Q44. The best rebounders in basketbal... [FREE SOLUTION]

Chapter 2: Q44. (page 45)

The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about 120 cm. (a) What is their initial 鈥渓aunch鈥� speed off the ground? (b) How long are they in the air?

Short Answer

Expert verified

The initial launch speed and time for which the basketball is in the air are $u = 4.85 m / s$ and $t_{n} = 0.988 s$ , respectively.

Step by step solution

Step 1. Calculation of initial launch speed

Kinematic analysis can be applied to various machine components for obtaining the velocity as well as acceleration.

Given data.

The vertical leap is about $h = 120 cm$ .

The relation to calculate the initial launch speed is given by.

$u = \sqrt{2 g h}$

On plugging the values in the above relation, you get.

$\begin{matrix} u = \sqrt{2 (9.81 m / s^{2}) (120 cm 脳 \frac{1 m}{100 cm})} \\ u = 4.85 m / s \end{matrix}$

Thus, $u = 4.85 m / s$ is the initial launch speed.

Step 2. Calculation of time

The relation to calculate the time is given by.

$\begin{matrix} v = u - g t \\ t = \frac{v - u}{- g} \end{matrix}$

Here, v is the final speed of the basketball whose value is zero at the maximum height.

On plugging the values in the above relation, you get.

$\begin{matrix} t = [\frac{0 - 4.85 m / s}{- 9.81 m / s^{2}}] \\ t = 0.494 s \end{matrix}$

The net time they are in the air is calculated as.

$\begin{matrix} t_{n} = 2 t \\ t_{n} = 2 (0.494 s) \\ t_{n} = 0.988 s \end{matrix}$

Thus, $t_{n} = 0.988 s$ is the required time.

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91影视

The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about 120 cm. (a) What is their initial 鈥渓aunch鈥� speed off the ground? (b) How long are they in the air?

Short Answer

Step by step solution

Step 1. Calculation of initial launch speed

Step 2. Calculation of time

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