/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 30P Determine the moment of inertia ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the moment of inertia of a 10.8-kg sphere of radius 0.648 m when the axis of rotation is through its center.

Short Answer

Expert verified

The moment of inertia of the solid sphere rotating about an axis through its centre is \(1.81\;{\rm{kg}}\;{{\rm{m}}^2}\).

Step by step solution

01

Identification of the given data

The mass of the sphere is \(m = 10.8\;{\rm{kg}}\).

The radius of the sphere is \(r = 0.648\;{\rm{m}}\).

02

Definition of the moment of inertia

A moment of inertia is a quantity that expresses a body’s tendency to resist angular acceleration about an axis of rotation.

It is given as the product of the mass of the rigid body and the square of the distance from the axis of rotation.

\(I = m{r^2}\)

03

Determination of the moment of inertia of the solid sphere

As the sphere rotates about the axis of rotation passing through its center, the moment of inertia is given as follows:

\(\begin{align}I &= \frac{2}{5}m{r^2}\\ &= \frac{2}{5}\left( {10.8\;{\rm{kg}}} \right){\left( {0.648\;{\rm{m}}} \right)^2}\\ &= 1.81\;{\rm{kg}}\;{{\rm{m}}^2}\end{align}\)

Thus, the moment of inertia of the solid sphere is \(1.81\;{\rm{kg}}\;{{\rm{m}}^2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A yo-yo is made of two solid cylindrical disks, each of mass 0.050 kg and diameter 0.075 m, joined by a (concentric) thin solid cylindrical hub of mass 0.0050 kg and diameter 0.013 m. Use conservation of energy to calculate the linear speed of the yo-yo just before it reaches the end of its 1.0-m-long string, if it is released from rest. (b) What fraction of its kinetic energy is rotational?

Two wheels having the same radius and mass rotate at the same angular velocity (Fig. 8–38). One wheel is made with spokes so nearly all the mass is at the rim. The other is a solid disk. How do their rotational kinetic energies compare?

(a) They are nearly the same.

(b) The wheel with spokes has about twice the KE.

(c) The wheel with spokes has higher KE, but not twice as high.

(d) The solid wheel has about twice the KE.

(e) The solid wheel has higher KE, but not twice as high.

FIGURE 8-38

MisConceptual Question 7.

To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets, as shown in Fig. 8–50. Suppose that the satellite has a mass of 3600 kg and a radius of 4.0 m and that the rockets each add a mass of 250 kg. What is the steady force required of each rocket if the satellite is to reach 32 rpm in 5.0 min, starting from rest?

FIGURE 8-50

Problem 45

A person exerts a horizontal force of 42 N on the end of a door 96 cm wide. What is the magnitude of the torque if the force is exerted (a) perpendicular to the door and (b) at a 60.0° angle to the face of the door?

A child rolls a ball on a level floor 3.5 m to another child. If the ball makes 12.0 revolutions, what is its diameter?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.