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(II) A skier traveling 11.0 m/s reaches the foot of a steady upward 19\(^\circ\) incline and glides 15 m up along this slope before coming to rest. What was the average coefficient of friction?

Short Answer

Expert verified
Average coefficient of friction is approximately 0.090.

Step by step solution

01

Setup the Problem

First, identify what is given and what needs to be found. The skier has an initial speed of \( v_i = 11.0 \, \text{m/s} \) and travels up an incline making an angle of \( \theta = 19^\circ \) until he comes to rest after a distance \( d = 15 \, \text{m} \). We need to find the average coefficient of friction \( \mu \).
02

Write Down Relevant Equations

We know that the work done against gravity and friction will equal the initial kinetic energy. This gives:\[ \frac{1}{2} m v_i^2 = mgh + f_d \]where \( h \) is the vertical height \( (h = d \sin \theta) \), and \( f_d \) is the work done by friction \( (f_d = \mu mgd \cos \theta) \).
03

Calculate the Vertical Height \( h \)

Using trigonometry, the vertical height \( h \) can be calculated as:\[ h = d \sin \theta = 15 \times \sin(19^\circ) \approx 4.89 \, \text{m} \]
04

Substitute Known Values and Solve for \( \mu \)

Substitute \( h \) and \( f_d \) into the work-energy equation:\[ \frac{1}{2} m (11)^2 = mg(4.89) + \mu \cdot m \cdot 9.8 \cdot 15 \cdot \cos(19^\circ) \]Cancel the mass \( m \) from all terms and compute the remaining values to solve for \( \mu \):\[ 60.5 = 9.8 \times 4.89 + \mu \times 9.8 \times 15 \times \cos(19^\circ) \]\[ 60.5 = 47.922 + \mu \times 138.875 \]\[ \mu = \frac{60.5 - 47.922}{138.875} \approx 0.090 \]
05

Conclude the Calculation

Finally, state the result for the coefficient of friction. \( \mu \approx 0.090 \) is the average coefficient of friction needed for the skier to come to rest over the 15 m incline.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Friction
The coefficient of friction is a value that represents the force resisting the sliding motion between two surfaces. In this problem, it's vital because it helps us measure how much the skier is slowed down by friction as they glide uphill. This coefficient, denoted by \( \mu \), depends on the nature of the surfaces in contact—in this case, the snow and the skis.
The coefficient value varies, with lower values indicating smoother surfaces and higher values showing rougher surfaces. This exercise calculates the average coefficient of friction to be approximately 0.090. This means that for every unit of normal force, there's about 9% of that force working opposite to the skier's motion due to friction.
Understanding the coefficient of friction is critical in physics, especially in problems involving motion across different surfaces. It helps in predicting how quickly a moving object will slow down due to the opposing force of friction.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. For the skier at the bottom of the hill, kinetic energy is given as \( \frac{1}{2} mv_i^2 \), where \( m \) is the mass of the skier, and \( v_i \) is the velocity, which in this case is 11.0 m/s.
This concept is central in calculating how far the skier will travel up the inclined plane. As the skier moves, kinetic energy is gradually converted into work done against gravity and friction. This is why the skier eventually comes to a stop.
In problems like these, knowing how to calculate and apply kinetic energy helps us understand and predict the movement and stopping distance of objects based on their speed and the resistance they encounter.
Inclined Plane
An inclined plane is a flat surface tilted at an angle, like a ramp. In this problem, it has an angle of 19° relative to the horizontal. The angle and length of the incline affect how forces like gravity and friction act on an object traveling along it.
For the skier, the incline's role is crucial because the component of gravitational force acting down the slope influences how quickly the skier comes to rest. This component can be broken down into forces parallel and perpendicular to the incline.
This playing field for physics problems helps demonstrate how different forces interact, guiding us through the complexities of motion along a slope. Knowing these concepts helps provide comprehensive solutions to challenges involving incline.
Work-Energy Principle
The work-energy principle indicates that the work done on an object is equal to the change in its kinetic energy. This principle is the foundation for determining how far the skier will glide uphill before stopping.
Initially, the skier has kinetic energy at the bottom of the incline. As they move uphill, this energy converts to work done against gravity and friction. The vertical component of this work is the energy needed to raise the skier to a height \( h \), and the horizontal component deals with frictional forces.
Understanding this principle allows us to utilize the equation \( \frac{1}{2} mv^2 = mgh + f_d \) effectively, balancing energy lost through work done by friction and energy gained in height. This relationship is powerful for solving many physics problems, providing clear guidance on energy transformations.

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Most popular questions from this chapter

(II) What is the minimum work needed to push a 950-kg car 710 m up along a 9.0\(^\circ\) incline? Ignore friction.

(III) A block of mass m is attached to the end of a spring (spring stiffness constant k), Fig. 6-43. The mass is given an initial displacement \(x_0\) from equilibrium, and an initial speed \(v_0\) .Ignoring friction and the mass of the spring, use energy methods to find (\(a\)) its maximum speed, and (\(b\)) its maximum stretch from equilibrium, in terms of the given quantities.

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(II) A 145-g baseball is dropped from a tree 12.0 m above the ground. (\(a\)) With what speed would it hit the ground if air resistance could be ignored? (\(b\)) If it actually hits the ground with a speed of 8.00 m/s, what is the average force of air resistance exerted on it?

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