/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 (I) A 0.145-kg baseball pitched ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the contact time between bat and ball is \(5.00 \times 10^{-3}s\), calculate the force (assumed to be constant) between the ball and bat.

Short Answer

Expert verified
The force between the ball and bat is 2233 N, directed opposite the initial motion.

Step by step solution

01

Determine the initial and final velocities

The initial velocity of the baseball is given as \(v_i = 31.0 \text{ m/s}\) towards the pitcher. The final velocity, after being hit, is \(v_f = -46.0 \text{ m/s}\), considering the direction has reversed.
02

Calculate the change in velocity

The change in velocity of the baseball can be calculated using the formula \(\Delta v = v_f - v_i\). Substitute the known values: \(\Delta v = -46.0 \text{ m/s} - 31.0 \text{ m/s} = -77.0 \text{ m/s}\).
03

Calculate the change in momentum

Momentum is given by the product of mass and velocity. The change in momentum \(\Delta p\) is \(\Delta p = m \times \Delta v\), where \(m = 0.145 \text{ kg}\). Substitute the values: \(\Delta p = 0.145 \times -77.0 = -11.165 \text{ kg} \cdot \text{m/s}\).
04

Calculate the average force

Force can be calculated using the formula \(F = \frac{\Delta p}{\Delta t}\), where \(\Delta p\) is the change in momentum and \(\Delta t = 5.00 \times 10^{-3} \text{ s}\). Substitute the values: \(F = \frac{-11.165}{5.00 \times 10^{-3}} = -2233 \text{ N}\). The negative sign indicates the force direction is opposite to the initial motion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity
Velocity is a fundamental concept in physics that describes how fast something is moving and in which direction. It's not just about speed, because velocity also considers direction.
If you imagine a car moving at 31 meters per second towards the north, its velocity is 31 m/s northward. When we talk about direction in physics, it matters a lot! This is why, in the problem provided, the initial velocity of the baseball is 31.0 m/s towards the pitcher, and after it’s hit, the velocity becomes -46.0 m/s, indicating it travels back in the opposite direction.
Understanding velocity helps us predict where something will be over time if it keeps moving at that speed. In this scenario, because of the change in direction after the baseball was hit, its velocity went from positive to negative, which is crucial for calculating the momentum change.
Force
Force is what happens when objects interact. In its simplest terms, force is a push or a pull on an object resulting from its interaction with another object.
Forces make things move or stop moving. In this case, the bat applies a force to the baseball to change its velocity.
The exercise involves calculating the average (constant) force acting on the baseball during the short collision time by the bat. The force that changes the baseball's velocity can be determined using the momentum change and the time of contact. This is given by the formula \[ F = \frac{\Delta p}{\Delta t} \]where
  • \( \Delta p \) is the change in momentum,
  • \( \Delta t \) represents the time duration of contact.
In our problem, the average force came out to be \(-2233 \text{ N}\), the negative sign indicating the force direction is against the initial motion of the ball.
Momentum Change
Momentum is all about motion. It represents the quantity of motion an object has and is calculated by multiplying mass and velocity. When the velocity of an object changes, so does its momentum.
In the baseball scenario, the change in velocity was crucial for finding the change in momentum.
The formula to find the momentum change in this case is:\[ \Delta p = m \times \Delta v \]where
  • \( \Delta p \) is the change in momentum,
  • \( m \) (0.145 kg for the baseball) is the mass, and
  • \( \Delta v \) is the change in velocity, computed as \(-77.0 \text{ m/s}\) in the problem.
This brief alteration in momentum, occurring during the collision with the bat, has measurable consequences: it changes the direction and speed of the baseball, achieving a final momentum value that influences how forces interact. The exercise simplified by assuming the bat-ball interaction had a constant force over a short time span, thus making the calculations straightforward yet insightful.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(II) An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.5 times the mass of the other. If 5500 J is released in the explosion, how much kinetic energy does each piece acquire?

(II) A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the vertical and horizontal components of the pendulum's maximum displacement.

Astronomers estimate that a 2.0-km-diameter asteroid collides with the Earth once every million years. The collision could pose a threat to life on Earth. \((a)\) Assume a spherical asteroid has a mass of 3200 kg for each cubic meter of volume and moves toward the Earth at 15 km/s. How much destructive energy could be released when it embeds itself in the Earth? \((b)\) For comparison, a nuclear bomb could release about \(4.0 \times 10^{16} J\). How many such bombs would have to explode simultaneously to release the destructive energy of the asteroid collision with the Earth?

(III) An atomic nucleus of mass \(m\) traveling with speed \(\upsilon\) collides elastically with a target particle of mass \(2m\) (initially at rest) and is scattered at 90\(^{\circ}\). \((a)\) At what angle does the target particle move after the collision? \((b)\) What are the final speeds of the two particles? \((c)\) What fraction of the initial kinetic energy is transferred to the target particle?

(II) A 144-g baseball moving 28.0 m/s strikes a stationary 5.25-kg brick resting on small rollers so it moves without significant friction. After hitting the brick, the baseball bounces straight back, and the brick moves forward at 1.10 m/s. \((a)\) What is the baseball's speed after the collision? \((b)\) Find the total kinetic energy before and after the collision.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.