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(II) A person scuffing her feet on a wool rug on a dry day accumulates a net charge of\( - {\bf{28}}\;{\bf{\mu C}}\). How many excess electrons does she get, and by how much does her mass increase?

Short Answer

Expert verified

The number of excess electrons is \(1.75 \times {10^{14}}\) and the mass of the person is increased by \(1.59 \times {10^{ - 16}}\;{\rm{kg}}\).

Step by step solution

01

Understanding the electric charge

Electric charge is a basic property of matter that causes small objects to attract or repel each other. The charge is quantised in nature and the electronic charge is the basic unit of charge.

The net quantity of charge is given as:

\(Q = ne\) … (i)

Here, n is the number of electrons and e is the electronic charge.

02

Given Data

The net charge accumulated by the person is, \(Q = - 28\;{\rm{\mu C}}\).

The charge on an electron is, \(e = 1.6 \times {10^{ - 19}}\;{\rm{C}}\)

03

Determination of the number of excess electrons

From equation (i), the number of excess electrons is,

\(n = \frac{q}{e}\)

Substitute the values in the above expression.

\(\begin{aligned}{l}n = \frac{{ - 28 \times {{10}^{ - 6}}\;{\rm{C}}}}{{ - 1.6 \times {{10}^{ - 19}}\;{\rm{C}}}}\\n = 1.75 \times {10^{14}}\end{aligned}\)

Thus, the number of excess electrons is \(1.75 \times {10^{14}}\).

04

Determination of the increase in mass

The expression to find the increase in mass is given as:

\(\Delta m = n \times {m_e}\)

Here, \({m_e}\)is the mass of the electron.

Substitute the values in the above expression.

\(\begin{aligned}{l}\Delta m = \left( {1.75 \times {{10}^{14}}} \right) \times \left( {9.1 \times {{10}^{ - 31}}\;{\rm{kg}}} \right)\\\Delta m = 1.59 \times {10^{ - 16}}\;{\rm{kg}}\end{aligned}\)

Thus, the mass of the person is increased by \(1.59 \times {10^{ - 16}}\;{\rm{kg}}\).

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Most popular questions from this chapter

Question:Two point charges,\({Q_1} = - 6.7{\rm{ }}\mu {\bf{C}}\) and\({Q_2} = {\bf{1}}{\bf{.8 }}\mu {\bf{C}}\)are located between two oppositely charged parallel plates, as shown in Fig. 16–65. The two charges are separated by a distance of \(x = 0.47 m\). Assume that the electric field produced by the charged plates is uniform and equal to\(E = 53,000 N/C\). Calculate the net electrostatic force on\({Q_1}\) and give its direction.

FIGURE 16–65 Problem 55.

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