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A woman is balancing on a high wire, which is tightly strung, as shown in Fig. 9鈥45. The tension in the wire is

(a) about half the woman鈥檚 weight.

(b) about twice the woman鈥檚 weight.

(c) about equal to the woman鈥檚 weight.

(d) much less than the woman鈥檚 weight.

(e) much more than the woman鈥檚 weight.

Short Answer

Expert verified

The correct option is (e).

Step by step solution

01

Concepts

At equilibrium, the net force is zero. For this problem, find the condition for vertical forces.

02

Explanation

Let m be the mass of the woman and T be the tension in the wire.

At equilibrium for the vertical forces,

\(\begin{aligned}{c}T\sin \theta + T\sin \theta = mg\\2T\sin \theta = mg\\\sin \theta = \frac{{mg}}{{2T}}\end{aligned}\).

You can observe that the angle of the rope with the horizontal is very small and less than \({30^ \circ }\). Then,

\(\begin{aligned}{c}\sin \theta < \sin {30^ \circ }\\\frac{{mg}}{{2T}} < \frac{1}{2}\\T > mg\end{aligned}\).

Therefore, the tension in the wire is more than the woman鈥檚 weight.

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