/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 8-8MCQ If you used 1000 J of energy to ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 8: 8-8MCQ (page 198)

If you used 1000 J of energy to throw a ball, would it travel faster if you threw the ball (ignoring air resistance)

(a) so that it was also rotating?

(b) so that it wasn't rotating?

(c) It makes no difference.

Short Answer

Expert verified

The correct option is (b).

Step by step solution

01

Rotational kinetic energy

The total kinetic energy is equal to the sum of rotational kinetic energy and translational kinetic energy.For this problem, you need a greater linear speed, i.e., the translational kinetic energy is large.

You use 1000 J energy to throw the ball.

02

Explanation

When you use 1000 J energy to throw a ball, the ball's total kinetic energy just after the throw is 1000 J. The ball travels faster, which means it has a greater linear kinetic energy.

For a greater linear speed, the translation energy of the ball is large, and the rotational kinetic energy is the minimum. Now, the minimum values should be zero when the ball is not rotating. Therefore, for the highest translational speed of the ball, it should not rotate.

Hence, option (b) is correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A yo-yo is made of two solid cylindrical disks, each of mass 0.050 kg and diameter 0.075 m, joined by a (concentric) thin solid cylindrical hub of mass 0.0050 kg and diameter 0.013 m. Use conservation of energy to calculate the linear speed of the yo-yo just before it reaches the end of its 1.0-m-long string, if it is released from rest. (b) What fraction of its kinetic energy is rotational?

A wheel 31 cm in diameter accelerates uniformly from 240 rpm to 360 rpm in 6.8 s. How far will a point on the edge of the wheel have traveled in this time?

The forearm in Fig. 8鈥�46 accelerates a 3.6-kg ball at \({\bf{7}}{\bf{.0}}\;{\bf{m/}}{{\bf{s}}^{\bf{2}}}\) by means of the triceps muscle, as shown. Calculate (a) the torque needed and (b) the force that must be exerted by the triceps muscle. Ignore the mass of the arm.

FIGURE 8-46

Problems 35 and 36

A large spool of rope rolls on the ground with the end of the rope lying on the top edge of the spool. A person grabs the end of the rope and walks a distance l, holding onto it, Fig. 8鈥�64. The spool rolls behind the person without slipping. What length of rope unwinds from the spool? How far does the spool鈥檚 center of mass move?

A sphere of radius\(r = {\bf{34}}{\bf{.5 cm}}\)and mass\(m = 1.80 kg\)starts from rest and rolls without slipping down a 30.0掳 incline that is 10.0 m long. (a) Calculate its translational and rotational speeds when it reaches the bottom. (b) What is the ratio of translational to rotational kinetic energy at the bottom? Avoid putting in numbers until the end so you can answer: (c) do your answers in (a) and (b) depend on the radius of the sphere or its mass?
See all solutions

Recommended explanations on Physics Textbooks

Translational Dynamics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Solid State Physics

Read Explanation

Engineering Physics

Read Explanation

Scientific Method Physics

Read Explanation

Torque and Rotational Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.