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Chapter 11: Q13P (page 292)

Express the following using the prefixes of Table 1鈥�4:

(a) \({\bf{1 \times 1}}{{\bf{0}}^{\bf{6}}}\;{\bf{volts}}\)

(b) \({\bf{2 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}\;{\bf{meters}}\)

(c) \({\bf{6 \times 1}}{{\bf{0}}^{\bf{3}}}\;{\bf{days}}\)

(d) \({\bf{18 \times 1}}{{\bf{0}}^{\bf{2}}}\;{\bf{bucks}}\)

(e) \({\bf{7 \times 1}}{{\bf{0}}^{{\bf{ - 7}}}}\;{\bf{seconds}}\)

Short Answer

Expert verified

The resultant expressions of the given values using prefixes for parts (a), (b), (c), (d), and (e) are \(1\;{\rm{megavolt}}\), \(2\;{\rm{micrometers}}\), \(6\;{\rm{kilodays}}\), \(18\;{\rm{hectobucks}}\), and \(0.7\;{\rm{microseconds}}\), respectively.

Step by step solution

01

Use of Prefixes 

Prefixes

Prefixes are added at the beginning of words to modify their meaning. In the word unhappy, 鈥渦n鈥� is the prefix, and 鈥渞e鈥� is the prefix in the word rewrite.

To express the given value using a prefix, use Table 1鈥�4.

\(\begin{aligned}{l}V = \left( {1 \times {{10}^6}\;{\rm{volts}} \times \frac{{1\;{\rm{megavolt}}}}{{{{10}^6}\;{\rm{volts}}}}} \right)\\ = 1\;{\rm{megavolt}}{\rm{.}}\end{aligned}\)

02

Metric (SI) prefixes 

To express the given value using a prefix, use Table 1鈥�4.

\(\begin{aligned}{l}d = \left( {2 \times {{10}^{ - 6}}\;{\rm{meters}} \times \frac{{1\;{\rm{micrometer}}}}{{{{10}^{ - 6}}\;{\rm{meters}}}}} \right)\\ = 2\;{\rm{micrometers}}{\rm{.}}\end{aligned}\)

03

SI prefixes

To express the given value using a prefix, use Table 1鈥�4.

\(\begin{aligned}{l}t = \left( {6 \times {{10}^3}\;{\rm{days}} \times \frac{{1\;{\rm{kiloday}}}}{{{{10}^3}\;{\rm{days}}}}} \right)\\ = 6\;{\rm{kilodays}}{\rm{.}}\end{aligned}\)

04

Metric prefixes

To express the given value using a prefix, use Table 1鈥�4.

\(\begin{aligned}{l}n = \left( {18 \times {{10}^2}\;{\rm{bucks}} \times \frac{{1\;{\rm{hectobuck}}}}{{{{10}^2}\;{\rm{bucks}}}}} \right)\\ = 18\;{\rm{hectobucks}}\end{aligned}\)

05

Applications of Prefixes 

To express the given value using a prefix, use Table 1鈥�4.

\(\begin{aligned}{l}t = 7 \times {10^{ - 7}}\;{\rm{seconds}}\\ = \left( {0.7 \times {{10}^{ - 6}}\;{\rm{seconds}} \times \frac{{1\;{\rm{microsecond}}}}{{{{10}^{ - 6}}\;{\rm{seconds}}}}} \right)\\ = 0.7\;{\rm{microseconds}}{\rm{.}}\end{aligned}\)

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