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Question: (II)Show that for a mixture of two gases at the same temperature, the ratio of their rms speeds is equal to the inverse ratio of the square roots of their molecular masses,\(\frac{{{{\bf{v}}_{\bf{1}}}}}{{{{\bf{v}}_{\bf{2}}}}}{\bf{ = }}\sqrt {\frac{{{{\bf{M}}_{\bf{2}}}}}{{{{\bf{M}}_{\bf{1}}}}}} \).

Short Answer

Expert verified

It is proved that the ratio of rms speeds is equal to the inverse ratio of the square root of their molecular masses; that is, \(\frac{{{v_1}}}{{{v_2}}} = \sqrt {\frac{{{M_2}}}{{{M_1}}}} \).

Step by step solution

01

Understanding the rms speed of gas molecules

The square root of the average of the squares of the speeds ofmoleculesis known as root-mean-square speed.

The root-mean-square speed is given as follows:

\({v_{{\rm{rms}}}} = \sqrt {\frac{{3RT}}{M}} \) … (i)

Here, R is the universal gas constant, T is the temperature, and M is the molecular mass.

02

Evaluation of the relation between rms speed and molecular mass

The rms speed is directly proportional to the square root of temperature and inversely proportional to the square root of molecular mass.

\(v \propto \sqrt {\frac{T}{M}} \)

Since the temperature is the same for both the gas molecules,

\(\begin{aligned}{c}\frac{{{v_{\rm{1}}}}}{{{v_2}}} &= \frac{{\sqrt {\frac{T}{{{M_1}}}} }}{{\sqrt {\frac{T}{{{M_2}}}} }}\\\frac{{{v_{\rm{1}}}}}{{{v_2}}} &= \sqrt {\frac{{{M_2}}}{{{M_1}}}} \end{aligned}\)

Thus, it is proved that the ratio of rms speeds is equal to the inverse ratio of the square root of their molecular masses, \(\frac{{{v_1}}}{{{v_2}}} = \sqrt {\frac{{{M_2}}}{{{M_1}}}} \).

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Most popular questions from this chapter

The escape speed from the Earth is \({\bf{1}}{\bf{.12 \times 1}}{{\bf{0}}^{\bf{4}}}\;{\bf{m/s}}\),that is, a gas molecule traveling away from Earth near the outer boundary of the Earth’s atmosphere would, at this speed, be able to escape from the Earth’s gravitational field and be lost in the atmosphere. At what temperature is the RMS speed of (a) oxygen molecules and (b) helium atoms equal to \({\bf{1}}{\bf{.12 \times 1}}{{\bf{0}}^{\bf{4}}}\;{\bf{m/s}}\)? (c) Can you explain why our atmosphere contains oxygen but not helium?

Question 17: Escape velocity from the Earth refers to the minimum speed an object must have to leave the Earth and never return. (a) The escape velocity from the Moon is about one-fifth what it is for the Earth, due to the Moon’s smaller mass. Explain why the Moon has practically no atmosphere. (b) If hydrogen was once in the Earth’s atmosphere, why would it have probably escaped?

(II) In an alcohol-in-glass thermometer, the alcohol column has length 12.61 cm at 0.0°C and length 22.79 cm at 100.0°C. What is the temperature if the column has length (a) 18.70 cm, and (b) 14.60 cm?

A precise steel tape measure has been calibrated at 14°C. At 37°C, (a) will it read high or low, and (b) what will be the percentage error?

Question: (II)Show that the rms speed of molecules in a gas is given by\({{\bf{v}}_{{\bf{rms}}}}{\bf{ = }}\sqrt {{\bf{3P/\rho }}} \)where P is the pressure in the gas and\({\bf{\rho }}\)is the gas density.

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