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Chapter 7: Q1P (page 170)

(I) What is the magnitude of the momentum of a 28-g sparrow flying with a speed of 8.4 m/s?

Short Answer

Expert verified

The magnitude of the momentum of the sparrow is \(0.24\;{\rm{kg}} \cdot {\rm{m/s}}\;\).

Step by step solution

01

Momentum

The magnitude of the momentum of any object is equal to the product of the mass and the speed of the object.

02

Given data

The mass of the sparrow is \(m = 28\;{\rm{g}} = 0.028\;{\rm{kg}}\).

The speed of the sparrow is \(v = 8.4\;{\rm{m/s}}\).

03

Calculation of the magnitude of the momentum

The magnitude of the momentum of the sparrow is calculated below.

\(\begin{array}{c}P = mv\\ = \left( {0.028\;{\rm{kg}}} \right) \times \left( {8.4\;{\rm{m/s}}} \right)\\ = 0.24\;{\rm{kg}} \cdot {\rm{m/s}}\;\end{array}\)

Hence, the magnitude of the momentum of the sparrow is \(0.24\;{\rm{kg}} \cdot {\rm{m/s}}\;\).

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Most popular questions from this chapter

Car A hits car B (initially at rest and of equal mass) from behind while going\(38\;{\rm{m/s}}\). Immediately after the collision, car B moves forward at\(15\;{\rm{m/s}}\)and car A is at rest. What fraction of the initial kinetic energy is lost in the collision?

You drop a 14-g ball from a height of 1.5 m and it only bounces back to a height of 0.85 m. What was the total impulse on the ball when it hit the floor? (Ignore air resistance.)

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FIGURE 7-39

Problem 53.

(a) Calculate the impulse experienced when a 55-kg person lands on firm ground after jumping from a height of 2.8 m.

(b) Estimate the average force exerted on the person鈥檚 feet by the ground if the landing is stiff-legged, and again

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FIGURE 7-34 Problem 24.
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