91影视

The resultant of collinear vectors is given by the algebraic sum of individual vectors with signs.

Magnitude of vector $\stackrel{鈫�}{A}$, A = 6.8 units

Magnitude of vector $\stackrel{鈫�}{B}$, B = 5.5 units

Let the magnitude of $\stackrel{鈫�}{C}$be represented by C.

The magnitude of vector $\stackrel{鈫�}{C}$is given by the sum of vectors $\stackrel{鈫�}{A}$and $\stackrel{鈫�}{B}$, with signs.

$\begin{array}{c}\stackrel{鈫�}{C}=\stackrel{鈫�}{A}+\stackrel{鈫�}{B}\\ =6.8\hat{i}+5.5\left(-\hat{i}\right)\\ =1.3\hat{i}\mathrm{units}\end{array}$

The magnitude of $\stackrel{鈫�}{C}$is given as follows:

$\begin{array}{c}\left|\stackrel{鈫�}{C}\right|=\left|1.3\hat{i}\right|\\ C=1.3\mathrm{units}\end{array}$

Thus, the magnitude of $\stackrel{鈫�}{C}$is 1.3 units, and the direction is along the +ve X-axis (as the sign is positive).

The magnitude of vector $\stackrel{鈫�}{C}$is given by the sum of vectors $\stackrel{鈫�}{A}$and $\stackrel{鈫�}{B}$, with signs.

$\begin{array}{c}\stackrel{鈫�}{C}=\stackrel{鈫�}{A}-\stackrel{鈫�}{B}\\ =6.8\hat{i}-5.5\left(-\hat{i}\right)\\ =12.3\hat{i}\mathrm{units}\end{array}$

The magnitude of $\stackrel{鈫�}{C}$is given as follows:

$\begin{array}{c}\left|\stackrel{鈫�}{C}\right|=\left|12.3\hat{i}\right|\\ C=12.3\mathrm{units}\end{array}$

Thus, the magnitude of $\stackrel{鈫�}{C}$is 12.3 units, and the direction is along the +ve X-axis (as the sign is positive).

The magnitude of vector $\stackrel{鈫�}{C}$is given by the sum of vectors $\stackrel{鈫�}{A}$and $\stackrel{鈫�}{B}$, with signs.

$\begin{array}{c}\stackrel{鈫�}{C}=\stackrel{鈫�}{B}-\stackrel{鈫�}{A}\\ =5.5\left(-\hat{i}\right)-6.8\hat{i}\\ =12.3\left(-\hat{i}\right)\mathrm{units}\end{array}$

The magnitude of $\stackrel{鈫�}{C}$is given as follows:

$\begin{array}{c}\left|\stackrel{鈫�}{C}\right|=\left|12.3\left(-\hat{i}\right)\right|\\ C=12.3\mathrm{units}\end{array}$

Thus, the magnitude of $\stackrel{鈫�}{C}$is 12.3 units, and the direction is along the 鈥搗e X-axis (as the sign is negative).