in the field is \(1.0 \times {10^{ - 7}}\;{\rm{J/}}{{\rm{m}}^{\rm{3}}}\).

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