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Chapter 16: Q6MCQ (page 443)

As an object acquires a positive charge, its mass usually

(a) decreases.

(b) increases.

(c) stays the same.

(d) becomes negative.

Short Answer

Expert verified

The correct answer is option (a) decreases

Step by step solution

01

Meaning of positively and negatively charged object

An object is supposed to be negatively charged if one electron is added, and positively charged when one electron is removed from its outer shell.

02

Explanation for the given options

If an electron is attached to the object, the object obtains a negative charge. The mass of the object adds the electron and thus the mass of the object increases.

Suppose an object acquires a positive charge; it loses electrons. So, the mass of the object does not remain the same. The mass of an object cannot be negative.

When electrons are removed from an object, it becomes positively charged. Since electrons have mass, as they are eliminated from the object, the mass of the object reduces.

Hence, the correct option (a).

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Most popular questions from this chapter

(II) What is the electric field strength at a point in space where a proton experiences an acceleration of 2.4 million 鈥�g鈥檚鈥�?

Question: (II) In Fig. 16鈥�62, two objects, \({{\bf{O}}_{\bf{1}}}\) and \({{\bf{O}}_{\bf{2}}}\) have charges \({\bf{ + 1}}{\bf{.0}}\;{\bf{\mu C}}\) and \({\bf{ - 2}}{\bf{.0}}\;{\bf{\mu C}}\), respectively, and a third object, \({{\bf{O}}_{\bf{3}}}\), is electrically neutral. (a) What is the electric flux through the surface \({A_1}\) that encloses all three objects? (b) What is the electric flux through the surface \({A_2}\) that encloses the third object only?

FIGURE 16鈥�62 Problem 39.

Given two point charges, Q and 2Q, a distance \(l\) apart, is there a point along the straight line that passes through them where \(E = 0\) when their signs are (a) opposite, (b) the same? If yes, state roughly where this point will be.

We wish to determine the electric field at a point near a positively charged metal sphere (a good conductor). We do so by bringing a small positive test charge, \({q_{\rm{o}}}\), to this point and measure the force \({F_{\rm{o}}}\) on it. \({{{F_{\rm{o}}}} \mathord{\left/{\vphantom {{{F_{\rm{o}}}} {{q_{\rm{o}}}}}} \right. \\{{q_{\rm{o}}}}}\) will be ____________ the electric field \({\bf{\vec E}}\) as it was at that point before the test charge was present.

(a) greater than

(b) less than

(c) equal to

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