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(II) Heat conduction to skin. Suppose 150 W of heat flows by conduction from the blood capillaries beneath the skin to the body’s surface area of \({\bf{1}}{\bf{.5}}\;{{\bf{m}}^{\bf{2}}}\). If the temperature difference is 0.50 C°, estimate the average distance of capillaries below the skin surface.

Short Answer

Expert verified

The average distance of capillaries below the skin surface is \(1.0 \times {10^{ - 3}}\;{\rm{m}}\).

Step by step solution

01

Understanding of the conduction process

The conduction heat transfer process may be defined as the transfer of heat energy by direct contact between two objects. It can also occur within one object.

02

Given data

The rate of heat flow is \(\frac{Q}{t} = 150\;{\rm{W}}\).

The surface area of the body is \(A = 1.5\;{{\rm{m}}^{\rm{2}}}\).

The difference in the temperatures is \(\Delta T = 0.50{\rm{^\circ C}}\).

From table 14-4:

The thermal conductivity of the human body is \(k = 0.2\;{{\rm{J}} \mathord{\left/{\vphantom {{\rm{J}} {{\rm{s}} \cdot {\rm{m}} \cdot {\rm{^\circ C}}}}} \right.\\} {{\rm{s}} \cdot {\rm{m}} \cdot {\rm{^\circ C}}}}\).

03

Evaluation of the average distance of capillaries below the skin surface

The expression for the heat conduction rate is given as:

\(\frac{Q}{t} = \frac{{kA\Delta T}}{l}\)

Rewrite the above equation as:

\(l = \frac{{kA\Delta T}}{{\left( {\frac{Q}{t}} \right)}}\)

Substitute the values in the above equation.

\(\begin{array}{c}l = \frac{{\left( {0.2\;{{\rm{J}} \mathord{\left/{\vphantom {{\rm{J}} {{\rm{s}} \cdot {\rm{m}} \cdot {\rm{^\circ C}}}}} \right.\\} {{\rm{s}} \cdot {\rm{m}} \cdot {\rm{^\circ C}}}}} \right)\left( {1.5\;{{\rm{m}}^{\rm{2}}}} \right)\left( {0.50{\rm{^\circ C}}} \right)}}{{\left( {150\;{\rm{W}}} \right)}}\\ = 1.0 \times {10^{ - 3}}\;{\rm{m}}\end{array}\)

Thus, the average distance of capillaries below the skin surface is \(1.0 \times {10^{ - 3}}\;{\rm{m}}\).

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Most popular questions from this chapter

A piece of wood lying in the Sun absorbs more heat than a piece of shiny metal. Yet the metal feels hotter than the wood when you pick it up. Explain.

(II) Determine the latent heat of fusion of mercury using the following calorimeter data: 1.00 kg of solid Hg at its melting point of \({\bf{ - 39}}{\bf{.0\circ C}}\) is placed in a 0.620-kg aluminum calorimeter with 0.400 kg of water at 12.80°C; the resulting equilibrium temperature is 5.06°C.

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When you put an ice cube in a glass of warm tea, which of the following happens?

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(b) Cold flows from the ice cube into the tea and heat flows from the tea into the ice cube.

(c) Heat flows from the tea into the ice cube.

(d) Neither heat nor cold flows. Only temperature flows between the ice and the tea.

Estimate the rate at which heat can be conducted from the interior of the body to the surface. As a model, assume that the thickness of tissue is 4.0 cm, that the skin is at 34°C and the interior at 37°C, and that the surface area \({\bf{1}}{\bf{.5}}\;{{\bf{m}}{\bf{2}}}\) is Compare this to the measured value of about 230 W that must be dissipated by a person working lightly. This clearly shows the necessity of convective cooling by the blood.

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