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A helicopter is ascending vertically with a speed of 5.40 m/s. At a height of 105 m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?]

Short Answer

Expert verified

The obtained solution is t=4.108s.

Step by step solution

01

Step 1. Kinematic equations 

Kinematics is one of the subfields of physics that describes the movement of a certain component without considering force.

Given data.

The speed of the helicopter is v=5.40m/s.

The height above the Earth is h=105m.

The relation from the equation of motion is given by.

h=vt+12gt2t2+2vgt-2hg=0

Here, g is the gravitational acceleration, and t is the time.

On plugging the values in the above relation, you get.

t2+25.40m/s-9.81m/s2t-2-105m-9.81m/s2=0t2+1.1t-21.4=0

02

Step 2. Calculation of time

On solving the above equation, you get;

t=-1.1±1.12-41-21.42×1t=4.108 s,-5.208 s

Thus, t=4.108 sis the required time of the helicopter.

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