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(II) A passenger on a boat moving at 1.70 m/s on a still lake walks up a flight of stairs at a speed of 0.60 m/s, Fig. 3-43. The stairs are angled at 45\(^\circ\) pointing in the direction of motion as shown. What is the velocity of the passenger relative to the water?

Short Answer

Expert verified
The velocity of the passenger relative to the water is approximately 2.168 m/s at an angle of 11.3°.

Step by step solution

01

Understand the Problem

The problem requires us to find the velocity of a passenger relative to the water. The passenger walks on stairs angled at 45° while the boat is moving on still water, so we must consider both the boat's and the passenger's movements.
02

Break Down the Velocities

The velocity of the boat relative to the water is 1.70 m/s. The passenger walks up the stairs at 0.60 m/s, but since the stairs are at a 45° angle, we need to consider both horizontal and vertical components of this velocity.
03

Calculate the Horizontal Component of the Passenger's Velocity

The horizontal component of the velocity can be calculated using \( \cos(45^\circ) \). Therefore, \( v_{p,horizontal} = 0.60 \times \cos(45^\circ) = 0.60 \times \frac{1}{\sqrt{2}} \approx 0.424 \text{ m/s} \).
04

Calculate the Vertical Component of the Passenger's Velocity

The vertical component is determined using \( \sin(45^\circ) \). Thus, \( v_{p,vertical} = 0.60 \times \sin(45^\circ) = 0.60 \times \frac{1}{\sqrt{2}} \approx 0.424 \text{ m/s} \).
05

Find the Resultant Horizontal Velocity

Add the horizontal component of the passenger's velocity to the velocity of the boat, giving \( v_{horizontal} = 1.70 + 0.424 = 2.124 \text{ m/s} \).
06

Combine the Components to Find the Total Velocity

The velocity relative to the water is a combination of the horizontal and vertical components. Use the Pythagorean theorem to find the magnitude: \( v = \sqrt{(2.124)^2 + (0.424)^2} \approx 2.168 \text{ m/s} \).
07

Determine the Direction of the Velocity

Calculate the angle of movement starting from the horizontal axis using \( \tan^{-1}\left( \frac{v_{p,vertical}}{v_{horizontal}} \right) = \tan^{-1}\left( \frac{0.424}{2.124} \right) \approx 11.3^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
When discussing physics and motion, especially in two dimensions, vector components are essential. A vector component breaks down a vector into two or more parts that show the influence in different directions. In our case, the velocity of the passenger walking up the stairs is a vector that needs to be assessed in both horizontal and vertical directions.

Vectors are often split into these components to simplify calculations. For a passenger moving at an angle, like 45 degrees on the stairs, we use trigonometric functions to determine these components. Specifically, we use:
  • Horizontal Component: This is calculated using the cosine function, since the cosine of the angle gives the adjacent side over hypotenuse in a right triangle.
  • Vertical Component: Calculated using the sine function, as sine provides the opposite side over hypotenuse.
In this context, understanding vector components helps us see how a velocity at an angle can similarly affect horizontal and vertical movement, which is crucial for determining the resultant velocity of the passenger.
Velocity Addition
When determining the velocity of the passenger relative to still water, velocity addition becomes vital. This concept involves combining velocities in different directions to find their net or resultant velocity. Velocity addition is simply finding the combined effect of two or more velocity vectors.

In this exercise, the boat's velocity and the passenger's horizontal velocity need to be compounded. Only the horizontal aspect of the passenger's walk contributes to this addition because both movements are in the same direction. The passenger already has a forward motion due to the boat, which further increases with his walk's horizontal component.

By understanding velocity addition, you'll know that:
  • If two velocities align, they sum up for a greater overall speed in that direction.
  • If they point in opposite directions, they partially cancel each other, resulting in a smaller net velocity.
Thus, mastering velocity addition aids you in finding the correct relative velocity in different motion scenarios.
Trigonometry in Physics
Trigonometry is indispensable in physics, especially when vectors involve angles. It allows us to resolve complex vectors into simpler components. For the walking scenario here, trigonometry helps break down the directional walk into horizontal and vertical velocity with precision.

When using trigonometry, we often rely on:
  • The sine function for angles to find vertical components.
  • The cosine function for determining horizontal components.
Both of these rely on understanding right-angled triangles. Since the stair angle in this exercise is 45 degrees, the sine and cosine values are equal, simplifying the split of velocity into components.

A solid grasp of trigonometry equips you to handle situations where motion isn’t straightforwardly horizontal or vertical, analyzing the influences in every dimension involved.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental tool when working with right-angle triangles and spatial distances in physics. It helps calculate the actual magnitude of a resultant vector when you know its orthogonal components.

For example, in this problem, after figuring out both horizontal and vertical components of the velocity, the Pythagorean theorem is used to determine the total velocity vector's magnitude. It states that:
  • If you have a right triangle, the square of the hypotenuse's length (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
  • Mathematically, it's expressed as: \( c = \sqrt{a^2 + b^2} \)
Applying the Pythagorean theorem ensures an accurate resultant velocity, giving you not just a safety net in calculations but also conveying understanding of physical movements in spatial contexts.

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Most popular questions from this chapter

(II) Vector \(\overrightarrow {V_1}\) is 6.6 units long and points along the negative \(x\) axis. Vector \(\overrightarrow {V_2}\) is 8.5 units long and points at \(+\)55\(^\circ\) to the positive \(x\) axis. (\(a\)) What are the \(x\) and \(y\) components of each vector? (\(b\)) Determine the sum \(\overrightarrow {V_1} + \overrightarrow {V_1}\) (magnitude and angle).

(I) If \(V_x =\) 9.80 units and \(V_y = -\)6.40 units, determine the magnitude and direction of \(\overrightarrow {V}\).

(I) A person going for a morning jog on the deck of a cruise ship is running toward the bow (front) of the ship at 2.0 m/s while the ship is moving ahead at 8.5 m/s. What is the velocity of the jogger relative to the water? Later, the jogger is moving toward the stern (rear) of the ship. What is the jogger's velocity relative to the water now?

(II) Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/s and enjoys a free fall until she is 150 m above the valley floor, at which time she opens her parachute (Fig. 3-37). (\(a\)) How long is the jumper in free fall? Ignore air resistance. (\(b\)) It is important to be as far away from the cliff as possible before opening the parachute. How far from the cliff is this jumper when she opens her chute?

(I) A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. How high was the cliff and how far from its base did the diver hit the water?

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