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(II) The summit of a mountain, 2450 m above base camp, is measured on a map to be 4580 m horizontally from the camp in a direction 38.4\(^\circ\) west of north.What are the components of the displacement vector from camp to summit? What is its magnitude? Choose the \(x\) axis east, \(y\) axis north, and \(z\) axis up.

Short Answer

Expert verified
Displacement vector components: \(x = -2850\) m, \(y = 3590\) m, \(z = 2450\) m. Magnitude: 5990 m.

Step by step solution

01

Identify the Components of the Displacement Vector

The displacement vector can be described in terms of its components along the x, y, and z axes. The z-component is given by the vertical elevation, which is 2450 m. The horizontal displacement given is 4580 m at an angle of 38.4° west of north. To find the x and y components, we need to use trigonometry, considering the direction angles.
02

Calculate the y-component of the Displacement Vector

Since the horizontal angle is given as 38.4° west of north, you can use the cosine function to find the y-component (northward component) of the horizontal displacement. This is given by \( 4580 \cos(38.4°) \). Compute this value to find the y-component.
03

Calculate the x-component of the Displacement Vector

Use the sine function to find the x-component (westward or negative eastward component). Since west is the negative x-direction, this component is \( -4580 \sin(38.4°) \). Compute this value to find the x-component.
04

Calculate the Magnitude of the Displacement Vector

The magnitude of the displacement vector can be found using the Pythagorean theorem in three dimensions. The formula is:\[\sqrt{x^2 + y^2 + z^2}\]Substitute the values of the components into this formula to find the magnitude.
05

Final Computation and Combination of Results

Compute the x and y values from Steps 2 and 3. Combine these with the z value (2450 m) to calculate the magnitude. Present all computed components: x, y, z, and the magnitude of the displacement vector.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
A displacement vector represents the change in position of an object and is typically described in terms of its components along specific axes. For a three-dimensional vector, like the one from a base camp to a mountain summit, these components are denoted as \( x \), \( y \), and \( z \). Each component reflects a portion of the total displacement along the respective axis:
  • The \( x \)-component corresponds to the east-west direction. If directed west, it's expressed as a negative value.
  • The \( y \)-component aligns with the north-south direction. Northward is positive.
  • The \( z \)-component accounts for vertical displacement, often upward, and hence is positive.
By breaking down a displacement vector into these individual components, its direction and magnitude can be more easily analyzed and calculated. This foundation is essential when trying to compute how far and in what direction the summit is relative to the camp.
Trigonometry
Trigonometry plays a crucial role in determining the horizontal components of a displacement vector. Given an angle describing the direction, trigonometric functions like sine and cosine are vital in translating this into usable vector components. Here's how it applies to our problem:
  • To find the \( y \)-component (northward), the cosine function is used because it corresponds to the adjacent side of the angle: \( 4580 \cos(38.4°) \).
  • The \( x \)-component (westward) uses the sine function as it represents the opposite side of the angle: \(-4580 \sin(38.4°) \).
These calculations depend heavily on understanding the right-angle triangle concept, where the horizontal displacement acts as the hypotenuse, and the components are sides of the triangle described. Knowing how to apply these functions allows accurate determination of each axis's vector component.
Magnitude Calculation
Once the components \( x \), \( y \), and \( z \) of a displacement vector have been identified, calculating the vector's overall magnitude becomes the next step. This measure represents the total size of the displacement, irrespective of direction, and can be visualized as the vector's length:
The formula for the magnitude of a vector in three-dimensional space builds on the Pythagorean theorem:\[\sqrt{x^2 + y^2 + z^2}\]This equation determines the magnitude by combining each squared component, summing them up, and taking the square root. Applying this method gives a scalar value, which depicts the actual spatial distance from the base to the summit."
Understanding how to derive a vector’s magnitude is essential in assessing not just direction but also the scale of movement in any given dimension.
Three-Dimensional Vectors
Three-dimensional vectors are a fundamental concept in physics and mathematics, representing quantities with both magnitude and direction in a 3D space. They are particularly useful for visualizing and solving problems involving spatial relations, such as the position change from a base camp to a mountain summit.
For instance, in terms of coordinates:
  • The Latitude-Longitude system can represent directions parallel to the Earth’s surface.
  • Elevation provides the vertical, third dimension encompassing height.
Each component \( x \), \( y \), and \( z \) interacts with one another to form a comprehensive picture of an object's location.This complexity requires both arithmetic and geometric comprehension to fully understand, emphasizing why assimilating three-dimensional vectors is pivotal in fields concerning real-world spatial interactions and navigation.

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Most popular questions from this chapter

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