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A person stands on a scale in an elevator. His apparent weight will be the greatest when the elevator

(a) is standing still.

(b) is moving upward at a constant velocity.

(c) is accelerating upward.

(d) is moving downward at a constant velocity.

(e) is accelerating downward.

Short Answer

Expert verified

The correct option is (c).

Step by step solution

01

Step 1. Forces on the person

The weight (mg) of the person is downward.

The normal force (N) on the person is upward.

Assumption:

Let m be the mass of the person.

Let a be the constant upward acceleration of the elevator.

02

Step 2. Calculation for the normal force during the upward acceleration of the elevator

The person feels the normal force acting on them. The normal force on the person is the apparent width of the person.

Then, using Newton’s second law of motion,

ma=N-mgN=mg+a

From the above relation, you get N>mgwhen the elevator is moving upward with a constant acceleration.

Hence, the person’s apparent weight will be the greatest when the elevator is accelerating upward.

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