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Magazine Chapter 6: Q38P (page 138)
Question: (I) The total electric flux from a cubical box of side 28.0 cm is
.What charge is enclosed by the box?
Short Answer
The charge enclosed by the box is \(1.64 \times {10^{ - 8}}\;{\rm{C}}\).
Step by step solution
Determination of the enclosed charge value
The value of the enclosed charge can be calculated by multiplying the value of the electric flux with the value of the permittivity of free space.
Given information
Given data:
The length of the side of a cubical box is \(a = 28.0\;{\rm{cm}}\).
The total electric flux is
Evaluation of the charge enclosed by the box
The charge enclosed by the box can be calculated using the following expression:
\({Q_{{\rm{Enclosed}}}} = {\phi _{\rm{E}}}{\varepsilon _{\rm{o}}}\)
Here, \({\varepsilon _{\rm{o}}}\) is the permittivity of free space, and its value is 
Substitute the values in the above equation.
Thus, the charge enclosed by the box is \(1.64 \times {10^{ - 8}}\;{\rm{C}}\).
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