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Green and blue LEDs became available many years after red LEDs were first developed. Approximately what energy gaps would you expect to find in green (525 nm) and in blue (465 nm) LEDs?

Short Answer

Expert verified
Green LED: 2.35 eV, Blue LED: 2.67 eV.

Step by step solution

01

Understand the Problem

We are asked to find the energy gaps for green and blue LEDs based on their wavelength. In semiconductor physics, the energy gap can be calculated from the photon's wavelength.
02

Use the Energy-Wavelength Relation

The energy (E) of a photon can be calculated using the formula \(E = \frac{hc}{\lambda}\), where \(h\) is Planck's constant \(6.626 \times 10^{-34} \, \text{Js}\), \(c\) is the speed of light \(3 \times 10^8 \, \text{m/s}\), and \(\lambda\) is the wavelength in meters.
03

Calculate the Energy Gap for Green LED

Convert the wavelength of the green LED from nanometers to meters: \(525 \, \text{nm} = 525 \times 10^{-9} \, \text{m}\). Then plug the values into the formula: \(E = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{525 \times 10^{-9}}\). Calculate the result, \(E \approx 3.769 \times 10^{-19} \, \text{J}\). Convert this energy to electronvolts (1 eV = 1.602 \times 10^{-19} \, J): \(E \approx \frac{3.769 \times 10^{-19}}{1.602 \times 10^{-19}} \approx 2.35 \, \text{eV}\).
04

Calculate the Energy Gap for Blue LED

Convert the wavelength of the blue LED from nanometers to meters: \(465 \, \text{nm} = 465 \times 10^{-9} \, \text{m}\). Then plug the values into the formula: \(E = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{465 \times 10^{-9}}\). Calculate the result, \(E \approx 4.28 \times 10^{-19} \, \text{J}\). Convert this energy to electronvolts: \(E \approx \frac{4.28 \times 10^{-19}}{1.602 \times 10^{-19}} \approx 2.67 \, \text{eV}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

LED wavelength
Light Emitting Diodes (LEDs) are widely used in modern technology. They come in different colors, which are determined by their wavelength. Each color corresponds to a specific range of wavelengths, measured in nanometers (nm). For instance, a green LED typically has a wavelength around 525 nm, whereas a blue LED has a wavelength around 465 nm.

Wavelength is essential because it directly relates to the energy of the light emitted. Shorter wavelengths, like blue, have more energy compared to longer wavelengths, like red or green. This is why blue LEDs have a higher energy gap compared to green LEDs.

Understanding LED wavelength is crucial not only for choosing the correct LED for your application but also for understanding how different materials in the semiconductor can affect the color of the light emitted.
semiconductor physics
Semiconductor physics is the backbone of how LEDs work. It deals with materials that have electrical conductivity between that of a conductor and an insulator. These materials are used to build the p-n junctions that are essential in LEDs.
  • The p-n junction consists of two types of semiconductor materials, one positive (p-type) and one negative (n-type).
  • When an electric current is applied, electrons and holes recombine at the junction.
  • This recombination releases energy in the form of light, which is what we see when an LED is lit.

The color of this light is determined by the material's energy gap. Different materials have different energy gaps, which in turn emit light of different colors when excited. As technology advanced, scientists were able to manipulate these materials to produce LEDs in a wide range of colors beyond the initially available red.
photon energy calculation
Photon energy calculation is a key concept in understanding how LEDs work. The energy of a photon, which is the basic unit of light, can be calculated using the formula: \[ E = \frac{hc}{\lambda} \]where:
  • \(E\) is the energy in joules (J),
  • \(h\) is Planck's constant \(6.626 \times 10^{-34} \, \text{Js}\),
  • \(c\) is the speed of light \(3 \times 10^8 \, \text{m/s}\),
  • \(\lambda\) is the wavelength in meters.

This formula shows the inverse relationship between energy and wavelength: shorter wavelengths (like blue) have higher energy, while longer wavelengths (like red and green) have lower energy. When calculating photon energy for LEDs, you often need to convert the result from joules to electronvolts (eV) because they are typically used in the context of semiconductor energy gaps. This involves dividing the energy in joules by the charge of an electron \(1.602 \times 10^{-19} \, \text{C}\).

This conversion is important because it allows you to compare energy values more directly and understand the efficiency and performance of different semiconductors used in LEDs.

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Most popular questions from this chapter

(III) Suppose that a silicon semiconductor is doped with phosphorus so that one silicon atom in 1.5 \(\times\) 10\(^6\) is replaced by a phosphorus atom. Assuming that the "extra" electron in every phosphorus atom is donated to the conduction band, by what factor is the density of conduction electrons increased? The density of silicon is 2330 kg/m\(^3\), and the density of conduction electrons in pure silicon is about 10\(^{16}\) m\(^{-3}\) at room temperature.

(II) Common salt, NaCl, has a density of 2.165 g/cm\(^3\). The molecular weight of NaCl is 58.44. Estimate the distance between nearest neighbor Na and Cl ions. [\(Hint: Each\) ion can be considered to be at the corner of a cube.]

Must we consider quantum effects for everyday rotating objects? Estimate the differences between rotational energy levels for a spinning baton compared to the energy of the baton. Assume the baton consists of a uniform 32-cm-long bar with a mass of 230 g and two small end masses, each of mass 380 g, and it rotates at 1.8 rev/s about the bar's center.

(I) Show that the quantity \(\hslash^2/I\) has units of energy.

(II) The band gap of silicon is 1.12 eV. (a) For what range of wavelengths will silicon be transparent? (See Example 29-5.) In what region of the electromagnetic spectrum does this transparent range begin? (b) If window glass is transparent for all visible wavelengths, what is the minimum possible band gap value for glass (assume \(\lambda =\) 400nm to 700nm)? [\(Hint:\) If the photon has less energy than the band gap, the photon will pass through the solid without being absorbed.]

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