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Chapter 12: Q32P (page 328)

Question: (II) Estimate the frequency of the 鈥渟ound of the ocean鈥� when you put your ear very near a 15-cm-diameter seashell (Fig. 12鈥�35).

Short Answer

Expert verified

The fundamental frequency of the seashell is \(576.6{\rm{ Hz}}\).

Step by step solution

01

Step-1:-Fundamental frequency of the seashell

Consider seashell as a closed tube. The frequency of a closed tube is the division of wave speed by wavelength.

02

Step-2:-Given data

The diameter of the seashell is \(l = 15{\rm{ cm}}\).

03

Step-3:-Calculation of fundamental frequency of the seashell

The fundamental frequency is calculated as;

\({f_1} = \frac{v}{{4l}}\)

Substitute the values in the above relation.

\(\begin{array}{c}{f_1} = \frac{{346{\rm{ m/s}}}}{{4 \times \left( {15\;{\rm{cm}}\left( {\frac{{1\;{\rm{m}}}}{{100\;{\rm{cm}}}}} \right)} \right)}}\\ = 576.6{\rm{ Hz}}\end{array}\)

The fundamental frequency of the sound of ocean from the seashell is \(576.6{\rm{ Hz}}\).

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Explain how a tube might be used as a filter to reduce the amplitude of sounds in various frequency ranges. (An example is a car muffler.)

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