/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q17. The Sun is below us at midnight,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Sun is below us at midnight, nearly in line with the Earth's centre. Are we then heavier at midnight, due to the Sun's gravitational force on us, than we are at noon? Explain.

Short Answer

Expert verified

The weight becomes heavier due to the gravitational force of the Sun and Earth at midnight.

Step by step solution

01

Step1. Understanding the gravitational force of Sun and Earth

The gravitational pull of the Sun is much stronger as compared to the Earth because Sun is heavier. In this problem, the gravitational force of the Sun and Earth will be used to explain the apparent weight at midnight.

02

Step 2. Explaining the reason behind the difference in apparent weight at midnight and noon

During midnight, the Sun is close to the Earth’s centre line, and in this situation, the direction of the gravitational force of Earth and Sun are in the equivalent direction, which makes the weight of the person heavier. On the other hand, the direction of the gravitational force of Earth and the Sun are in different directions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Every few hundred years most of the planets line up on the same side of the Sun. Calculate the total force on the Earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line, Fig. 5–44. The masses aremV=0.815mE,mJ=318mE,mSat=95.1mEand the mean distances of the four planets from the Sun are 108, 150, 778, and 1430 million km. What fraction of the Sun’s force on the Earth is this?

A horizontal force of 310 N is exerted on a 2.0-kg ball as it rotates (at arm’s length) uniformly in a horizontal circle of radius 0.90 m. Calculate the speed of the ball.

The source of the Mississippi River, is closer to the centre of the Earth than is its outlet in Louisiana (because the Earth is fatter at the equator than at the poles). Explain how the Mississippi can flow "uphill."

Our Sun revolves about the center of our Galaxy (\({{\bf{m}}_{\bf{g}}} \approx {\bf{4 \times 1}}{{\bf{0}}^{{\bf{41}}}}{\bf{\;kg}}\)) at a distance \({\bf{3 \times 1}}{{\bf{0}}^{\bf{4}}}\;{\bf{light - year}}\) (\({\bf{1}}\;{\bf{ly = 3 \times 1}}{{\bf{0}}^{\bf{8}}}\;{\bf{m/s \times 3}}{\bf{.16 \times 1}}{{\bf{0}}^{\bf{7}}}\;{\bf{s/yr \times 1}}\;{\bf{yr}}\)). What is the period of the Sun’s orbital motion about the centre of the Galaxy?

A 975-kg sports car (including driver) crosses the rounded top of a hill (radius = 88.0 m) at 18.0 m/s. Determine (a) the normal force exerted by the road on the car, (b) the normal force exerted by the car on the 62.0-kg driver, and (c) the car speed at which the normal force on the driver equals zero.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.