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Can a small force ever exert a greater torque than a larger force? Explain.

Short Answer

Expert verified

It is true that asmall force can exert a greater torque than a larger force if the perpendicular distance is large enough for the smaller force.

Step by step solution

01

Understanding the application of force on the lever arm

Consider the application of force on the lever arm. The lever arm distance is large. Apply the force on the lever arm.The torque that acts on the lever arm is the product of lever arm distance (perpendicular distance) and the force applied on the lever arm.

The value of torque is more when the distance or length of the lever arm is more, and the value of force acting on the lever is less and vice versa.

Consider a wrench which can be represented as:

02

Determination of the torque due to a larger force

Consider that a force\(\left( F \right)\)of 10 N acts on the lever arm having a distance\(\left( r \right)\)of 2 m.

The torque acting on the lever arm can be expressed as:

\(T = F \times r\)

Substitute the values in the above equation.

\(T = 10{\rm{ N}} \times 2{\rm{ m}}\)

\(T = 20{\rm{ N}} \cdot {\rm{m}}\) … (i)

Thus, the torque due to a large force and a small lever distance is\(20{\rm{ N}} \cdot {\rm{m}}\).

03

Determination of the torque due to a smaller force

Consider that a force\(\left( F \right)\)of 5 N acts on the lever arm having a distance\(\left( r \right)\)of 5 m.

The torque acting on the lever arm can be expressed as:

\(T = F \times r\)

Substitute the values in the above equation.

\(T = 5{\rm{ N}} \times 5{\rm{ m}}\)

\(T = 25{\rm{ N}} \cdot {\rm{m}}\) … (ii)

Thus, the torque due to a small force and a large lever distance is\(25{\rm{ N}} \cdot {\rm{m}}\).

From equations (i) and (ii), it is clear that the torque due to a small force and a large lever distance is greater than the torque due to a large force and a small lever distance.

Thus, it is true that a small force can exert a greater torque than a larger force if the perpendicular distance is large enough for the smaller force.

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Most popular questions from this chapter

A potter is shaping a bowl on a potter's wheel rotating at a constant angular velocity of 1.6 rev/s (Fig. 8–48). The frictional force between her hands and the clay is 1.5 N. (a) How large is her torque on the wheel if the diameter of the bowl is 9.0 cm? (b) How long would it take for the potter's wheel to stop if the only torque acting on it is due to the potter's hands? The moment of inertia of the wheel and the bowl is \(0.11\;{\rm{kg}} \cdot {{\rm{m}}^{\rm{2}}}\).

FIGURE 8-48

Problem 40

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