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I) How much tension must a rope withstand if it is used to accelerate a 1210-kg car horizontally along a frictionless surface at 1.20 m/s\(^2\) ?

Short Answer

Expert verified
The tension in the rope must be 1452 N.

Step by step solution

01

Understand the Problem

We need to find the tension in the rope, which acts as the force required to accelerate a car with a given mass and acceleration.
02

Recall Newton's Second Law

Newton's second law of motion states that the force required to accelerate an object is the product of the object's mass and its acceleration. This is expressed in the equation:\[ F = m \cdot a \]where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
03

Identify Given Values

From the problem, we know that the mass \( m \) of the car is 1210 kg, and the acceleration \( a \) is 1.20 m/s\(^2\).
04

Substitute Values into the Equation

Substitute the given mass and acceleration values into the equation:\[ F = 1210 \times 1.20 \]
05

Calculate the Force

Perform the multiplication to find the force:\[ F = 1452 \text{ N} \]This force is the tension that the rope must withstand.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Acceleration
When it comes to understanding Newton's Second Law, the concept of mass and acceleration is pivotal. Mass is a measure of how much matter is in an object, often understood as the object's resistance to being moved. It's expressed in kilograms (kg) and directly impacts how an object accelerates under any given force.
Acceleration, on the other hand, is a change in the velocity of an object over time. It's measured in meters per second squared (m/s²). The relationship between mass and acceleration is influenced by how much force is applied to the object.
According to Newton's Second Law of Motion, the force applied to an object causes it to accelerate. This relationship is expressed mathematically as:
  • The force acting on an object is equal to the mass of the object multiplied by the acceleration (\( F = m \cdot a \).)
Thus, understanding how mass and acceleration interact aids in calculating the forces in various physics problems, such as the tension in a rope in our given problem scenario.
Tension in Physics
Tension is a type of force exerted by a rope, string, or another object that is being stretched. In physics, tension is important for understanding how forces are transmitted through a medium. It's particularly noticeable when you pull one end of a rope, and that force travels along its length. In our problem, the tension in the rope is synonymous with the force needed to accelerate the car. Tension acts similarly to a pulling force that compels an object to move in the direction of the applied force. On a frictionless surface, the tension is the sole force causing horizontal movement, simplifying calculations:
  • Tension must be equal to or greater than the force being applied to achieve the desired acceleration.
  • If the rope cannot withstand the calculated tension, it might break, failing to move the car.
This means understanding tension is crucial for solving problems where forces are a factor in horizontal or even vertical movements.
Force Calculation
Force calculation underpins many principles in physics. It's essential to compute how much force an object experiences due to other forces acting upon it, like tension. To understand force calculation, it's useful to reiterate Newton's Second Law:The force required to move an object is the product of its mass and the acceleration it undergoes.
  • Using this idea, we can calculate the force necessary to move an object in any direction.
  • For example, in a horizontal force scenario such as a car on a frictionless surface, force requirements are easier to compute as friction doesn't complicate the movement.
In the exercise provided, we calculate the tension by multiplying the car's mass (1210 kg) by its acceleration (1.20 m/s²). This gives us the precise force needing to be exerted by the rope to move the car, resulting in:\[ F = 1210 \times 1.20 = 1452 \text{ N} \]By mastering force calculations, you can tackle complex physics problems, simplifying them to basic multiplication where the roles of mass and acceleration are clear.

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Most popular questions from this chapter

A 75-kg snowboarder has an initial velocity of 5.0 m/s at the top of a 28\(^\circ\) incline (Fig. 4-75). After sliding down the 110-m-long incline (on which the coefficient of kinetic friction is \(\mu_k=\) 0.18 ), the snowboarder has attained a velocity \(v\). The snowboarder then slides along a flat surface (on which \(\mu_k=\) 0.15 ) and comes to rest after a distance \(x\). Use Newton's second law to find the snowboarder's acceleration while on the incline and while on the flat surface. Then use these accelerations to determine \(x\).

(II) A 2.0-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force, and when the applied force reaches 9.0 N, the drawer suddenly opens, throwing all the utensils to the floor. What is the coefficient of static friction between the drawer and the cabinet?

(II) How much tension must a cable withstand if it is used to accelerate a 1200-kg car vertically upward at 0.70 m/s\(^2\)?

(II) The cable supporting a 2125-kg elevator has a maximum strength of 21,750 N. What maximum upward acceleration can it give the elevator without breaking?

In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to push grocery carts up the ramps and it is desirable that this not be too difficult. The engineer has done a survey and found that almost no one complains if the force required is no more than 18 N. Ignoring friction, at what maximum angle \(\theta\) should the ramps be built, assuming a full 25-kg cart?

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