91影视

A point charge exerts an electric force on another point charge in the vicinity. It could be attractive as well as repulsive depending upon the nature of the two charges.

The expression for the electric force is given as:

\(F = k\frac{{{Q_1}{Q_2}}}{{{r^2}}}\) 鈥� (i)

Here, k is the Coulomb鈥檚 constant,\({Q_1},\;{Q_2}\)are the charges and r is the separation between the charges.

The first charge is, \({Q_1} = + 25\;{\rm{\mu C}}\)

The second charge is \({Q_2} = 2.5\;{\rm{mC}}\)

The separation between the charges is, \(r = 16\;{\rm{cm}}\)

The expression for the electric force is given as:

\(F = k\frac{{{Q_1}{Q_2}}}{{{r^2}}}\)

Substitute the values in the above expression.

\(\begin{aligned}{l}F = \left( {9.0 \times {{10}^9}\;{\rm{N}} \cdot {{\rm{m}}^2}{\rm{/}}{{\rm{C}}^2}} \right)\frac{{\left( {25 \times {{10}^{ - 6}}\;{\rm{C}}} \right)\left( {2.5 \times {{10}^{ - 3}}\;{\rm{C}}} \right)}}{{{{\left( {16\;{\rm{cm}} \times \frac{{{{10}^{ - 2}}\;{\rm{m}}}}{{1\;{\rm{cm}}}}} \right)}^2}}}\\F = 2.2 \times {10^4}\;{\rm{N}}\end{aligned}\)

Thus, the magnitude of the force exerted is\(2.2 \times {10^4}\;{\rm{N}}\).