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Metabolism implies blood circulation in a body. It provides cooling by convection. If metabolism were nearly to stop, the heat loss would occur by conduction or radiation.

The rate of heat loss from the human body is\(\frac{Q}{t} = 200\;{\rm{W}}\)

The initial temperature is\({T_{\rm{i}}} = 36.6^\circ {\rm{C}}\).

The final temperature is\({T_{\rm{f}}} = 35.6^\circ {\rm{C}}\).

The mass is \(m = 65\;{\rm{kg}}\)

The relation to find the time is given by:

\(\begin{aligned}{c}\frac{Q}{t} = \left( {\frac{{mc\Delta T}}{t}} \right)\\P = \left( {\frac{{mc\left( {{T_{\rm{i}}} - {T_{\rm{f}}}} \right)}}{t}} \right)\end{aligned}\)

Here,\(t\)is the time and cis the specific heat whose value is obtained from Table 14-1, which is\(3470\;{\rm{J/kg}} \cdot ^\circ {\rm{C}}\).

Substitute the values in the above expression.

\(\begin{aligned}{c}200\;{\rm{W}} = \left( {\frac{{\left( {65\;{\rm{kg}}} \right)\left( {3470\;{\rm{J/kg}} \cdot ^\circ {\rm{C}}} \right)\left( {36.6^\circ {\rm{C}} - 35.6^\circ {\rm{C}}} \right)}}{t}} \right)\\t = 1127.75\;{\rm{s}}\end{aligned}\)

Thus, the time taken for the body temperature to drop is\(1127.75\;{\rm{s}}\).