Chapter 31: Problem 54
Consider a system of nuclear power plants that produce 2100MW. (\(a\)) What total mass of \(^{235}_{92}\)U fuel would be required to operate these plants for 1 yr, assuming that 200 MeV is released per fission? (\(b\)) Typically 6% of the \(^{235}_{92}\)U nuclei that fission produce strontium \(-\)90, \(^{90}_{38}\)Sr, a \(\beta^-\) emitter with a half-life of 29 yr. What is the total radioactivity of the \(^{90}_{38}\)Sr, in curies, produced in 1 yr? (Neglect the fact that some of it decays during the 1-yr period.)
Short Answer
Step by step solution
Convert Power to Energy
Convert Energy Per Fission Event
Calculate Number of Fissions Required
Calculate Mass of Uranium Required
Calculate Amount of Strontium-90 Produced
Convert to Curies
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nuclear Power Plants
- Nuclear power plants are designed to manage the nuclear fission process safely and efficiently.
- They produce electricity without emitting greenhouse gases, unlike fossil fuel plants.
- Water plays a crucial role in nuclear power plants as both a coolant and in generating steam to drive turbines.
Uranium-235
- During fission, uranium-235 absorbs a neutron and becomes an unstable isotope, leading to its split into smaller elements and the release of a substantial amount of energy (around 200 MeV per fission event).
- Uranium-235 has a fission probability that makes it especially useful in both nuclear power plants and nuclear weapons.
- This isotope has a relatively long half-life of about 703.8 million years, which contributes to its suitability as a fuel in nuclear reactors.
Strontium-90 Decay
- Strontium-90 has a half-life of 29 years, meaning it remains radioactive and poses potential health risks for an extended period.
- Once released into the environment, Strontium-90 can be absorbed into bones, as it mimics calcium.
- This can lead to increased risks of bone cancer and leukemia.
Radioactivity Measurement
- The decay constant (\(\lambda\)) is a vital parameter representing the probability of decay per unit time for a radioactive isotope.
- Activity (\(A\)) quantifies the number of decays per second, often expressed in becquerels or curies (1 curie equals \(3.7 \times 10^{10}\) decays per second).
- The decay constant, determined using the half-life formula: \(\lambda = \frac{\ln(2)}{T_{1/2}}\).
- The number of strontium-90 particles produced during fission.